Re: [R] how to print a data.frame without row.names

2005-08-02 Thread Romain Francois 
Le 02.08.2005 15:45, Heinz Tuechler a écrit :

Dear All,
is there a simple way to print a data.frame without its row.names?

example:
datum - as.Date(c(2004-01-01, 2004-01-06, 2004-04-12))
content - c('Neujahr', 'Hl 3 K.', 'Ostern')
df1 - data.frame(datum, content)
print(df1)

   datum content
1 2004-01-01 Neujahr
2 2004-01-06 Hl 3 K.
3 2004-04-12  Ostern

Can I get this table without 1, 2, 3 ?
  

See write.table and its row.names argument

R write.table(df1, row.names=FALSE)

Romain

-- 
visit the R Graph Gallery : http://addictedtor.free.fr/graphiques
 ~ 
~~  Romain FRANCOIS - http://addictedtor.free.fr ~~
Etudiant  ISUP - CS3 - Industrie et Services   
~~http://www.isup.cicrp.jussieu.fr/  ~~
   Stagiaire INRIA Futurs - Equipe SELECT  
~~   http://www.inria.fr/recherche/equipes/select.fr.html~~
 ~ 

__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html

Re: [R] how to print a data.frame without row.names

2005-08-02 Thread Heinz Tuechler 
At 16:05 02.08.2005 +0200, Romain Francois wrote:
Le 02.08.2005 15:45, Heinz Tuechler a écrit :

Dear All,
is there a simple way to print a data.frame without its row.names?

example:
datum - as.Date(c(2004-01-01, 2004-01-06, 2004-04-12))
content - c('Neujahr', 'Hl 3 K.', 'Ostern')
df1 - data.frame(datum, content)
print(df1)

   datum content
1 2004-01-01 Neujahr
2 2004-01-06 Hl 3 K.
3 2004-04-12  Ostern

Can I get this table without 1, 2, 3 ?
  

See write.table and its row.names argument

R write.table(df1, row.names=FALSE)

Romain


write.table(df1, row.names=FALSE, quote=FALSE)
datum content
2004-01-01 Neujahr
2004-01-06 Hl 3 K.
2004-04-12 Ostern

I tried this, but then the column headers and column contents are not aligned.

If you expand the example, you see clearly the difference.

datum - as.Date(c(2004-01-01, 2004-01-06, 2004-04-12))
content - c('Neujahr', 'Hl 3 K.', 'Ostern')
number - c(1, 6, 110)
string - c('a', '', 'c')
df1 - data.frame(datum, content, number, string)
print(df1)
   datum content number string
1 2004-01-01 Neujahr  1  a
2 2004-01-06 Hl 3 K.  6   
3 2004-04-12  Ostern110  c

write.table(df1, row.names=FALSE, quote=FALSE)
datum content number string
2004-01-01 Neujahr 1 a
2004-01-06 Hl 3 K. 6 
2004-04-12 Ostern 110 c

Maybe I missed a function like print.xtable with type=ascii. It seems
that it has to be done with cat.

Thank you

Heinz

-- 
visit the R Graph Gallery : http://addictedtor.free.fr/graphiques
 ~ 
~~  Romain FRANCOIS - http://addictedtor.free.fr ~~
Etudiant  ISUP - CS3 - Industrie et Services   
~~http://www.isup.cicrp.jussieu.fr/  ~~
   Stagiaire INRIA Futurs - Equipe SELECT  
~~   http://www.inria.fr/recherche/equipes/select.fr.html~~
 ~ 



__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html

Re: [R] how to print a data.frame without row.names

2005-08-02 Thread Martin Maechler 

 Heinz == Heinz Tuechler [EMAIL PROTECTED]
 on Tue, 02 Aug 2005 17:46:07 +0200 writes:

  ...

Heinz I tried this, but then the column headers and column
Heinz contents are not aligned.

  

Use the tabulator if you need them aligned :

write.table(USArrests, row.names = FALSE, sep = \t)

__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html

Re: [R] how to print a data.frame without row.names

2005-08-02 Thread Peter Dalgaard 
Martin Maechler [EMAIL PROTECTED] writes:

  Heinz == Heinz Tuechler [EMAIL PROTECTED]
  on Tue, 02 Aug 2005 17:46:07 +0200 writes:
 
   ...
 
 Heinz I tried this, but then the column headers and column
 Heinz contents are not aligned.
 
   
 
 Use the tabulator if you need them aligned :
 
 write.table(USArrests, row.names = FALSE, sep = \t)

Unless a column or a header is 8 chars or wider (and UrbanPop is!).

This seems to do it:

  x - as.matrix(format(USArrests))
  rownames(x) - rep(, nrow(x))
  print(x, quote=FALSE, right=TRUE)

-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html

Re: [R] how to print a data.frame without row.names

2005-08-02 Thread Heinz Tuechler 
Thanks to all of you for your help.

As far as I see, the solution of Peter Dalgaard works exactly as I want.
All other solutions have limitations.

Heinz

At 19:19 02.08.2005 +0200, Peter Dalgaard wrote:
Martin Maechler [EMAIL PROTECTED] writes:

  Heinz == Heinz Tuechler [EMAIL PROTECTED]
  on Tue, 02 Aug 2005 17:46:07 +0200 writes:
 
   ...
 
 Heinz I tried this, but then the column headers and column
 Heinz contents are not aligned.
 
   
 
 Use the tabulator if you need them aligned :
 
 write.table(USArrests, row.names = FALSE, sep = \t)

Unless a column or a header is 8 chars or wider (and UrbanPop is!).

This seems to do it:

  x - as.matrix(format(USArrests))
  rownames(x) - rep(, nrow(x))
  print(x, quote=FALSE, right=TRUE)

-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907



__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html