Re: [sage-support] using a base other then base 10.
When dealing with base 36 I realized there is no letter available to use in for loops. Here is the code that I have right now. a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,t,u,v,w,x,y,z = var('a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,t,u,v,w,x,y,z') pie = pi.n(1000) pie36 = list(pie.str(base=36)) pie36.remove('.') a = 10; b = 11; c = 12; d = 13; e = 14; f = 15; g = 16; h = 17; i = 18; j = 19; k = 20; l = 21; m = 22; n = 23; o = 24; p = 25; q = 26; r = 27; s = 28; t = 29; u = 30; v = 31; w = 32; x = 33; y = 34; z = 35; pie36 = [int(ii) for ii in pie36] I tried using ii for the increment count for the for loop, but here is what I get as the error. --- ValueError Traceback (most recent call last) /home/nooniensoong97/ipython console in module() ValueError: invalid literal for int() with base 10: 'i' I guess you can not use more then a letter to count the increments in the loop? Is there anyway to get around this issue? -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
Re: [sage-support] using a base other then base 10.
On Monday, May 21, 2012 9:49:08 AM UTC-7, Eric Kangas wrote: When dealing with base 36 I realized there is no letter available to use in for loops. Here is the code that I have right now. a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,t,u,v,w,x,y,z = var('a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,t,u,v,w,x,y,z') pie = pi.n(1000) pie36 = list(pie.str(base=36)) pie36.remove('.') a = 10; b = 11; c = 12; d = 13; e = 14; f = 15; g = 16; h = 17; i = 18; j = 19; k = 20; l = 21; m = 22; n = 23; o = 24; p = 25; q = 26; r = 27; s = 28; t = 29; u = 30; v = 31; w = 32; x = 33; y = 34; z = 35; pie36 = [int(ii) for ii in pie36] I tried using ii for the increment count for the for loop, but here is what I get as the error. --- ValueError Traceback (most recent call last) /home/nooniensoong97/ipython console in module() ValueError: invalid literal for int() with base 10: 'i' I guess you can not use more then a letter to count the increments in the loop? Is there anyway to get around this issue? How about: sage: D = dict([(Integer(j).str(base=36),j) for j in range(36)]) (This creates a dictionary with entries like '3':3 and 'a':10, associating a base 36 representation as a string to the corresponding integer.) Then sage: pie = pi.n(1000) sage: pie36 = list(pie.str(base=36)) sage: pie36.remove('.') sage: [D[ii] for ii in pie36] ought to do what you want. -- John -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
Re: [sage-support] using a base other then base 10.
thanks wasn't even thinking about a dictionary. On Monday, May 21, 2012 10:05:26 AM UTC-7, John H Palmieri wrote: On Monday, May 21, 2012 9:49:08 AM UTC-7, Eric Kangas wrote: When dealing with base 36 I realized there is no letter available to use in for loops. Here is the code that I have right now. a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,t,u,v,w,x,y,z = var('a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,t,u,v,w,x,y,z') pie = pi.n(1000) pie36 = list(pie.str(base=36)) pie36.remove('.') a = 10; b = 11; c = 12; d = 13; e = 14; f = 15; g = 16; h = 17; i = 18; j = 19; k = 20; l = 21; m = 22; n = 23; o = 24; p = 25; q = 26; r = 27; s = 28; t = 29; u = 30; v = 31; w = 32; x = 33; y = 34; z = 35; pie36 = [int(ii) for ii in pie36] I tried using ii for the increment count for the for loop, but here is what I get as the error. --- ValueError Traceback (most recent call last) /home/nooniensoong97/ipython console in module() ValueError: invalid literal for int() with base 10: 'i' I guess you can not use more then a letter to count the increments in the loop? Is there anyway to get around this issue? How about: sage: D = dict([(Integer(j).str(base=36),j) for j in range(36)]) (This creates a dictionary with entries like '3':3 and 'a':10, associating a base 36 representation as a string to the corresponding integer.) Then sage: pie = pi.n(1000) sage: pie36 = list(pie.str(base=36)) sage: pie36.remove('.') sage: [D[ii] for ii in pie36] ought to do what you want. -- John -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
Re: [sage-support] using a base other then base 10.
The following: sage: z = pi.n(100) sage: z.str(base=4) '3.0210033310202011220300203103010301212022023200' should get you started. Doug -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org