Re: [R] Selective subsetting

2006-11-10 Thread Benilton Carvalho
A=matrix(1:9,3)
A[lower.tri(A)]

b

On Nov 10, 2006, at 4:50 PM, Davendra Sohal wrote:

 Hi all,
 Here's an interesting (for me, at least!) problem I came across:
 I have a correlation matrix, let's say with 6 variables, A to F, as  
 column
 headings and the same 6 as row headings.
 The matrix is filled with correlation coefficients. Therefore, the  
 diagonal
 is all 1's, and each of the two triangles formed by the diagonal  
 has the
 same 15 correlation coefficients.
 I need to extract these 15 coefficients from this. I don't want the  
 1's and
 I don't want redundant values.
 I tried converting the matrix to a list, using c(m) and then I'm  
 stuck.
 Does something like b = a[x, x+1:n] exist in R? SAS will do it.
 x can be looped to go from 1 to n (n here is 6, of course) and it will
 select the required values, but I cannot make it work.
 Please help.
 Many thanks,
 -DS.

   [[alternative HTML version deleted]]

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Re: [R] Selective subsetting

2006-11-10 Thread Dimitrios Rizopoulos
try this:

cor.mat - cor(iris[1:4])
cor.mat[lower.tri(cor.mat)]


I hope it helps.

Best,
Dimitris


Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
  http://www.student.kuleuven.be/~m0390867/dimitris.htm


Quoting Davendra Sohal [EMAIL PROTECTED]:

 Hi all,
 Here's an interesting (for me, at least!) problem I came across:
 I have a correlation matrix, let's say with 6 variables, A to F, as column
 headings and the same 6 as row headings.
 The matrix is filled with correlation coefficients. Therefore, the diagonal
 is all 1's, and each of the two triangles formed by the diagonal has the
 same 15 correlation coefficients.
 I need to extract these 15 coefficients from this. I don't want the 1's and
 I don't want redundant values.
 I tried converting the matrix to a list, using c(m) and then I'm stuck.
 Does something like b = a[x, x+1:n] exist in R? SAS will do it.
 x can be looped to go from 1 to n (n here is 6, of course) and it will
 select the required values, but I cannot make it work.
 Please help.
 Many thanks,
 -DS.

   [[alternative HTML version deleted]]

 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.





Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm

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Re: [R] Selective subsetting

2006-11-10 Thread Francisco Zagmutt
Look at the functions tril() and triu() in the Matrix package

Regards

Francisco


Davendra Sohal wrote:
 Hi all,
 Here's an interesting (for me, at least!) problem I came across:
 I have a correlation matrix, let's say with 6 variables, A to F, as column
 headings and the same 6 as row headings.
 The matrix is filled with correlation coefficients. Therefore, the diagonal
 is all 1's, and each of the two triangles formed by the diagonal has the
 same 15 correlation coefficients.
 I need to extract these 15 coefficients from this. I don't want the 1's and
 I don't want redundant values.
 I tried converting the matrix to a list, using c(m) and then I'm stuck.
 Does something like b = a[x, x+1:n] exist in R? SAS will do it.
 x can be looped to go from 1 to n (n here is 6, of course) and it will
 select the required values, but I cannot make it work.
 Please help.
 Many thanks,
 -DS.
 
   [[alternative HTML version deleted]]
 
 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 

-- 
Dr. Francisco J. Zagmutt
College of Veterinary Medicine and Biomedical Sciences
Colorado State University

__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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