Re: [R] do.call([, ...) question
Hi Robin, you could try the following: lis - lapply(seq(1, length(dim(a))+1), function(x,a.,jj.) if(x==1) a. else jj.[[x-1]] ,a.=a, jj.=jj) do.call([,lis) I hope this helps. Best, Dimitris Dimitris Rizopoulos Ph.D. Student Biostatistical Centre School of Public Health Catholic University of Leuven Address: Kapucijnenvoer 35, Leuven, Belgium Tel: +32/16/396887 Fax: +32/16/337015 Web: http://www.med.kuleuven.ac.be/biostat/ http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm/ - Original Message - From: Robin Hankin [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, September 08, 2004 4:08 PM Subject: [R] do.call([, ...) question Hi again everyone I have an arbitrarily dimensional array a and a list jj of length length(dim(a)).The elements of jj are vectors of indexes. How do I use do.call() to extract a[ jj[[1]], jj[[2]], jj[[3]], ...] ? Toy example follows: a - matrix(1:30,5,6) jj - list(5:1,6:1) I want the following a[ jj[[1]],jj[[2]] ] How do I do this? OBAttempts: do.call([,list(a,jj)) do.call([,c(a,jj)) do.call([,list(a,unlist(jj))) Of course, the one that works is do.call([,list(a,jj[[1]],jj[[2]])) but I don't know how long jj is apriori so this won't do. -- Robin Hankin Uncertainty Analyst Southampton Oceanography Centre SO14 3ZH tel +44(0)23-8059-7743 [EMAIL PROTECTED] (edit in obvious way; spam precaution) __ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] do.call([, ...) question
Robin Hankin [EMAIL PROTECTED] writes: Hi again everyone I have an arbitrarily dimensional array a and a list jj of length length(dim(a)).The elements of jj are vectors of indexes. How do I use do.call() to extract a[ jj[[1]], jj[[2]], jj[[3]], ...] ? Toy example follows: a - matrix(1:30,5,6) jj - list(5:1,6:1) I want the following a[ jj[[1]],jj[[2]] ] How do I do this? OBAttempts: do.call([,list(a,jj)) do.call([,c(a,jj)) do.call([,list(a,unlist(jj))) Of course, the one that works is do.call([,list(a,jj[[1]],jj[[2]])) but I don't know how long jj is apriori so this won't do. do.call([,c(list(a),jj)) -- O__ Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907 __ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
RE: [R] do.call([, ...) question
This worked very well for me: do.call([, c(list(a), jj)) What about you? Kevin -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Robin Hankin Sent: Wednesday, September 08, 2004 7:08 AM To: [EMAIL PROTECTED] Subject: [R] do.call([, ...) question Hi again everyone I have an arbitrarily dimensional array a and a list jj of length length(dim(a)).The elements of jj are vectors of indexes. How do I use do.call() to extract a[ jj[[1]], jj[[2]], jj[[3]], ...] ? Toy example follows: a - matrix(1:30,5,6) jj - list(5:1,6:1) I want the following a[ jj[[1]],jj[[2]] ] How do I do this? OBAttempts: do.call([,list(a,jj)) do.call([,c(a,jj)) do.call([,list(a,unlist(jj))) Of course, the one that works is do.call([,list(a,jj[[1]],jj[[2]])) but I don't know how long jj is apriori so this won't do. -- Robin Hankin Uncertainty Analyst Southampton Oceanography Centre SO14 3ZH tel +44(0)23-8059-7743 [EMAIL PROTECTED] (edit in obvious way; spam precaution) __ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
