Re: [sqlite] Why am I not getting anything?

2019-02-09 Thread Igor Korot 
Thank you.

On Sun, Feb 10, 2019 at 1:35 AM Shawn Wagner  wrote:
>
> SELECT * FROM pragma_foreign_key_list('temp1');
>
> The table name needs to be a string for the pragma_foreign_key_list virtual
> table. (It's not for the corresponding pragma statement.)
>
> On Sat, Feb 9, 2019, 11:31 PM Igor Korot 
> > Hi, ALL,
> >
> > [code]
> > sqlite> SELECT * FROM sqlite_master WHERE name LIKE '%temp%';
> > type|name|tbl_name|rootpage|sql
> > table|temp|temp|40|CREATE TABLE temp(id INTEGER PRIMARY KEY, name
> > VARCHAR(200))
> > table|temp1|temp1|41|CREATE TABLE temp1(myid INTEGER PRIMARY KEY, id
> > INTEGER, my
> > name VARCHAR(200), CONSTRAINT temp1tempid FOREIGN KEY(id) REFERENCES
> > temp(id))
> > table|temp2|temp2|43|CREATE TABLE temp2(id INTEGER, name TEXT, value
> > NUMERIC(15,
> >  2))
> > table|temp3|temp3|1268|CREATE TABLE temp3(id INTEGER PRIMARY KEY, data
> > TEXT)
> > table|temp4|temp4|1269|CREATE TABLE temp4(myid INTEGER PRIMARY KEY, id
> > INTEGER,
> > myname VARCHAR(200), FOREIGN KEY(id) REFERENCES temp(id))
> > sqlite>
> > sqlite>
> > sqlite>
> > sqlite> SELECT * FROM pragma_foreign_key_list(temp1);
> > Error: no such column: temp1
> > sqlite>
> > [/code]
> >
> > I should get an information about the foreign key that exists for the
> > table temp1,
> > but I have an error.
> >
> > And when I execute the PRAGMA directly, I do get the results:
> >
> > [code]
> > sqlite> PRAGMA foreign_key_list(temp1);
> > id|seq|table|from|to|on_update|on_delete|match
> > 0|0|temp|id|id|NO ACTION|NO ACTION|NONE
> > [/code]
> >
> > [code]
> > sqlite> .version
> > SQLite 3.24.0 2018-06-04 19:24:41
> > c7ee0833225bfd8c5ec2f9bf62b97c4e04d03bd9566366
> > d5221ac8fb199a87ca
> > zlib version 1.2.11
> > gcc-5.2.0
> > sqlite>
> > [/code]
> >
> > This is on Windows 8.1
> >
> > Am I doing something wrong?
> > ___
> > sqlite-users mailing list
> > sqlite-users@mailinglists.sqlite.org
> > http://mailinglists.sqlite.org/cgi-bin/mailman/listinfo/sqlite-users
> >
> ___
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Re: [sqlite] Why am I not getting anything?

2019-02-09 Thread Shawn Wagner 
SELECT * FROM pragma_foreign_key_list('temp1');

The table name needs to be a string for the pragma_foreign_key_list virtual
table. (It's not for the corresponding pragma statement.)

On Sat, Feb 9, 2019, 11:31 PM Igor Korot  Hi, ALL,
>
> [code]
> sqlite> SELECT * FROM sqlite_master WHERE name LIKE '%temp%';
> type|name|tbl_name|rootpage|sql
> table|temp|temp|40|CREATE TABLE temp(id INTEGER PRIMARY KEY, name
> VARCHAR(200))
> table|temp1|temp1|41|CREATE TABLE temp1(myid INTEGER PRIMARY KEY, id
> INTEGER, my
> name VARCHAR(200), CONSTRAINT temp1tempid FOREIGN KEY(id) REFERENCES
> temp(id))
> table|temp2|temp2|43|CREATE TABLE temp2(id INTEGER, name TEXT, value
> NUMERIC(15,
>  2))
> table|temp3|temp3|1268|CREATE TABLE temp3(id INTEGER PRIMARY KEY, data
> TEXT)
> table|temp4|temp4|1269|CREATE TABLE temp4(myid INTEGER PRIMARY KEY, id
> INTEGER,
> myname VARCHAR(200), FOREIGN KEY(id) REFERENCES temp(id))
> sqlite>
> sqlite>
> sqlite>
> sqlite> SELECT * FROM pragma_foreign_key_list(temp1);
> Error: no such column: temp1
> sqlite>
> [/code]
>
> I should get an information about the foreign key that exists for the
> table temp1,
> but I have an error.
>
> And when I execute the PRAGMA directly, I do get the results:
>
> [code]
> sqlite> PRAGMA foreign_key_list(temp1);
> id|seq|table|from|to|on_update|on_delete|match
> 0|0|temp|id|id|NO ACTION|NO ACTION|NONE
> [/code]
>
> [code]
> sqlite> .version
> SQLite 3.24.0 2018-06-04 19:24:41
> c7ee0833225bfd8c5ec2f9bf62b97c4e04d03bd9566366
> d5221ac8fb199a87ca
> zlib version 1.2.11
> gcc-5.2.0
> sqlite>
> [/code]
>
> This is on Windows 8.1
>
> Am I doing something wrong?
> ___
> sqlite-users mailing list
> sqlite-users@mailinglists.sqlite.org
> http://mailinglists.sqlite.org/cgi-bin/mailman/listinfo/sqlite-users
>
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[sqlite] Why am I not getting anything?

2019-02-09 Thread Igor Korot 
Hi, ALL,

[code]
sqlite> SELECT * FROM sqlite_master WHERE name LIKE '%temp%';
type|name|tbl_name|rootpage|sql
table|temp|temp|40|CREATE TABLE temp(id INTEGER PRIMARY KEY, name VARCHAR(200))
table|temp1|temp1|41|CREATE TABLE temp1(myid INTEGER PRIMARY KEY, id INTEGER, my
name VARCHAR(200), CONSTRAINT temp1tempid FOREIGN KEY(id) REFERENCES temp(id))
table|temp2|temp2|43|CREATE TABLE temp2(id INTEGER, name TEXT, value NUMERIC(15,
 2))
table|temp3|temp3|1268|CREATE TABLE temp3(id INTEGER PRIMARY KEY, data TEXT)
table|temp4|temp4|1269|CREATE TABLE temp4(myid INTEGER PRIMARY KEY, id INTEGER,
myname VARCHAR(200), FOREIGN KEY(id) REFERENCES temp(id))
sqlite>
sqlite>
sqlite>
sqlite> SELECT * FROM pragma_foreign_key_list(temp1);
Error: no such column: temp1
sqlite>
[/code]

I should get an information about the foreign key that exists for the
table temp1,
but I have an error.

And when I execute the PRAGMA directly, I do get the results:

[code]
sqlite> PRAGMA foreign_key_list(temp1);
id|seq|table|from|to|on_update|on_delete|match
0|0|temp|id|id|NO ACTION|NO ACTION|NONE
[/code]

[code]
sqlite> .version
SQLite 3.24.0 2018-06-04 19:24:41 c7ee0833225bfd8c5ec2f9bf62b97c4e04d03bd9566366
d5221ac8fb199a87ca
zlib version 1.2.11
gcc-5.2.0
sqlite>
[/code]

This is on Windows 8.1

Am I doing something wrong?
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