Re: About BindException bug

1999-10-12 Thread Vijaya Mahalakshmi

Yong,
The bug is nothing but if try to use the same port again it  gives
exception.
i think you follow this..
 --
 From: Yong Hu[SMTP:[EMAIL PROTECTED]]
 Reply To: A mailing list for discussion about Sun Microsystem's Java
 Servlet API Technology.
 Sent: Tuesday, October 12, 1999 6:52 AM
 To:   [EMAIL PROTECTED]
 Subject:  Re: About BindException little change

 vijaya,
   Thanks for your help.I has tried your code and it works well.But
 there is a bug in the code.The code "ServerSocket rSocket = new
 ServerSocket(SERVLET_PORT)" will throw a excepiton:address in use unless I
 close the serversocket first.

   I has another quetion about RMI.I create tow RMI servers which are
 bound in port 1099.Each of them runs well singly,but when they run at
 the same time(in the same machine),the last one will throw a exception:
   Unexpected exception: neseted exception is:
 java.lang.ClassNotFoundException:RmiServer1_Stub.
 Rmiserver1.class is one RMI server I has defined.

 thanks in advance.
 HuYong

 From: Vijaya Mahalakshmi [EMAIL PROTECTED]
 Reply-To: "A mailing list for discussion about Sun Microsystem's Java
 Servlet API Technology." [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Subject: Re: About BindException little change
 Date: Mon, 11 Oct 1999 00:01:11 -0400
 
 Yong,
  I tried your program with little change which I am sending that,
 the port which is in already  in use will  print 0,(that's what I think)
 ,
 try this it will print your port number
 import java.net.*;
 import java.io.*;
 
 public class UsersServlet
 {
 
 static int SERVLET_PORT=1;
 public static void main(String args[])
 {
   try
   {
   ServerSocket serverSocket = new ServerSocket(SERVLET_PORT);
   System.out.println(serverSocket.getLocalPort());
   ServerSocket rSocket = new ServerSocket(SERVLET_PORT);
   System.out.println(rSocket.getLocalPort());
   }
   catch(Exception e)
   {
   }
 
 }
 }
 Thanks for your problem,
 vijaya

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Re: About BindException bug

1999-10-12 Thread Yong Hu

Thanks.
If does this mean that I can't registry tow RMIServer in the default
RMI port,that is 1099?

Regards
Huyong


From: Vijaya Mahalakshmi [EMAIL PROTECTED]
Reply-To: "A mailing list for discussion about Sun Microsystem's Java
Servlet API Technology." [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: Re: About BindException bug
Date: Tue, 12 Oct 1999 07:28:24 -0400

Yong,
The bug is nothing but if try to use the same port again it  gives
exception.
i think you follow this..
  --
  From: Yong Hu[SMTP:[EMAIL PROTECTED]]
  Reply To: A mailing list for discussion about Sun Microsystem's Java
  Servlet API Technology.
  Sent: Tuesday, October 12, 1999 6:52 AM
  To:   [EMAIL PROTECTED]
  Subject:  Re: About BindException little change
 
  vijaya,
Thanks for your help.I has tried your code and it works well.But
  there is a bug in the code.The code "ServerSocket rSocket = new
  ServerSocket(SERVLET_PORT)" will throw a excepiton:address in use unless
I
  close the serversocket first.
 
I has another quetion about RMI.I create tow RMI servers which are
  bound in port 1099.Each of them runs well singly,but when they run at
  the same time(in the same machine),the last one will throw a exception:
Unexpected exception: neseted exception is:
  java.lang.ClassNotFoundException:RmiServer1_Stub.
  Rmiserver1.class is one RMI server I has defined.
 
  thanks in advance.
  HuYong
 
  From: Vijaya Mahalakshmi [EMAIL PROTECTED]
  Reply-To: "A mailing list for discussion about Sun Microsystem's Java
  Servlet API Technology." [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Subject: Re: About BindException little change
  Date: Mon, 11 Oct 1999 00:01:11 -0400
  
  Yong,
   I tried your program with little change which I am sending
that,
  the port which is in already  in use will  print 0,(that's what I
think)
  ,
  try this it will print your port number
  import java.net.*;
  import java.io.*;
  
  public class UsersServlet
  {
  
  static int SERVLET_PORT=1;
  public static void main(String args[])
  {
try
{
ServerSocket serverSocket = new ServerSocket(SERVLET_PORT);
System.out.println(serverSocket.getLocalPort());
ServerSocket rSocket = new ServerSocket(SERVLET_PORT);
System.out.println(rSocket.getLocalPort());
}
catch(Exception e)
{
}
  
  }
  }
  Thanks for your problem,
  vijaya
 
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