Hi guys. I'm using sqlalchemy 1.1.13, want to construct that query: select o.*, jsonb_agg(ou.*) from "Orders" o left join "OrderUIN" ou on ou."OrderID" = o."OrderID" group by o."OrderID"
I tried that options: - func.jsonb_agg(OrderUINTable), got select o.*, jsonb_agg() from "Orders"... Empty argument for the function, as you can see. - func.jsonb_agg(OrderUINTable.columns.values()), got can't adapt type 'Column' - func.jsonb_agg(OrderUINTable.alias), got TypeError: self_group() got an unexpected keyword argument 'against' How can I implement it? -- SQLAlchemy - The Python SQL Toolkit and Object Relational Mapper http://www.sqlalchemy.org/ To post example code, please provide an MCVE: Minimal, Complete, and Verifiable Example. See http://stackoverflow.com/help/mcve for a full description. --- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at https://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.
