Dear Avneet
the function aggregate (see also ?aggregate) could be useful for
your problem. See the short example I've written below.
dat1 - data.frame(lot = factor(1:10),y1 = rnorm(10))
str(dat1)
dat2 - data.frame(nr = 1:100, lot = factor(rep(1:10, each = 10)),y2 =
rnorm(100))
str(dat2)
dat2.agr - aggregate(dat2$y, by = list(lot = dat2$lot), FUN = mean)
names(dat2.agr)[2] - y2
dat.mer - merge(dat1, dat2.agr)
str(dat.mer)
Be careful about merging dataframes. There should always be a
control that the right cases are merged together.
Regards,
Christoph Buser
--
Christoph Buser [EMAIL PROTECTED]
Seminar fuer Statistik, LEO C11
ETH (Federal Inst. Technology) 8092 Zurich SWITZERLAND
phone: x-41-1-632-5414 fax: 632-1228
http://stat.ethz.ch/~buser/
avneet singh writes:
Hello :)
I have two data frames, one has properties taken on a
piece by piece basis and the other has performance on
a lot by lot basis. I wish to combine these two data
frames but the problem is that each lot has multiple
pieces and hence i need to take a mean of the
properties of multiple pieces and match it to the row
having data about the lot.
I was wondering if there is a simple commmand, an
extension of merge, or an option of merge i do not
know which could easily do this work.
Thank you :)
=
I believe in equality for everyone, except reporters and photographers.
~Mahatma Gandhi
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
--
Christoph Buser [EMAIL PROTECTED]
Seminar fuer Statistik, LEO C11
ETH (Federal Inst. Technology) 8092 Zurich SWITZERLAND
phone: x-41-1-632-5414 fax: 632-1228
http://stat.ethz.ch/~buser/
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
