CPU 100% usage in applet
Hi, I am running my applet on IE 5.5 not using any plugin, on a NT heavy duty machine. The applet takes up 100% CPU. The applet does not have any GUI component but launches JSP pages. The applet connects to backend resources using socket, uses threads etc. The bulk of the code is in Java classes- the classes themselves run fine outside of the applet. I can see the memory usage- that is not high. Any ideas or suggestions welcome. How can we measure CPU usage in Java? Thanks a lot, Sanjay __ Do You Yahoo!? Yahoo! Finance - Get real-time stock quotes http://finance.yahoo.com -- To unsubscribe, e-mail: mailto:[EMAIL PROTECTED] For additional commands, e-mail: mailto:[EMAIL PROTECTED]
GetPort returning -1 from applet
Trying to get portnumber from an applet running on Apache. get the port number as -1. This is whether I use the url with/without the port number- URL currrentPage = getCodeBase(); String protocol = currrentPage.getProtocol(); String host= currrentPage.getHost(); int port= currrentPage.getPort(); The host comes correctly as- localhost but port returns as -1. Thanks Sanjay __ Do You Yahoo!? Yahoo! Health - Feel better, live better http://health.yahoo.com -- To unsubscribe, e-mail: mailto:[EMAIL PROTECTED] For additional commands, e-mail: mailto:[EMAIL PROTECTED]
RE: Working Directory
Thanks all for responding. The most suitable approach for me is: InputStream is = this.getClass().getClassLoader().getResourceAsStream(myApp.properties); I just put my file in the classes directory- that is what I would like. Sanjay --- Jacob Kjome [EMAIL PROTECTED] wrote: That might work in most cases, but it won't find the file in a container that doesn't expand the .war archive. The following will read it whether in a directory structure or in a .war archive: InputStream is = getServletContext().getResourceAsStream(/WEB-INF/myApp.properties); If the file exists in the same package as the class, you can load it like this: InputStream is = this.getClass().getResourceAsStream(myApp.properties); I would think you could also do this to find it in the classes directory: InputStream is = this.getClass().getClassLoader().getResourceAsStream(myApp.properties); All those methods are independent of the filesystem. Jake At 11:38 AM 4/3/2002 -0500, you wrote: I place my properties files in the WEB-INF directory and do the following to find them - String webInfFolder = getServletContext().getRealPath(/WEB-INF) -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Wednesday, April 03, 2002 11:34 AM To: tomcat Subject: Working Directory I am trying to read a properties file from my servlet. It always comes back saying file not found. I have tried placing the file in classes/web-inf/context-path. Ideally I would like to lace it in my classes directory- How do I achieve it. Thanks Sanjay __ Do You Yahoo!? Yahoo! Tax Center - online filing with TurboTax http://taxes.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Tax Center - online filing with TurboTax http://taxes.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Working Directory
I am trying to read a properties file from my servlet. It always comes back saying file not found. I have tried placing the file in classes/web-inf/context-path. Ideally I would like to lace it in my classes directory- How do I achieve it. Thanks Sanjay __ Do You Yahoo!? Yahoo! Tax Center - online filing with TurboTax http://taxes.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Working Directory
Thanks Mark Craig. My situation is slightly different. I am trying to read the property file from a Java class on the server(not the servlet). I would think there would be a way around to do this- else I can work around to pass a param to the helper class. Thanks Sanjay --- Craig R. McClanahan [EMAIL PROTECTED] wrote: On Wed, 3 Apr 2002, Wagoner, Mark wrote: Date: Wed, 3 Apr 2002 11:38:31 -0500 From: Wagoner, Mark [EMAIL PROTECTED] Reply-To: Tomcat Users List [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Subject: RE: Working Directory I place my properties files in the WEB-INF directory and do the following to find them - String webInfFolder = getServletContext().getRealPath(/WEB-INF) This only works if the app is run from an unpacked directory, which is not guaranteed to be portable (not every server supports running this way). The best way to read a properties file is to put it in the WEB-INF subdirectory and use something like: Properties props = new Properties(); InputStream stream = getServletContext().getResourceAsStream(/WEB-INF/myprops.properties); props.load(stream); stream.close(); which is guaranteed to be portable to any server. Craig -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Wednesday, April 03, 2002 11:34 AM To: tomcat Subject: Working Directory I am trying to read a properties file from my servlet. It always comes back saying file not found. I have tried placing the file in classes/web-inf/context-path. Ideally I would like to lace it in my classes directory- How do I achieve it. Thanks Sanjay __ Do You Yahoo!? Yahoo! Tax Center - online filing with TurboTax http://taxes.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Tax Center - online filing with TurboTax http://taxes.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Working Directory
Carig,
I tried this it does not work. I can't get the stream.
I have a property file in the classes directory- where
I all my classes are. My code is:
MyClass thisInstance = new MyClass();
InputStream stream =
thisInstance.getClass().getResourceAsStream(propFile);
if ( stream != null) {
props.load(stream);
stream.close();
}else System.out.println(The stream null);
Thanks
Sanjay
--- Craig R. McClanahan [EMAIL PROTECTED] wrote:
On Wed, 3 Apr 2002, Sanjay Bahal wrote:
Date: Wed, 3 Apr 2002 12:00:17 -0800 (PST)
From: Sanjay Bahal [EMAIL PROTECTED]
Reply-To: Tomcat Users List
[EMAIL PROTECTED]
To: Tomcat Users List
[EMAIL PROTECTED]
Subject: RE: Working Directory
Thanks Mark Craig.
My situation is slightly different. I am trying to
read the property file from a Java class on the
server(not the servlet). I would think there would
be
a way around to do this- else I can work around to
pass a param to the helper class.
Consider using
getClass().getResourceAsStream(myprops.properties)
for
this kind of purpose. This looks for
myprops.properties on your class
path, and loads it from wherever the classes
themselves are found (either
an unpacked directory or a JAR file).
Thanks
Sanjay
Craig
--- Craig R. McClanahan [EMAIL PROTECTED]
wrote:
On Wed, 3 Apr 2002, Wagoner, Mark wrote:
Date: Wed, 3 Apr 2002 11:38:31 -0500
From: Wagoner, Mark
[EMAIL PROTECTED]
Reply-To: Tomcat Users List
[EMAIL PROTECTED]
To: 'Tomcat Users List'
[EMAIL PROTECTED]
Subject: RE: Working Directory
I place my properties files in the WEB-INF
directory and do the following to
find them -
String webInfFolder =
getServletContext().getRealPath(/WEB-INF)
This only works if the app is run from an
unpacked
directory, which is not
guaranteed to be portable (not every server
supports
running this way).
The best way to read a properties file is to put
it
in the WEB-INF
subdirectory and use something like:
Properties props = new Properties();
InputStream stream =
getServletContext().getResourceAsStream(/WEB-INF/myprops.properties);
props.load(stream);
stream.close();
which is guaranteed to be portable to any
server.
Craig
-Original Message-
From: Sanjay Bahal [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, April 03, 2002 11:34 AM
To: tomcat
Subject: Working Directory
I am trying to read a properties file from my
servlet.
It always comes back saying file not found. I
have
tried placing the file in
classes/web-inf/context-path. Ideally I would
like
to
lace it in my classes directory- How do I
achieve
it.
Thanks
Sanjay
__
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Re: mod_webapp
Can any one give the url for mod_jk or web_app I have not been able to find it on the site. Thanks Sanjay --- Andrzej Jan Taramina [EMAIL PROTECTED] wrote: Searching the jakarta site is like trying to find a needle in a haystack. Does anyone have the url for an already built mod_webapp for windows machines? Far as I know, the current code for mod_webapp on a windows platform still have a critical bug that causes it to block when sending binary (eg. image) data between Apache and Tomcat. Just FYI ...Andrzej Chaeron Corporation http://www.chaeron.com -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Greetings - send holiday greetings for Easter, Passover http://greetings.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: ANYONE HAVE MOD_JK?
I need one too for NT. Thanks a lot, Sanjay --- Neil Streeter [EMAIL PROTECTED] wrote: I have installed all binary packages Tomcat 4.0.3... apache 1.3.24 on windows 2000 is there a binary version of mod_jk available that fits this setup? I couldn't find it... if you have one, could you please send it to me! -- or -- will the 'old' binary that I could find for tomcat 3.x work w/o problems? (it says it was compiled agains the x.17 version of apache - so I'm guessing not) I don't have ms c++ so I'm not able to compile this as far as I know... unless there is a gnu compiler that I can use that will do the trick (please point this out! I don't do much w/ ms products in this realm -- mostly linux) I downloaded the 'connectors src' from tomcat 4.0.1 - but I don't think I can do anything w/ it I could be missing something the docs are sparse in this area... Thanks, ns -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: Tomcat 4 NT Service
I am looking for it too? Thanks, Sanjay --- Karthik Gopal [EMAIL PROTECTED] wrote: Hi , Where can I find the jk_nt_service.exe for Tomcat 4? Or can I reuse any older version of this exe. Thankx Karthik -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: Tomcat 4 NT Service
Thanks Jacob. I will try it out. Sanjay --- Jacob Kjome [EMAIL PROTECTED] wrote: Hello, I saw you both asking how to run Tomcat 4 as an NT Service on the Tomcat User list. I was looking at the archives. I'm not subscribed to the list, which is why I am sending this directly to you. Here is you answer: Install Catalina Service: %CATALINA_HOME%\bin\tomcat.exe -install Apache-Catalina %JAVA_HOME%\jre\bin\server\jvm.dll -Djava.class.path=%CATALINA_HOME%\bin\bootstrap.jar;%JAVA_HOME%\lib\tools.jar -Dcatalina.home=%CATALINA_HOME% %CATALINA_OPTS% -Xrs -start org.apache.catalina.startup.Bootstrap -params start -stop org.apache.catalina.startup.Bootstrap -params stop -out %CATALINA_HOME%\logs\stderr.log Uninstall Catalina Service: %CATALINA_HOME%\bin\tomcat.exe -uninstall Apache-Catalina I found the answer after looking at this article: http://www.webmasterbase.com/printTemplate.php?aid=305 As you can tell, Tomcat 4.xx does not use jk_nt_service.exe like Tomcat 3.xx does. Hope that helps. May I suggest that you post this answer back to the list so others can see how to do this. later, Jake -- Best regards, Jacob mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Configuring Tomcat 4/mod_webapp
What is the exact link to get mod_jk. I can't seem to find it- 4) Integrate Tomcat and Apache Stop the Tomcat and Apache services. Then download mod_webapp from jakarta.apache.org Thanks Sanjay --- Chris Pheby [EMAIL PROTECTED] wrote: Apache, MySQL, Tomcat, Netbeans and Mozilla --- Hope this helps Chris. - 1) Install Apache Install Apache_1.3.22-win32-x86.exe (Windows Installer of latest stable release) to c:\server\ (actually places it in Apache subdirectory of c:\server). During installation select the Run as Service for all Users option. Verify the installation in Control Panel / Services by checking for Apache. 2) Install MySQL Install mysql-max-3.23.49-win.zip by unzipping and running setup.exe Recommend installing to c:\server\mysql Create c:\winnt\my.ini with the following contents: [mysqld] basedir=C:/projects/mysql datadir=C:/projects/mysql/data When you are done add c:\server\mysql\bin to the path environment variable. You can get MySQL-Front from www.mysqlfront.de if you need a graphical front end for the database. Also available is MyODBC, which allows MySQL to be connected to by applications utilising ODBC. You can use the winmysqladmin utility to make mysql-max run as a service instead of mysql which supports transactions with berkeley db tables. 3) Install Java 2 Standard Edition 1.4 Run the J2SE installer, and choose to install to c:\Program Files\Java\J2SE. Install all components and set it as a plugin for all browsers Add the following to the PATH variable: c:\Progra~1\J2SE\bin. Install Tomcat 4.0.4 beta 1 LE Download Tomcat 4.0.4 beta 1 LE (for JDK 1.4) and run the installer. Take care to install Tomcat as a Service when offered the option by the installer. Set the following environment variables: JAVA_HOME - c:\Progra~1\Java\J2SE CATALINA_HOME - c:\Progra~1\Java\Tomcat 4) Integrate Tomcat and Apache Stop the Tomcat and Apache services. Then download mod_webapp from jakarta.apache.org. Extract libapr.dll to c:\winnt\system32. Also extract libapr.dll and mod_webapp.so to c:\server\apache\modules. Add the following lines to httpd.conf: LoadModule webapp_module modules/mod_webapp.so AddModule mod_webapp.c You need to configure a connector in httpd.conf (examples shown for the modules you can export initially - remove the comments to enable them): IfModule mod_webapp.c WebAppConnection warpConnection warp localhost:8008 WebAppInfo /webapp-info #WebAppDeploy examples warpConnection /examples #WebAppDeploy webdav warpConnection /webdav /IfModule Before restarting Apache download Service+ from ActivePlus and use it to set Apache as depending on Tomcat. Then restart Apache (Tomcat will restart automatically). 5) Install JDBC Driver for MySQL Download the MySQL JDBC driver. Open the file (mm.mysql-2.0.11-you-must-unjar-me.jar) in WinZip and extract mm.mysql-2.0.11-bin.jar and place it in c:\program files\java\j2se\jre\lib\ext. It will now be automatically available to Java programs, without needing to add it to the classpath. 6) Install Mozilla Plugin Copy the np* files from C:\Program Files\Java\J2SE\jre\bin to C:\Program Files\Mozilla\Plugins. Restart Mozilla 7) Install NetBeans Install NetBeans to c:\Program Files\Java\NetBeans. The installer will automatically detect the JDK. Netbeans can debug Tomcat, if you want to enable this first remove the existing Tomcat Service: net stop Apache Tomcat c:\progra~1\java\tomcat\bin\tomcat.exe -uninstall Apache Tomcat Next install the modified Tomcat service which is enabled for debugging: Tomcat.exe -install Apache Tomcat c:\progra~1\java\j2se\jre\bin\server\jvm.dll -Djava.class.path=c:\progra~1\j ava\tomcat\bin\bootstrap.jar;c:\progra~1\java\tomcat\bin\servlet.jar;C:\Prog ra~1\Java\J2SE\lib\tools.jar -Xint -Xdebug -Xnoagent -Xrunjdwp:transport=dt_ socket,server=y,address=12999,suspend=n -Dcatalina.home=c:\progra~1\java\tom cat\ -start org.apache.catalina.startup.Bootstrap -params start -stop org.apache.catalina.startup.Bootstrap -params stop -out c:\progra~1\java\tomcat\logs\stdout.log -err c:\progra~1\java\tomcat\logs\stderr.log Make the service depend on MySQL as before Once Tomcat has been restarted go to Netbeans, and select the Debug / Attach menu. Seelect JPDA as the Debugger Type, Socket Attach, the hostname of the machine Tomcat is on, and 12999 as the port. It is now possible to debug the running Tomcat server. To assist debugging mount the Tomcat Sources in the Netbeans explorer: C:\Program Files\Java\J2SE\src C:\Program Files\Java\Tomcat\src\catalina\src\share C:\Program Files\Java\Tomcat\src\catalina\src\test C:\Program Files\Java\Tomcat\src\jasper\src\share -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] On Behalf Of Larry Chambers Sent:
Tomact-Apache Link
How do I link Apache and Tomcat. Is it mod_jk or mod_webapp. What are the links to get them. Thanks a lot, Sanjay __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Servlet mapping question
I found a problem with this. If you don't do /* it becomes case sensitive. So that again becomes an issue. Sanjay --- Sanjay Bahal [EMAIL PROTECTED] wrote: Yes this works? I will paly with it more and post. Thanks a lot, Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Sanjay, Try http://localhost:8080/context/search/SearchServlet where context is the directory name under webapps. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Monday, March 25, 2002 5:04 PM To: Tomcat Users List Subject: RE: Servlet mapping question My problem has been this mapping has not worked: servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/SearchServlet/url-pattern /servlet-mapping If I try to call this- http://localhost:8080/search/SearchServlet it fails uneless I make mapiing to /search/*. Thanks Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Then according to Craig's previous email you need to-do something like this: servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/SearchServlet/url-pattern /servlet-mapping servlet-mapping servlet-nameSearchServlet2/servlet-name url-pattern/search/SearchServlet2/url-pattern /servlet-mapping then you should reach it with http:/.../search/SearchServlet or http://.../search/SerchServlet2 for you're two different ones. Let me know if this is what you are looking for. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Friday, March 22, 2002 3:16 PM To: Tomcat Users List Subject: RE: Servlet mapping question I have a similar issue- albeit simpler. I have two servlets in one subdir. I have mapped it with something like- servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/*/url-pattern /servlet-mapping As a result of which /search/anything calls the SearchServlet. How do I map to another servlet in the same directory. I tried removing the /* and giving a specific name- the 1st servlet itself fails. Thanks Sanjay --- Craig R. McClanahan [EMAIL PROTECTED] wrote: On Fri, 22 Mar 2002, Sean LeBlanc wrote: To add even more to this - I can't even get the pattern like this to work: url-pattern/c*/url-pattern anything typed doesn't seem to get recognized and used by the servlet. Any ideas would be welcome. You might start by consulting the Servlet Specification, to see what mapping patterns are legal :-). http://java.sun.com/products/servlet/download.html 1. Exact match (/foo or /foo/bar) 2. Prefix match (/* or /foo/* or /foo/bar/*) 3. Extension match (*.jsp or *.foo) 4. Default servlet (/) used if no other mapping matches. (NOTE: Tomcat 4 uses this for the file-serving servlet, so replacing it will remove file serving unless you do that yourself) The rules are applied hierarchically -- in other words, the container checks for exact matches first, then prefix matches, ... In each case, request.getServletPath() will return the portion of the request URI that was used to map to your servlet. In case (2), anything after the matching part will be returned via request.getPathInfo(). Craig McClanahan -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] === message truncated === __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Servlet mapping question
What I am trying to do now is mapping my servlets to names like /search/* to SearchServlet /def/* to DefaultServlet etc. I would think this is a convulted naming/mapping convention but that is as far as I have been able to think. Thanks a lot, Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: All tomcat URLs are case sensitive just like *nix, even on windoz. Nothing we can do about it. Other method is to map /* to a specific servlet that parses the * and send it on to the correct class. Then you could make it none case sensitive. -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Tuesday, March 26, 2002 12:19 PM To: Tomcat Users List Subject: RE: Servlet mapping question I found a problem with this. If you don't do /* it becomes case sensitive. So that again becomes an issue. Sanjay --- Sanjay Bahal [EMAIL PROTECTED] wrote: Yes this works? I will paly with it more and post. Thanks a lot, Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Sanjay, Try http://localhost:8080/context/search/SearchServlet where context is the directory name under webapps. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Monday, March 25, 2002 5:04 PM To: Tomcat Users List Subject: RE: Servlet mapping question My problem has been this mapping has not worked: servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/SearchServlet/url-pattern /servlet-mapping If I try to call this- http://localhost:8080/search/SearchServlet it fails uneless I make mapiing to /search/*. Thanks Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Then according to Craig's previous email you need to-do something like this: servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/SearchServlet/url-pattern /servlet-mapping servlet-mapping servlet-nameSearchServlet2/servlet-name url-pattern/search/SearchServlet2/url-pattern /servlet-mapping then you should reach it with http:/.../search/SearchServlet or http://.../search/SerchServlet2 for you're two different ones. Let me know if this is what you are looking for. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Friday, March 22, 2002 3:16 PM To: Tomcat Users List Subject: RE: Servlet mapping question I have a similar issue- albeit simpler. I have two servlets in one subdir. I have mapped it with something like- servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/*/url-pattern /servlet-mapping As a result of which /search/anything calls the SearchServlet. How do I map to another servlet in the same directory. I tried removing the /* and giving a specific name- the 1st servlet itself fails. Thanks Sanjay --- Craig R. McClanahan [EMAIL PROTECTED] wrote: On Fri, 22 Mar 2002, Sean LeBlanc wrote: To add even more to this - I can't even get the pattern like this to work: url-pattern/c*/url-pattern anything typed doesn't seem to get recognized and used by the servlet. Any ideas would be welcome. You might start by consulting the Servlet Specification, to see what mapping patterns are legal :-). http://java.sun.com/products/servlet/download.html 1. Exact match (/foo or /foo/bar) 2. Prefix match (/* or /foo/* or /foo/bar/*) 3. Extension match (*.jsp or *.foo) 4. Default servlet (/) used if no other mapping matches. (NOTE: Tomcat 4 uses this for the file-serving servlet, so replacing it will remove file serving unless you do that yourself) The rules are applied hierarchically -- in other words, the container checks for exact matches first, then prefix matches, ... In each case, request.getServletPath() will return the portion of the request URI that was used to map to your servlet. In case (2), anything after the matching part will be returned via request.getPathInfo(). Craig McClanahan -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. === message truncated === __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th
RE: Servlet mapping question
My problem has been this mapping has not worked: servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/SearchServlet/url-pattern /servlet-mapping If I try to call this- http://localhost:8080/search/SearchServlet it fails uneless I make mapiing to /search/*. Thanks Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Then according to Craig's previous email you need to-do something like this: servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/SearchServlet/url-pattern /servlet-mapping servlet-mapping servlet-nameSearchServlet2/servlet-name url-pattern/search/SearchServlet2/url-pattern /servlet-mapping then you should reach it with http:/.../search/SearchServlet or http://.../search/SerchServlet2 for you're two different ones. Let me know if this is what you are looking for. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Friday, March 22, 2002 3:16 PM To: Tomcat Users List Subject: RE: Servlet mapping question I have a similar issue- albeit simpler. I have two servlets in one subdir. I have mapped it with something like- servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/*/url-pattern /servlet-mapping As a result of which /search/anything calls the SearchServlet. How do I map to another servlet in the same directory. I tried removing the /* and giving a specific name- the 1st servlet itself fails. Thanks Sanjay --- Craig R. McClanahan [EMAIL PROTECTED] wrote: On Fri, 22 Mar 2002, Sean LeBlanc wrote: To add even more to this - I can't even get the pattern like this to work: url-pattern/c*/url-pattern anything typed doesn't seem to get recognized and used by the servlet. Any ideas would be welcome. You might start by consulting the Servlet Specification, to see what mapping patterns are legal :-). http://java.sun.com/products/servlet/download.html 1. Exact match (/foo or /foo/bar) 2. Prefix match (/* or /foo/* or /foo/bar/*) 3. Extension match (*.jsp or *.foo) 4. Default servlet (/) used if no other mapping matches. (NOTE: Tomcat 4 uses this for the file-serving servlet, so replacing it will remove file serving unless you do that yourself) The rules are applied hierarchically -- in other words, the container checks for exact matches first, then prefix matches, ... In each case, request.getServletPath() will return the portion of the request URI that was used to map to your servlet. In case (2), anything after the matching part will be returned via request.getPathInfo(). Craig McClanahan -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Servlet mapping question
Yes this works? I will paly with it more and post. Thanks a lot, Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Sanjay, Try http://localhost:8080/context/search/SearchServlet where context is the directory name under webapps. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Monday, March 25, 2002 5:04 PM To: Tomcat Users List Subject: RE: Servlet mapping question My problem has been this mapping has not worked: servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/SearchServlet/url-pattern /servlet-mapping If I try to call this- http://localhost:8080/search/SearchServlet it fails uneless I make mapiing to /search/*. Thanks Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Then according to Craig's previous email you need to-do something like this: servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/SearchServlet/url-pattern /servlet-mapping servlet-mapping servlet-nameSearchServlet2/servlet-name url-pattern/search/SearchServlet2/url-pattern /servlet-mapping then you should reach it with http:/.../search/SearchServlet or http://.../search/SerchServlet2 for you're two different ones. Let me know if this is what you are looking for. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Friday, March 22, 2002 3:16 PM To: Tomcat Users List Subject: RE: Servlet mapping question I have a similar issue- albeit simpler. I have two servlets in one subdir. I have mapped it with something like- servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/*/url-pattern /servlet-mapping As a result of which /search/anything calls the SearchServlet. How do I map to another servlet in the same directory. I tried removing the /* and giving a specific name- the 1st servlet itself fails. Thanks Sanjay --- Craig R. McClanahan [EMAIL PROTECTED] wrote: On Fri, 22 Mar 2002, Sean LeBlanc wrote: To add even more to this - I can't even get the pattern like this to work: url-pattern/c*/url-pattern anything typed doesn't seem to get recognized and used by the servlet. Any ideas would be welcome. You might start by consulting the Servlet Specification, to see what mapping patterns are legal :-). http://java.sun.com/products/servlet/download.html 1. Exact match (/foo or /foo/bar) 2. Prefix match (/* or /foo/* or /foo/bar/*) 3. Extension match (*.jsp or *.foo) 4. Default servlet (/) used if no other mapping matches. (NOTE: Tomcat 4 uses this for the file-serving servlet, so replacing it will remove file serving unless you do that yourself) The rules are applied hierarchically -- in other words, the container checks for exact matches first, then prefix matches, ... In each case, request.getServletPath() will return the portion of the request URI that was used to map to your servlet. In case (2), anything after the matching part will be returned via request.getPathInfo(). Craig McClanahan -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: how to redirect System.out, or a relevant link please
Try this: System.setOut(new PrintStream(new FileOutputStream(filename,true))); System.setErr(new PrintStream(new FileOutputStream(filename,true))); --- Leila Lappin [EMAIL PROTECTED] wrote: Hello everyone, Could someone please send me a link to find information on redirecting system.out and system.err. I've been to http://www.jguru.com/faq/view.jsp?EID=302980 they suggested reading the relevant discussion on the archived mailing list http://mikal.org/interests/java/tomcat/archive/search?start=60search=how+to+redirect ). I'm still reading through and haven't found the answer. I've setup Logger tag in server.xml and it points to org.apache.catalina.logger.FileLogger. I get all messages generated by tomcat but nothing from my own diagnostics. I'm using tomcat-4.0.2 on Redhat 7.2. thanks in advance for your help. Leila __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Servlet Deploy Problem Help
Lance, Yes- that is what I want to do: http://.../search/servletName or its mapping. for each servlet I want to map and call it. Lets say I have 5 different servlets- I want to have 5 mappings and call them all by their names. what is this Front Controller pattern- you have some kind of an example? Thanks Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Sanjay, If I understand you're request what you want is /search/hello /search/abc /search/def with hello, abc, and def all being servlets. Then you want to be able to reach each servlet with the url http://.../search/servletName. If this is the case I think you will end up adding a servlet-mapping entry for each servlet you want to call. Unless someone else can help. The other methos is the Front Controller pattern where a single Controller/servlet is mapped and it dispatches the request on to the proper place. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Friday, March 22, 2002 10:24 AM To: Tomcat Users List Subject: RE: Servlet Deploy Problem Help Lance, Thanks. Ideally I don't want to call my servlet with /abc. In this case whatever tag I give it will open the same one. However what I need instead is to call diffrenet servlets with /search/hello/servletalias. How can I achieve that. Thanks Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Now try http://localhost:8080/search/hello/abc it should work also. getting it to work with just /search/hello gets into mapping issues I haven't had to work out yet sorry. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 12:42 PM To: Tomcat Users List Subject: RE: Servlet Deploy Problem Help Lance - yes it works thanks a lot. But what are other shorter forms that I can use to call the servlet. I would hope to call it with like /search/hello. What has the /hello/* mapping bought me. Thanks Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: try http://localhost:8080/search/hello/HelloWorld let me know if this works. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 10:13 AM To: Tomcat Users List Subject: RE: Servlet Deploy Problem Help Lance, So in other words if I may to /hello/* I would be able to call my servelet with /hello? or the full URL http://localhost:8080/search/hello? I tried it did not work- requested resource (/hello) is not available. Thanks a lot, Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Sanjay, The servlet-mapping is a tag that allows you to map a specified pattern to the specified servlet. Don't get me started on the pattern syntax I still haven't taken the time to fully comprehend it. So basically what we told the server was that anytime it sees the pattern /hello/ in the context of this app send it to the HelloWorld servlet. The anything means anything you want to type after the /hello/ since we told it to match on the /hello/. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 9:01 AM To: Tomcat Users List Subject: RE: Servlet Deploy Problem Help Lance Thanks. What does servlet-mapping mean- is it directory structure or an alias to a servlet.I was trying to use /hello as an alias for the HelloWorld servlet and try calling it by /hello or by full URL /hello- am I completely off on this. and what is this anything? Thanks again servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/*/url-pattern /servlet-mapping Then you should be able to call it like: http://localhost:8080/search/hello/anything --- Lance Smith [EMAIL PROTECTED] wrote: In you're web.xml change: servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping to : servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/*/url-pattern /servlet-mapping Then you should be able to call it like: http://localhost:8080/search/hello/anything Hope this helps Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 8:21 AM To: [EMAIL PROTECTED] Subject: Servlet Deploy Problem Help I am just restarting this thread. My problem remains unsolved. I am running Tomcat4.01/NT. The setup should be OK as the examples run. I am trying to deploy the HelloWorldExample. My directory structure is- Tomcat4\webapps\search
RE: Servlet mapping question
I have a similar issue- albeit simpler. I have two servlets in one subdir. I have mapped it with something like- servlet-mapping servlet-nameSearchServlet/servlet-name url-pattern/search/*/url-pattern /servlet-mapping As a result of which /search/anything calls the SearchServlet. How do I map to another servlet in the same directory. I tried removing the /* and giving a specific name- the 1st servlet itself fails. Thanks Sanjay --- Craig R. McClanahan [EMAIL PROTECTED] wrote: On Fri, 22 Mar 2002, Sean LeBlanc wrote: To add even more to this - I can't even get the pattern like this to work: url-pattern/c*/url-pattern anything typed doesn't seem to get recognized and used by the servlet. Any ideas would be welcome. You might start by consulting the Servlet Specification, to see what mapping patterns are legal :-). http://java.sun.com/products/servlet/download.html 1. Exact match (/foo or /foo/bar) 2. Prefix match (/* or /foo/* or /foo/bar/*) 3. Extension match (*.jsp or *.foo) 4. Default servlet (/) used if no other mapping matches. (NOTE: Tomcat 4 uses this for the file-serving servlet, so replacing it will remove file serving unless you do that yourself) The rules are applied hierarchically -- in other words, the container checks for exact matches first, then prefix matches, ... In each case, request.getServletPath() will return the portion of the request URI that was used to map to your servlet. In case (2), anything after the matching part will be returned via request.getPathInfo(). Craig McClanahan -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Servlet Deploy Problem Help
I am just restarting this thread. My problem remains unsolved. I am running Tomcat4.01/NT. The setup should be OK as the examples run. I am trying to deploy the HelloWorldExample. My directory structure is- Tomcat4\webapps\search\WEB-INF\classes I have my .htm file in the \search directory and my class in the \classes and my web.xml in the \WEB-INF. My web.xml looks like this- I have used the example file to create it- servlet servlet-nameHelloWorld/servlet-name description HelloWorld /description servlet-classHelloWorldExample/servlet-class /servlet servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping Is this web.xml correct? I have not been able to execute my servelt any which way: /hello http://localhost:8080/search/servlet/HelloWorldExample http://localhost:8080/search/servlet/HelloWorld http://localhost:8080/search/HelloWorld I either get a resource not found or java.util.MissingResourceException: Can't find bundle for base name LocalStrings, locale en_US at java.util.ResourceBundle.throwMissingResourceException(ResourceBundle.java:707) at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:604) at java.util.ResourceBundle.getBundle(ResourceBundle.java:559) at HelloWorldExample.doGet(Unknown Source) My question is how do I exceute it- from the /search directory or from anywhere else using a full url path. Thanks a lot, Sanjay __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Servlet Deploy Problem Help
Thanks of the insight. The servlet is a HelloWorld example. The only imports in the class are: import java.io.*; import java.text.*; import java.util.*; import javax.servlet.*; import javax.servlet.http.*; I would easily suppose these should be available to Tomcat. If not what do I do. Thanks Sanjay --- Randy Layman [EMAIL PROTECTED] wrote: The stack trace you included indicates that you are running the servlet, but its throwing an exception. -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 9:21 AM To: [EMAIL PROTECTED] Subject: Servlet Deploy Problem Help I either get a resource not found or java.util.MissingResourceException: Can't find bundle for base name LocalStrings, locale en_US at java.util.ResourceBundle.throwMissingResourceException(Resourc eBundle.java:707) at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:604) at java.util.ResourceBundle.getBundle(ResourceBundle.java:559) at HelloWorldExample.doGet(Unknown Source) If your servlet wasn't being called then you wouldn't see it in the stack trace. I would suggest that you look at how you are loading resources in your servlet (they are probably not in the classpath). Randy -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Servlet Deploy Problem Help
Lance Thanks. What does servlet-mapping mean- is it directory structure or an alias to a servlet.I was trying to use /hello as an alias for the HelloWorld servlet and try calling it by /hello or by full URL /hello- am I completely off on this. and what is this anything? Thanks again servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/*/url-pattern /servlet-mapping Then you should be able to call it like: http://localhost:8080/search/hello/anything --- Lance Smith [EMAIL PROTECTED] wrote: In you're web.xml change: servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping to : servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/*/url-pattern /servlet-mapping Then you should be able to call it like: http://localhost:8080/search/hello/anything Hope this helps Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 8:21 AM To: [EMAIL PROTECTED] Subject: Servlet Deploy Problem Help I am just restarting this thread. My problem remains unsolved. I am running Tomcat4.01/NT. The setup should be OK as the examples run. I am trying to deploy the HelloWorldExample. My directory structure is- Tomcat4\webapps\search\WEB-INF\classes I have my .htm file in the \search directory and my class in the \classes and my web.xml in the \WEB-INF. My web.xml looks like this- I have used the example file to create it- servlet servlet-nameHelloWorld/servlet-name description HelloWorld /description servlet-classHelloWorldExample/servlet-class /servlet servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping Is this web.xml correct? I have not been able to execute my servelt any which way: /hello http://localhost:8080/search/servlet/HelloWorldExample http://localhost:8080/search/servlet/HelloWorld http://localhost:8080/search/HelloWorld I either get a resource not found or java.util.MissingResourceException: Can't find bundle for base name LocalStrings, locale en_US at java.util.ResourceBundle.throwMissingResourceException(ResourceBundle.java:7 07) at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:604) at java.util.ResourceBundle.getBundle(ResourceBundle.java:559) at HelloWorldExample.doGet(Unknown Source) My question is how do I exceute it- from the /search directory or from anywhere else using a full url path. Thanks a lot, Sanjay __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Servlet Deploy Problem Help
Lance, So in other words if I may to /hello/* I would be able to call my servelet with /hello? or the full URL http://localhost:8080/search/hello? I tried it did not work- requested resource (/hello) is not available. Thanks a lot, Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Sanjay, The servlet-mapping is a tag that allows you to map a specified pattern to the specified servlet. Don't get me started on the pattern syntax I still haven't taken the time to fully comprehend it. So basically what we told the server was that anytime it sees the pattern /hello/ in the context of this app send it to the HelloWorld servlet. The anything means anything you want to type after the /hello/ since we told it to match on the /hello/. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 9:01 AM To: Tomcat Users List Subject: RE: Servlet Deploy Problem Help Lance Thanks. What does servlet-mapping mean- is it directory structure or an alias to a servlet.I was trying to use /hello as an alias for the HelloWorld servlet and try calling it by /hello or by full URL /hello- am I completely off on this. and what is this anything? Thanks again servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/*/url-pattern /servlet-mapping Then you should be able to call it like: http://localhost:8080/search/hello/anything --- Lance Smith [EMAIL PROTECTED] wrote: In you're web.xml change: servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping to : servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/*/url-pattern /servlet-mapping Then you should be able to call it like: http://localhost:8080/search/hello/anything Hope this helps Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 8:21 AM To: [EMAIL PROTECTED] Subject: Servlet Deploy Problem Help I am just restarting this thread. My problem remains unsolved. I am running Tomcat4.01/NT. The setup should be OK as the examples run. I am trying to deploy the HelloWorldExample. My directory structure is- Tomcat4\webapps\search\WEB-INF\classes I have my .htm file in the \search directory and my class in the \classes and my web.xml in the \WEB-INF. My web.xml looks like this- I have used the example file to create it- servlet servlet-nameHelloWorld/servlet-name description HelloWorld /description servlet-classHelloWorldExample/servlet-class /servlet servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping Is this web.xml correct? I have not been able to execute my servelt any which way: /hello http://localhost:8080/search/servlet/HelloWorldExample http://localhost:8080/search/servlet/HelloWorld http://localhost:8080/search/HelloWorld I either get a resource not found or java.util.MissingResourceException: Can't find bundle for base name LocalStrings, locale en_US at java.util.ResourceBundle.throwMissingResourceException(ResourceBundle.java:7 07) at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:604) at java.util.ResourceBundle.getBundle(ResourceBundle.java:559) at HelloWorldExample.doGet(Unknown Source) My question is how do I exceute it- from the /search directory or from anywhere else using a full url path. Thanks a lot, Sanjay __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Servlet Deploy Problem Help
Randy, Yes that was the problem.Now when I give the complete path-http://localhost:8080/search/servlet/HelloWorldExample I can execute the class. But I still can not execute the class with: /hello or http://localhost:8080/search/HelloWorld or http://localhost:8080/search/servlet/HelloWorld Thanks very much again, Sanjay --- Randy Layman [EMAIL PROTECTED] wrote: Your problem isn't in the loaded classes (that would be a class not found). Instead look at where you are calling the method java.util.ResourceBundle.getBundle. The parameter you are passing in references a resource that Tomcat can't find. Randy -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 9:56 AM To: Tomcat Users List Subject: RE: Servlet Deploy Problem Help Thanks of the insight. The servlet is a HelloWorld example. The only imports in the class are: import java.io.*; import java.text.*; import java.util.*; import javax.servlet.*; import javax.servlet.http.*; I would easily suppose these should be available to Tomcat. If not what do I do. Thanks Sanjay --- Randy Layman [EMAIL PROTECTED] wrote: The stack trace you included indicates that you are running the servlet, but its throwing an exception. -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 9:21 AM To: [EMAIL PROTECTED] Subject: Servlet Deploy Problem Help I either get a resource not found or java.util.MissingResourceException: Can't find bundle for base name LocalStrings, locale en_US at java.util.ResourceBundle.throwMissingResourceException(Resourc eBundle.java:707) at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:604) at java.util.ResourceBundle.getBundle(ResourceBundle.java:559) at HelloWorldExample.doGet(Unknown Source) If your servlet wasn't being called then you wouldn't see it in the stack trace. I would suggest that you look at how you are loading resources in your servlet (they are probably not in the classpath). Randy -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: Servlet Deploy Problem Help
Lance - yes it works thanks a lot. But what are other shorter forms that I can use to call the servlet. I would hope to call it with like /search/hello. What has the /hello/* mapping bought me. Thanks Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: try http://localhost:8080/search/hello/HelloWorld let me know if this works. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 10:13 AM To: Tomcat Users List Subject: RE: Servlet Deploy Problem Help Lance, So in other words if I may to /hello/* I would be able to call my servelet with /hello? or the full URL http://localhost:8080/search/hello? I tried it did not work- requested resource (/hello) is not available. Thanks a lot, Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Sanjay, The servlet-mapping is a tag that allows you to map a specified pattern to the specified servlet. Don't get me started on the pattern syntax I still haven't taken the time to fully comprehend it. So basically what we told the server was that anytime it sees the pattern /hello/ in the context of this app send it to the HelloWorld servlet. The anything means anything you want to type after the /hello/ since we told it to match on the /hello/. Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 9:01 AM To: Tomcat Users List Subject: RE: Servlet Deploy Problem Help Lance Thanks. What does servlet-mapping mean- is it directory structure or an alias to a servlet.I was trying to use /hello as an alias for the HelloWorld servlet and try calling it by /hello or by full URL /hello- am I completely off on this. and what is this anything? Thanks again servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/*/url-pattern /servlet-mapping Then you should be able to call it like: http://localhost:8080/search/hello/anything --- Lance Smith [EMAIL PROTECTED] wrote: In you're web.xml change: servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping to : servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/*/url-pattern /servlet-mapping Then you should be able to call it like: http://localhost:8080/search/hello/anything Hope this helps Lance -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 8:21 AM To: [EMAIL PROTECTED] Subject: Servlet Deploy Problem Help I am just restarting this thread. My problem remains unsolved. I am running Tomcat4.01/NT. The setup should be OK as the examples run. I am trying to deploy the HelloWorldExample. My directory structure is- Tomcat4\webapps\search\WEB-INF\classes I have my .htm file in the \search directory and my class in the \classes and my web.xml in the \WEB-INF. My web.xml looks like this- I have used the example file to create it- servlet servlet-nameHelloWorld/servlet-name description HelloWorld /description servlet-classHelloWorldExample/servlet-class /servlet servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping Is this web.xml correct? I have not been able to execute my servelt any which way: /hello http://localhost:8080/search/servlet/HelloWorldExample http://localhost:8080/search/servlet/HelloWorld http://localhost:8080/search/HelloWorld I either get a resource not found or java.util.MissingResourceException: Can't find bundle for base name LocalStrings, locale en_US at java.util.ResourceBundle.throwMissingResourceException(ResourceBundle.java:7 07) at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:604) at java.util.ResourceBundle.getBundle(ResourceBundle.java:559) at HelloWorldExample.doGet(Unknown Source) My question is how do I exceute it- from the /search directory or from anywhere else using a full url path. Thanks a lot, Sanjay __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards. http://movies.yahoo.com
Tomact Servlet Deploy Problem Help
I installed Tomcat4.01/NT the examples run- webapps/servlets. I am trying to deploy my example it does not run. I have directory structure /webapps/search/Web-inf/classes. Under /search I have my html file hello.htm- td VALIGN=TOP WIDTH=30%a href=/helloimg SRC=/images/execute.gif HSPACE=4 BORDER=0 align=TOP/aa href=/servlet/HelloWorldExampleExecute/a/td I have my class in /classes. Under Web-inf I have my web.xml- servlet servlet-nameHelloWorld/servlet-name description HelloWorld /description servlet-classHelloWorldExample/servlet-class /servlet servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping When I run I get the error- The requested resource (/hello) is not available. The othet tag also fails. I have restarted etc Tomcat. Am I not doing something right? How do I turn on debugging/logging etc on the server. Thanks Sanjay __ Do You Yahoo!? Yahoo! Sports - live college hoops coverage http://sports.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: [Tomact Servlet Deploy Problem Help]
Kaikuo Luo, Thanks. Check my mail- I am doing all that. Is the name WEN-INF case sensitive? Sanjay --- Law Kaikuo [EMAIL PROTECTED] wrote: Hi Sanjay Bahal, Maybe you should create a subdirectory under WEN-INF called classes and put you java class there. You need to specify the fully qualified pathe for your servlet class in the web.xml file and set the mapping. Use the map name in any request. Kaikuo Luo Sanjay Bahal [EMAIL PROTECTED] wrote: I installed Tomcat4.01/NT the examples run- webapps/servlets. I am trying to deploy my example it does not run. I have directory structure /webapps/search/Web-inf/classes. Under /search I have my html file hello.htm- td VALIGN=TOP WIDTH=30%a href=/helloimg SRC=/images/execute.gif HSPACE=4 BORDER=0 align=TOP/aa href=/servlet/HelloWorldExampleExecute/a/td I have my class in /classes. Under Web-inf I have my web.xml- servlet servlet-nameHelloWorld/servlet-name description HelloWorld /description servlet-classHelloWorldExample/servlet-class /servlet servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping When I run I get the error- The requested resource (/hello) is not available. The othet tag also fails. I have restarted etc Tomcat. Am I not doing something right? How do I turn on debugging/logging etc on the server. Thanks Sanjay __ Do You Yahoo!? Yahoo! Sports - live college hoops coverage http://sports.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Sports - live college hoops coverage http://sports.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: [Tomact Servlet Deploy Problem Help]
Thanks Lance. I made it all caps- That took me a step further. Note to Windows(NT) users- windows shows the name in mixed case in explorer- even though you may type it in caps if you look at properties and DOS-NAME it will show the actual name- uppercase in this case. --- I got an error. This error was a servlet-mapping tag was not closed. I had used the sample web.xml for my web.xml and it had a comment with a servlet-mapping tag. I got rid of that. That brought me to my next error. The part of error that I could garb on the DOS screen is as below. How do I log the errors in a log file? at org.apache.catalina.startup.ContextConfig.applicationConfig(Unknown S ource) at org.apache.catalina.startup.ContextConfig.start(Unknown Source) at org.apache.catalina.startup.ContextConfig.lifecycleEvent(Unknown Sour ce) at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(Unknown Source) at org.apache.catalina.core.StandardContext.start(Unknown Source) at org.apache.catalina.core.ContainerBase.addChildInternal(Unknown Sourc e) at org.apache.catalina.core.ContainerBase.addChild(Unknown Source) at org.apache.catalina.core.StandardHost.addChild(Unknown Source) at org.apache.catalina.core.StandardHostDeployer.install(Unknown Source) at org.apache.catalina.core.StandardHost.install(Unknown Source) at org.apache.catalina.startup.HostConfig.deployDirectories(Unknown Sour ce) at org.apache.catalina.startup.HostConfig.deployApps(Unknown Source) at org.apache.catalina.startup.HostConfig.run(Unknown Source) at java.lang.Thread.run(Thread.java:484) [ERROR] Digester - -Parse Fatal Error at line 145 column 3: The content of eleme nts must consist of well-formed character data or markup. org.xml.sax.SAXParseE xception: The content of elements must consist of well-formed character data or markup. Thanks a lot, Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Yes it must be ALL capital letters. -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Wednesday, March 20, 2002 11:14 AM To: Tomcat Users List Subject: Re: [Tomact Servlet Deploy Problem Help] Kaikuo Luo, Thanks. Check my mail- I am doing all that. Is the name WEN-INF case sensitive? Sanjay --- Law Kaikuo [EMAIL PROTECTED] wrote: Hi Sanjay Bahal, Maybe you should create a subdirectory under WEN-INF called classes and put you java class there. You need to specify the fully qualified pathe for your servlet class in the web.xml file and set the mapping. Use the map name in any request. Kaikuo Luo Sanjay Bahal [EMAIL PROTECTED] wrote: I installed Tomcat4.01/NT the examples run- webapps/servlets. I am trying to deploy my example it does not run. I have directory structure /webapps/search/Web-inf/classes. Under /search I have my html file hello.htm- td VALIGN=TOP WIDTH=30%a href=/helloimg SRC=/images/execute.gif HSPACE=4 BORDER=0 align=TOP/aa href=/servlet/HelloWorldExampleExecute/a/td I have my class in /classes. Under Web-inf I have my web.xml- servlet servlet-nameHelloWorld/servlet-name description HelloWorld /description servlet-classHelloWorldExample/servlet-class /servlet servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping When I run I get the error- The requested resource (/hello) is not available. The othet tag also fails. I have restarted etc Tomcat. Am I not doing something right? How do I turn on debugging/logging etc on the server. Thanks Sanjay __ Do You Yahoo!? Yahoo! Sports - live college hoops coverage http://sports.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Sports - live college hoops coverage http://sports.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Sports - live college hoops coverage http://sports.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: [Tomact Servlet Deploy Problem Help]
I took care of this last error- some malform in the web.xml. Now I am back to square 1- my server starts but when I execute it gives error: 1. http://localhost:8080/servlet/HelloWorld The requested resource (/servlet/HelloWorld) is not available. 2. /hello The requested resource (/hello) is not available. Thanks a lot, Sanjay --- Sanjay Bahal [EMAIL PROTECTED] wrote: Thanks Lance. I made it all caps- That took me a step further. Note to Windows(NT) users- windows shows the name in mixed case in explorer- even though you may type it in caps if you look at properties and DOS-NAME it will show the actual name- uppercase in this case. --- I got an error. This error was a servlet-mapping tag was not closed. I had used the sample web.xml for my web.xml and it had a comment with a servlet-mapping tag. I got rid of that. That brought me to my next error. The part of error that I could garb on the DOS screen is as below. How do I log the errors in a log file? at org.apache.catalina.startup.ContextConfig.applicationConfig(Unknown S ource) at org.apache.catalina.startup.ContextConfig.start(Unknown Source) at org.apache.catalina.startup.ContextConfig.lifecycleEvent(Unknown Sour ce) at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(Unknown Source) at org.apache.catalina.core.StandardContext.start(Unknown Source) at org.apache.catalina.core.ContainerBase.addChildInternal(Unknown Sourc e) at org.apache.catalina.core.ContainerBase.addChild(Unknown Source) at org.apache.catalina.core.StandardHost.addChild(Unknown Source) at org.apache.catalina.core.StandardHostDeployer.install(Unknown Source) at org.apache.catalina.core.StandardHost.install(Unknown Source) at org.apache.catalina.startup.HostConfig.deployDirectories(Unknown Sour ce) at org.apache.catalina.startup.HostConfig.deployApps(Unknown Source) at org.apache.catalina.startup.HostConfig.run(Unknown Source) at java.lang.Thread.run(Thread.java:484) [ERROR] Digester - -Parse Fatal Error at line 145 column 3: The content of eleme nts must consist of well-formed character data or markup. org.xml.sax.SAXParseE xception: The content of elements must consist of well-formed character data or markup. Thanks a lot, Sanjay --- Lance Smith [EMAIL PROTECTED] wrote: Yes it must be ALL capital letters. -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Wednesday, March 20, 2002 11:14 AM To: Tomcat Users List Subject: Re: [Tomact Servlet Deploy Problem Help] Kaikuo Luo, Thanks. Check my mail- I am doing all that. Is the name WEN-INF case sensitive? Sanjay --- Law Kaikuo [EMAIL PROTECTED] wrote: Hi Sanjay Bahal, Maybe you should create a subdirectory under WEN-INF called classes and put you java class there. You need to specify the fully qualified pathe for your servlet class in the web.xml file and set the mapping. Use the map name in any request. Kaikuo Luo Sanjay Bahal [EMAIL PROTECTED] wrote: I installed Tomcat4.01/NT the examples run- webapps/servlets. I am trying to deploy my example it does not run. I have directory structure /webapps/search/Web-inf/classes. Under /search I have my html file hello.htm- td VALIGN=TOP WIDTH=30%a href=/helloimg SRC=/images/execute.gif HSPACE=4 BORDER=0 align=TOP/aa href=/servlet/HelloWorldExampleExecute/a/td I have my class in /classes. Under Web-inf I have my web.xml- servlet servlet-nameHelloWorld/servlet-name description HelloWorld /description servlet-classHelloWorldExample/servlet-class /servlet servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping When I run I get the error- The requested resource (/hello) is not available. The othet tag also fails. I have restarted etc Tomcat. Am I not doing something right? How do I turn on debugging/logging etc on the server. Thanks Sanjay __ Do You Yahoo!? Yahoo! Sports - live college hoops coverage http://sports.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! Sports - live college hoops coverage http://sports.yahoo.com/ -- To unsubscribe: mailto:[EMAIL PROTECTED
RE: [Tomact Servlet Deploy Problem Help]
I further tried using the tag- http://localhost:8080/search/servlet/HelloWorldExample This also errors out: java.util.MissingResourceException: Can't find bundle for base name LocalStrings, locale en_US at java.util.ResourceBundle.throwMissingResourceException(ResourceBundle.java:707) at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:604) at java.util.ResourceBundle.getBundle(ResourceBundle.java:559) at HelloWorldExample.doGet(Unknown Source) Thanks, Sanjay --- Sanjay Bahal [EMAIL PROTECTED] wrote: Thanks Charlie I tried both it did not work. My web.xml looks like this: servlet servlet-nameHelloWorld/servlet-name servlet-classHelloWorldExample/servlet-class /servlet servlet-mapping servlet-nameHelloWorld/servlet-name url-pattern/hello/url-pattern /servlet-mapping So I have mapped by class to a servlet and then mapped to urlpattern /hello. My understanding is (correct me) if I have html in the webapp/myapp/ directory I should be able to call with /hello or HelloWorld with a tag like- /hello or /HelloWorld. On the other hand if I try- http://localhost:8080/search/hello I get this error( search is myapp dir under webapps): java.util.MissingResourceException: Can't find bundle for base name LocalStrings, locale en_US at java.util.ResourceBundle.throwMissingResourceException(ResourceBundle.java:707) at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:604) at java.util.ResourceBundle.getBundle(ResourceBundle.java:559) at HelloWorldExample.doGet(Unknown Source) If I try http://localhost:8080/search/HelloWorld I get Resource not found error. Thanks a lot. Sanjay --- Cox, Charlie [EMAIL PROTECTED] wrote: -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Wednesday, March 20, 2002 1:28 PM To: Tomcat Users List Subject: RE: [Tomact Servlet Deploy Problem Help] I took care of this last error- some malform in the web.xml. Now I am back to square 1- my server starts but when I execute it gives error: 1. http://localhost:8080/servlet/HelloWorld The requested resource (/servlet/HelloWorld) is not available. try: http://localhost:8080/servlet/HelloWorldClass you need the actual class name here 2. /hello The requested resource (/hello) is not available. try: http://localhost:8080/hello/world This mapping means that anything in the 'hello' directory should go to the servlet. Thanks a lot, Sanjay --- Sanjay Bahal [EMAIL PROTECTED] wrote: Thanks Lance. I made it all caps- That took me a step further. Note to Windows(NT) users- windows shows the name in mixed case in explorer- even though you may type it in caps if you look at properties and DOS-NAME it will show the actual name- uppercase in this case. --- I got an error. This error was a servlet-mapping tag was not closed. I had used the sample web.xml for my web.xml and it had a comment with a servlet-mapping tag. I got rid of that. That brought me to my next error. The part of error that I could garb on the DOS screen is as below. How do I log the errors in a log file? at org.apache.catalina.startup.ContextConfig.applicationConfig(Unknown S ource) at org.apache.catalina.startup.ContextConfig.start(Unknown Source) at org.apache.catalina.startup.ContextConfig.lifecycleEvent(Unknown Sour ce) at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(Unknown Source) at org.apache.catalina.core.StandardContext.start(Unknown Source) at org.apache.catalina.core.ContainerBase.addChildInternal(Unknown Sourc e) at org.apache.catalina.core.ContainerBase.addChild(Unknown Source) at org.apache.catalina.core.StandardHost.addChild(Unknown Source) at org.apache.catalina.core.StandardHostDeployer.install(Unknown Source) at org.apache.catalina.core.StandardHost.install(Unknown Source) at org.apache.catalina.startup.HostConfig.deployDirectories(Unknown Sour ce) at org.apache.catalina.startup.HostConfig.deployApps(Unknown Source) at org.apache.catalina.startup.HostConfig.run(Unknown Source) at java.lang.Thread.run(Thread.java:484) [ERROR] Digester - -Parse Fatal Error at line 145 column 3: The content of eleme nts must consist of well-formed character data or markup. org.xml.sax.SAXParseE xception: The content of elements must consist === message truncated === __ Do
Re: STARTING TOMCAT
if you http to it then tomact page should show:
http://loclahost:8080/
HTH
--- Daliso Zuze [EMAIL PROTECTED] wrote:
Thanks Avi,
what exactly should it show if tomcat is running?
Daliso
- Original Message -
From: Avi Green [EMAIL PROTECTED]
To: Tomcat Users List
[EMAIL PROTECTED]
Sent: Friday, November 30, 2001 3:20 AM
Subject: Re: STARTING TOMCAT
IS THERE ANY CONFIRMATION THAT YOU CAN GET THAT
TOMCAT IS ACTUALLY
RUNNING APART FROM TRYING http://localhost:8080
1. Check ps
$ ps aguwwx |grep -i tomcat
2. Check netstat
$ netstat -elpt
==
= Avi Green :-) avi at sputnik7.com (-: 212
320-3735 =
Unix SysAdmin System Specialist
=
http://www.sputnik7.com - chronic online
entertainment
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http://www.epitonic.com - Hi Quality Free MP3
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http://www.we-deliver.tv - Log on, order in,
smoke out
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RE: CLASSPATH for web apps - and the answer is?
Larry, You are right. It was the files in the jre/ext. I do not when I had ever put them there- but I removed them and now everything works like a charm. Thanks a lot, Sanjay --- Larry Isaacs [EMAIL PROTECTED] wrote: I think the sealing violation means that a class was loaded from a sealed jar and another class that is in this jar was found and loaded from some other jar, violating the sealing. The error also seems related XML. The only jar I am aware of are certain versions of crimson.jar, I'm not sure which. The crimson.jar in lib\container of Tomcat 3.3 is not sealed. Again, I am assuming you CLASSPATH doesn't matter because the unmodified tomcat.bat ignores it. I am also assuming you haven't added any jars to Tomcat 3.3's lib directories. This only leaves the jre/lib/ext jars as the source of additional jars. Does this directory contain any jars? Cheers, Larry P.S. Concerning your CLASSPATH setting, rt.jar isn't in C:\jdk1.3\lib, it's in C:\jdk1.3\jre\lib. However, it shouldn't be necessary to have rt.jar in CLASSPATH. (Note: A pre-release version of Tomcat 3.3 needed it if you were using Jikes to compile JSP files.) The JDK (or JRE) will include this jar in the boot classloader automatically. The boot classloader takes prioritly over the CLASSPATH classloader, so having it in CLASSPATH has no effect. -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Thursday, November 29, 2001 9:39 AM To: Tomcat Users List Subject: RE: CLASSPATH for web apps - and the answer is? Larry, Thanks. The /ext should be the same as I it is the same version of jdk1.3. But another symptom on my win98 m/c is I get this very same error: java.lang.SecurityException: sealing violation at java.net.URLClassLoader.defineClass(URLClassLoader.java:234) even outside of tomcat - say when I try to open a URL? I simply can't figure it out. I perhaps would try re-installing the jdk. TIA Sanjay --- Larry Isaacs [EMAIL PROTECTED] wrote: I think you will be better off if we can get Tomcat 3.3 working on your Win98 machine. I will therefore assume that your CLASSPATH setting is irrelavent to to problem. What do you have in the C:\jdk1.3\jre\lib\ext directory? Any differences between the jars in your Win98 jre\lib\ext and the Win2k jre\lib\ext. If you have jars in the jre\lib\ext directory, you might try moving them to a temporary location and then try starting Tomcat 3.3 on Win98 to see what happens. Cheers, Larry -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Wednesday, November 28, 2001 9:22 PM To: Tomcat Users List Subject: RE: CLASSPATH for web apps - and the answer is? Larry, I tried it- it did not work. I could not even get the log file: In tomcat 3.2 and tomact 3.3 I set the logging- but it does not write to the log Logger name=tc_log path=logs/tomcat.log verbosityLevel = DEBUG / In 3.2 I get this error trying to run tomcat: FATAL: configuration error java.lang.SecurityException: sealing violation at java.net.URLClassLoader.defineClass(URLClassLoader.java:234) at java.net.URLClassLoader.access$100(URLClassLoader.java:56) at java.net.URLClassLoader$1.run(URLClassLoader.java:195) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:297) at java.lang.ClassLoader.loadClass(ClassLoader.java:253) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:313) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:120) at javax.xml.parsers.SAXParserFactory.newInstance(SAXParserFactor y.java:92) at org.apache.tomcat.util.xml.XmlMapper.readXml(XmlMapper.java:210) at org.apache.tomcat.startup.Tomcat.execute(Tomcat.java:187) at org.apache.tomcat.startup.Tomcat.main(Tomcat.java:235) On 3.3 I can not grab the error. My system classpath is: CLASSPATH=.;c:\jdk1.3\lib\rt.jar;c:\xerces\xerces.jar; c:\soap\lib\soap.jar;c:\wstk\uddi4j\lib\uddi4j.jar; c:\wstk\wsdl4j\lib\wsdl4j.jar;c:\wstk\lib\wstk.jar; c:\wstk\lib\xss4j.jar; c:\wstk\soap\lib\mail.jar; c:\wstk\soap\lib\activation.jar;c:\webservices\classes; c:\jsse\lib\jcert.jar; c:\jsse\lib\jnet.jar; c:\jsse\lib\jsse.jar;c:\axis\lib\axis.jar;c:\axis\lib\log4j-gump.jar; === message truncated === __ Do You Yahoo!? Yahoo
RE: CLASSPATH for web apps - and the answer is?
Larry, Thanks. The /ext should be the same as I it is the same version of jdk1.3. But another symptom on my win98 m/c is I get this very same error: java.lang.SecurityException: sealing violation at java.net.URLClassLoader.defineClass(URLClassLoader.java:234) even outside of tomcat - say when I try to open a URL? I simply can't figure it out. I perhaps would try re-installing the jdk. TIA Sanjay --- Larry Isaacs [EMAIL PROTECTED] wrote: I think you will be better off if we can get Tomcat 3.3 working on your Win98 machine. I will therefore assume that your CLASSPATH setting is irrelavent to to problem. What do you have in the C:\jdk1.3\jre\lib\ext directory? Any differences between the jars in your Win98 jre\lib\ext and the Win2k jre\lib\ext. If you have jars in the jre\lib\ext directory, you might try moving them to a temporary location and then try starting Tomcat 3.3 on Win98 to see what happens. Cheers, Larry -Original Message- From: Sanjay Bahal [mailto:[EMAIL PROTECTED]] Sent: Wednesday, November 28, 2001 9:22 PM To: Tomcat Users List Subject: RE: CLASSPATH for web apps - and the answer is? Larry, I tried it- it did not work. I could not even get the log file: In tomcat 3.2 and tomact 3.3 I set the logging- but it does not write to the log Logger name=tc_log path=logs/tomcat.log verbosityLevel = DEBUG / In 3.2 I get this error trying to run tomcat: FATAL: configuration error java.lang.SecurityException: sealing violation at java.net.URLClassLoader.defineClass(URLClassLoader.java:234) at java.net.URLClassLoader.access$100(URLClassLoader.java:56) at java.net.URLClassLoader$1.run(URLClassLoader.java:195) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:297) at java.lang.ClassLoader.loadClass(ClassLoader.java:253) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:313) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:120) at javax.xml.parsers.SAXParserFactory.newInstance(SAXParserFactor y.java:92) at org.apache.tomcat.util.xml.XmlMapper.readXml(XmlMapper.java:210) at org.apache.tomcat.startup.Tomcat.execute(Tomcat.java:187) at org.apache.tomcat.startup.Tomcat.main(Tomcat.java:235) On 3.3 I can not grab the error. My system classpath is: CLASSPATH=.;c:\jdk1.3\lib\rt.jar;c:\xerces\xerces.jar; c:\soap\lib\soap.jar;c:\wstk\uddi4j\lib\uddi4j.jar; c:\wstk\wsdl4j\lib\wsdl4j.jar;c:\wstk\lib\wstk.jar; c:\wstk\lib\xss4j.jar; c:\wstk\soap\lib\mail.jar; c:\wstk\soap\lib\activation.jar;c:\webservices\classes; c:\jsse\lib\jcert.jar; c:\jsse\lib\jnet.jar; c:\jsse\lib\jsse.jar;c:\axis\lib\axis.jar;c:\axis\lib\log4j-gump.jar; I have not made any change the tomcat.bat file in 3.2 or 3.3. When I try the same thing on my win2000 machine everything works great. There seems to be somethng funky with win98. TIA Sanjay --- Larry Isaacs [EMAIL PROTECTED] wrote: Is the tomcat.bat unmodified? Note that in its unmodified state, it contains: set CLASSPATH=%TOMCAT_INSTALL%\lib\tomcat.jar which replaces any CLASSPATH setting in your environment (your CLASSPATH setting is saved and restored however). The recommended procedure for adding classes to Tomcat 3.3 is documented at: http://jakarta.apache.org/tomcat/tomcat-3.3-doc/tomcat-ug.htm l#configuring_classes The stacktrace isn't complete and doesn't show the error. In server.xml, you can add: path=logs/tomcat.log to the LogSetter name=tc_log ... / entry to capture Tomcat's log output in a file. Hopefully the stack trace will appear in the tomcat.log file. Cheers, Larry -Original Message- From: Sanjay bahal [mailto:[EMAIL PROTECTED]] Sent: Wednesday, November 28, 2001 12:01 AM To: Tomcat Users List Subject: RE: CLASSPATH for web apps - and the answer is? Larry, I am on win98, jdk1.3, Tomcat3.3. I have my TOMCAT_HOME and JAVA_HOME setup. My st\ystem classpath is: CLASSPATH=.;c:\jdk1.3\lib\rt.jar;c:\xerces\xerces.jar; c:\soap\lib\soap.jar;c:\wstk\uddi4j\lib\uddi4j.jar; c:\wstk\wsdl4j\lib\wsdl4j.jar;c:\wstk\lib\wstk.jar;c:\w stk\lib\xss4j.jar;c:\wstk\soap\lib\mail.jar;c:\wstk\soap\lib\a ctivation.jar;c:\webservices\classes; c:\jsse\lib\jcert.jar;c:\jsse\lib\jnet.jar;c:\jsse\lib\jsse.ja r;c:\axis\lib\axis.jar; Note: I removed jaxp, parser, crimso.jar from the classpath. I run tomcat c:\tomcat run The error I get is: [this is the best I can grab
Re: STARTING TOMCAT
It is at the bottom of evry mail. S --- Saran Shalini [EMAIL PROTECTED] wrote: How do I unsubscibe this service ?? - Original Message - From: David Smith [EMAIL PROTECTED] To: Tomcat Users List [EMAIL PROTECTED] Sent: Thursday, November 29, 2001 12:59 PM Subject: Re: STARTING TOMCAT Number one place to take a look is catalina.out in the $CATALINA_HOME/logs directory. If the TC is failing on start, it'll show there. --David On Thursday 29 November 2001 11:46 am, you wrote: IS THERE ANY CONFIRMATION THAT YOU CAN GET THAT TOMCAT IS ACTUALLY RUNNING APART FROM TRYING http://localhost:8080 I've tried starting up tomcat on SuSE linx 6.2, everything seemed alright but no response on localhost:8080, I don't know what to try next? What should I be looking for in the log file? Daliso Zuze University of Namibia +264 81 248 4931 -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! GeoCities - quick and easy web site hosting, just $8.95/month. http://geocities.yahoo.com/ps/info1 -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: CLASSPATH for web apps - and the answer is?
Larry, I tried it- it did not work. I could not even get the log file: In tomcat 3.2 and tomact 3.3 I set the logging- but it does not write to the log Logger name=tc_log path=logs/tomcat.log verbosityLevel = DEBUG / In 3.2 I get this error trying to run tomcat: FATAL: configuration error java.lang.SecurityException: sealing violation at java.net.URLClassLoader.defineClass(URLClassLoader.java:234) at java.net.URLClassLoader.access$100(URLClassLoader.java:56) at java.net.URLClassLoader$1.run(URLClassLoader.java:195) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:297) at java.lang.ClassLoader.loadClass(ClassLoader.java:253) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:313) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:120) at javax.xml.parsers.SAXParserFactory.newInstance(SAXParserFactory.java:92) at org.apache.tomcat.util.xml.XmlMapper.readXml(XmlMapper.java:210) at org.apache.tomcat.startup.Tomcat.execute(Tomcat.java:187) at org.apache.tomcat.startup.Tomcat.main(Tomcat.java:235) On 3.3 I can not grab the error. My system classpath is: CLASSPATH=.;c:\jdk1.3\lib\rt.jar;c:\xerces\xerces.jar; c:\soap\lib\soap.jar;c:\wstk\uddi4j\lib\uddi4j.jar; c:\wstk\wsdl4j\lib\wsdl4j.jar;c:\wstk\lib\wstk.jar; c:\wstk\lib\xss4j.jar; c:\wstk\soap\lib\mail.jar; c:\wstk\soap\lib\activation.jar;c:\webservices\classes; c:\jsse\lib\jcert.jar; c:\jsse\lib\jnet.jar; c:\jsse\lib\jsse.jar;c:\axis\lib\axis.jar;c:\axis\lib\log4j-gump.jar; I have not made any change the tomcat.bat file in 3.2 or 3.3. When I try the same thing on my win2000 machine everything works great. There seems to be somethng funky with win98. TIA Sanjay --- Larry Isaacs [EMAIL PROTECTED] wrote: Is the tomcat.bat unmodified? Note that in its unmodified state, it contains: set CLASSPATH=%TOMCAT_INSTALL%\lib\tomcat.jar which replaces any CLASSPATH setting in your environment (your CLASSPATH setting is saved and restored however). The recommended procedure for adding classes to Tomcat 3.3 is documented at: http://jakarta.apache.org/tomcat/tomcat-3.3-doc/tomcat-ug.html#configuring_classes The stacktrace isn't complete and doesn't show the error. In server.xml, you can add: path=logs/tomcat.log to the LogSetter name=tc_log ... / entry to capture Tomcat's log output in a file. Hopefully the stack trace will appear in the tomcat.log file. Cheers, Larry -Original Message- From: Sanjay bahal [mailto:[EMAIL PROTECTED]] Sent: Wednesday, November 28, 2001 12:01 AM To: Tomcat Users List Subject: RE: CLASSPATH for web apps - and the answer is? Larry, I am on win98, jdk1.3, Tomcat3.3. I have my TOMCAT_HOME and JAVA_HOME setup. My st\ystem classpath is: CLASSPATH=.;c:\jdk1.3\lib\rt.jar;c:\xerces\xerces.jar; c:\soap\lib\soap.jar;c:\wstk\uddi4j\lib\uddi4j.jar; c:\wstk\wsdl4j\lib\wsdl4j.jar;c:\wstk\lib\wstk.jar;c:\w stk\lib\xss4j.jar;c:\wstk\soap\lib\mail.jar;c:\wstk\soap\lib\a ctivation.jar;c:\webservices\classes; c:\jsse\lib\jcert.jar;c:\jsse\lib\jnet.jar;c:\jsse\lib\jsse.ja r;c:\axis\lib\axis.jar; Note: I removed jaxp, parser, crimso.jar from the classpath. I run tomcat c:\tomcat run The error I get is: [this is the best I can grab from the DOS window]- at org.apache.tomcat.util.compat.Jdk12Support.doPrivileged(Unknown Source) at org.apache.tomcat.startup.EmbededTomcat.execute(Unknown Source) at java.lang.reflect.Method.invoke(Native Method) at org.apache.tomcat.util.IntrospectionUtils.execute(Unknown Source) at org.apache.tomcat.startup.Main.execute(Unknown Source) at org.apache.tomcat.startup.Main.main(Unknown Source) Guessed home=C:\tomcat java.lang.reflect.InvocationTargetException: org.apache.tomcat.core.TomcatExcept ion: EmbededTomcat.initContextManager at org.apache.tomcat.startup.EmbededTomcat.initContextManager(Unknown Source) at org.apache.tomcat.startup.EmbededTomcat.execute1(Unknown Source) at org.apache.tomcat.startup.EmbededTomcat$1.run(Unknown Source) at org.apache.tomcat.util.compat.Jdk12Support$PrivilegedProxy.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at org.apache.tomcat.util.compat.Jdk12Support.doPrivileged(Unknown Source) at org.apache.tomcat.startup.EmbededTomcat.execute(Unknown Source) at java.lang.reflect.Method.invoke(Native Method) at org.apache.tomcat.util.IntrospectionUtils.execute(Unknown Source) at org.apache.tomcat.startup.Main.execute(Unknown Source
RE: CLASSPATH for web apps - and the answer is?
Larry, I can not even bring Tomcat 3.3 up ( not even 3.2). So are you saying with 3.3 could use xalan and xerces only- And I do not need crimson, jaxp, parser? Thanks a lot, Sanjay --- Larry Isaacs [EMAIL PROTECTED] wrote: If you are adding 2.2-D13 xalan.jar in Tomcat 3.2.3, you will probably need to replace the jaxp.jar and parser.jar with the v1.4.3 xerces.jar. For Tomcat 3.3 you could update the v2.1.0 xalan.jar and replace crimson.jar with xerces.jar. If you can use Tomcat 3.3 instead of Tomcat 3.2.3, I would recommend doing so. There are classloading issues that can be addressed in 3.3, which can't in 3.2.x. I could offer more help if I knew your error and some simple steps to reproduce your problem. Cheers, Larry -Original Message- From: Ian Bruseker [mailto:[EMAIL PROTECTED]] Sent: Monday, November 26, 2001 7:52 PM To: [EMAIL PROTECTED] Subject: CLASSPATH for web apps - and the answer is? Greetings. I'm new to this list. Go easy on me. :-) Last Monday, Roland Berger posted a message to this list titled CLASSPATH for web apps (I found his posting in the web archive at mikal.org). In his email he asks why Tomcat 3.2.3 is not loading up log4j.jar from his WEB-INF/lib directory, and comments on how un-Jakarta-like it would be to have to hardcode a classpath for ever web app in the startup script. I am having the same problem (the only difference is the jar Tomcat isn't loading for me is xalan.jar (from Xalan-J 2.2-D13), not log4j.jar). I've tried both 3.2.3 and 3.2.4, with slightly different error message but the same basic, bad result. 3.3 failed too, but that's probably because TOMCAT_HOME$/lib seems to have much more importance and organization now, and I just don't get it yet (besides, I'm not really looking to upgrade just yet). I'm sure whatever the answer to his message was will be the same answer I require. Unfortunately, at this moment the web archive for this list stops at November 19th (the day his message was posted), so if there were any replies to it, the archive isn't providing them for me. I really require an answer soon (rather than waiting for the archives to get updated) so I can move on with my work. Could someone help me out here? Thank you. Ian. -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] __ Do You Yahoo!? Yahoo! GeoCities - quick and easy web site hosting, just $8.95/month. http://geocities.yahoo.com/ps/info1 -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: CLASSPATH for web apps - and the answer is?
Larry, I am on win98, jdk1.3, Tomcat3.3. I have my TOMCAT_HOME and JAVA_HOME setup. My st\ystem classpath is: CLASSPATH=.;c:\jdk1.3\lib\rt.jar;c:\xerces\xerces.jar; c:\soap\lib\soap.jar;c:\wstk\uddi4j\lib\uddi4j.jar; c:\wstk\wsdl4j\lib\wsdl4j.jar;c:\wstk\lib\wstk.jar;c:\w stk\lib\xss4j.jar;c:\wstk\soap\lib\mail.jar;c:\wstk\soap\lib\activation.jar;c:\webservices\classes; c:\jsse\lib\jcert.jar;c:\jsse\lib\jnet.jar;c:\jsse\lib\jsse.jar;c:\axis\lib\axis.jar; Note: I removed jaxp, parser, crimso.jar from the classpath. I run tomcat c:\tomcat run The error I get is: [this is the best I can grab from the DOS window]- at org.apache.tomcat.util.compat.Jdk12Support.doPrivileged(Unknown Source) at org.apache.tomcat.startup.EmbededTomcat.execute(Unknown Source) at java.lang.reflect.Method.invoke(Native Method) at org.apache.tomcat.util.IntrospectionUtils.execute(Unknown Source) at org.apache.tomcat.startup.Main.execute(Unknown Source) at org.apache.tomcat.startup.Main.main(Unknown Source) Guessed home=C:\tomcat java.lang.reflect.InvocationTargetException: org.apache.tomcat.core.TomcatExcept ion: EmbededTomcat.initContextManager at org.apache.tomcat.startup.EmbededTomcat.initContextManager(Unknown Source) at org.apache.tomcat.startup.EmbededTomcat.execute1(Unknown Source) at org.apache.tomcat.startup.EmbededTomcat$1.run(Unknown Source) at org.apache.tomcat.util.compat.Jdk12Support$PrivilegedProxy.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at org.apache.tomcat.util.compat.Jdk12Support.doPrivileged(Unknown Source) at org.apache.tomcat.startup.EmbededTomcat.execute(Unknown Source) at java.lang.reflect.Method.invoke(Native Method) at org.apache.tomcat.util.IntrospectionUtils.execute(Unknown Source) at org.apache.tomcat.startup.Main.execute(Unknown Source) at org.apache.tomcat.startup.Main.main(Unknown Source) Thanks a lot, Sanjay --- Larry Isaacs [EMAIL PROTECTED] wrote: I can't claim to be up to date with the latest state of Xerces, Xalan, and Jaxp, so there may be new issues that I'm not aware of with respect to combinations of Xerces, Xalan, etc. The fundamental problem in Tomcat 3.2.x is that: 1) The web server classes, including Jasper, live on the CLASSPATH. 2) I believe it is Jasper that requires an XML parser, so an XML parser has to exist on the CLASSPATH too. 3) Because Tomcat 3.2 uses the Java 2 sequence of classloader searching (as does Tomcat 3.3), classes found on the CLASSPATH take precedence over classes local to the web applications. Thus, all web applications are forced to use the XML parser on the CLASSPATH. Jasper doesn't care which XML parser. So you can upgrade the Jaxp 1.0.1 version (jaxp.jar + parser.jar) to crimson.jar (the current version has the jaxp.jar classes included) or xerces.jar depending on your other requirements. However, if you have two web applications that want different versions of XML parser, you are stuck. Tomcat 3.3 avoids forcing a single XML parser on all the web applications by building a more complicated classloader hierarchy which hides most of the server and Jasper classes from the web applications. A side effect of this is that adding classes and jars is more complicated than simply adding them to the CLASSPATH. This is why the tomcat.sh/tomcat.bat script ignores your CLASSPATH setting since that is all too often the wrong place to add them. Adding classes for Tomcat 3.3 is documented here: http://jakarta.apache.org/tomcat/tomcat-3.3-doc/tomcat-ug.html#configuring_classes If this doesn't help, please describe the error you are seeing and how you have changed the default Tomcat 3.3 configuration. Cheers, Larry -Original Message- From: Sanjay bahal [mailto:[EMAIL PROTECTED]] Sent: Tuesday, November 27, 2001 2:35 PM To: Tomcat Users List Subject: RE: CLASSPATH for web apps - and the answer is? Larry, I can not even bring Tomcat 3.3 up ( not even 3.2). So are you saying with 3.3 could use xalan and xerces only- And I do not need crimson, jaxp, parser? Thanks a lot, Sanjay --- Larry Isaacs [EMAIL PROTECTED] wrote: If you are adding 2.2-D13 xalan.jar in Tomcat 3.2.3, you will probably need to replace the jaxp.jar and parser.jar with the v1.4.3 xerces.jar. For Tomcat 3.3 you could update the v2.1.0 xalan.jar and replace crimson.jar with xerces.jar. If you can use Tomcat 3.3 instead of Tomcat 3.2.3, I would recommend doing so. There are classloading issues that can be addressed in 3.3, which can't in 3.2.x. I could offer more help if I knew your error and some simple steps to reproduce your problem. Cheers, Larry -Original Message- From: Ian Bruseker [mailto:[EMAIL
Installing/Running Tomact
Hi, I can not seem to be able to run Tomact. I have tried Tomact_3_2, Tomact_3_3, Tomact_4_01.nothing works. Is it really so difficult? On : 3_2 I used to get the sealing violation error- I tried the various sugestions on the site- nothing worked. On 3_3 I can not even grab the error msg. On 4_01 I get an error- I can not grab the error msg- My system classpath is: CLASSPATH=.;c:\jdk1.3\lib\rt.jar;c:\xerces\xerces.jar;c:\soap\lib\soap.jar;c:\xml\jaxp.jar;c:\xml\parser.jar;c:\xml\xalan.jar;c:\wstk\uddi4j\lib\uddi4j.jar;c:\wstk\wsdli4j\lib\wsdl4j.jar;c:\wstk\lib\wstk.jar;c:\wstk\lib\xss4j.jar;c:\wstk\soap\lib\mail.jar;c:\wstk\soap\lib\activation.jar;c:\webservices\classes;c:\jsse\lib\jcert.jar;c:\jsse\lib\jnet.jar;c:\jsse\lib\jsse.jar;c:\axis\lib\axis.jar; do we need all the xml parser files- I have jaxp, parser, xalan, xerces? I g\have tried adding and removing files and cahnging the order etc- Nothing seems to work. I am on win98, jdk1.3 Thanks a lot guys, Sanjay __ Do You Yahoo!? Yahoo! GeoCities - quick and easy web site hosting, just $8.95/month. http://geocities.yahoo.com/ps/info1 -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Sealing violation Error
I get this Sealing violation error not only when I try to run tomcat but also when I try to execute a class: My Class Path is - C:\xerces\xerces.jar;C:\soap\lib\soap.jar;C:\wstk\wsdl4j\lib\wsdl4j.jar;C:\wstk\uddi4j\lib\uddi4j.jar;C:\wstk\lib\soapenc.jar;C:\wstk\lib\wstk.jar;C:\wstk\lib\xalan.jar;C:\wstk\lib \xss4j.jar;C:\jsse\lib\jsse.jar;C:\jsse\lib\jnet.jar;C:\jsse\lib\jcert.jar;C:\wstk\soap\lib\pop3.jar;C:\wstk\soap\lib\mail.jar;C:\wstk\soap\lib\mailapi.jar;C:\wstk\soap\lib\activat ion.jar;C:\wstk\soap\lib\smtp.jar;C:\soap\SOAPEnv\SOAPEnvelope.jar;c:\webservices\classes;.;C:\jsdk2 .1\server.jar;C:\jsdk2 .1\servlet.jar; c:\ant\lib\ant.jar;C:\Kawa4.1\kawaclasses.zip;c:\jdk1.3\lib\tools.jar;c:\jdk1.3\jre\lib\rt.jar;c:\jdk1.3\jre\lib\i18n.jar I get the error: java.lang.SecurityException: sealing violation at java.net.URLClassLoader.defineClass(URLClassLoader.java:234) at java.net.URLClassLoader.access$100(URLClassLoader.java:56) at java.net.URLClassLoader$1.run(URLClassLoader.java:195) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:297) at java.lang.ClassLoader.loadClass(ClassLoader.java:253) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:313) at org.apache.crimson.jaxp.DocumentBuilderFactoryImpl.newDocumentBuilder(DocumentBuilderFactoryImpl.java:88) at com.ibm.uddi.client.UDDIProxy.send(UDDIProxy.java:1180) at com.ibm.uddi.client.UDDIProxy.find_business(UDDIProxy.java:192) at tutorial.UDDI1.main(UDDI1.java:78) java.lang.NullPointerException at com.ibm.uddi.request.FindBusiness.saveToXML(FindBusiness.java:194) at com.ibm.uddi.client.UDDIProxy.send(UDDIProxy.java:1186) at com.ibm.uddi.client.UDDIProxy.find_business(UDDIProxy.java:192) at tutorial.UDDI1.main(UDDI1.java:78) Exception in thread main Process Exit... When I try to run Tomcat: C:\ tomcat run FATAL: configuration error java.lang.SecurityException: sealing violation at java.net.URLClassLoader.defineClass(URLClassLoader.java:234) at java.net.URLClassLoader.access$100(URLClassLoader.java:56) at java.net.URLClassLoader$1.run(URLClassLoader.java:195) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:297) at java.lang.ClassLoader.loadClass(ClassLoader.java:253) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:313) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:120) at javax.xml.parsers.SAXParserFactory.newInstance(SAXParserFactory.java:92) at org.apache.tomcat.util.xml.XmlMapper.readXml(XmlMapper.java:210) at org.apache.tomcat.startup.Tomcat.execute(Tomcat.java:187) at org.apache.tomcat.startup.Tomcat.main(Tomcat.java:235) Tomcat classpath is: CLASSPATH=.;c:\jdk1.3\lib\rt.jar;jswdk-1.0.1\lib\jspengine.jar;C:\jsdk2 .1\server.jar;C:\jsdk2 .1\servlet.jar; c:\ant\lib\ant.jar;c:\xerces\xerces.jar;c:\soap\lib\soap.jar;c:\wstk\uddi4j\lib\uddi4j.jar;c:\wstk\wsdli4j\lib\wsdl4j.jar;c:\wstk\lib\wstk.jar;;c:\wstk\lib\xss4j.jar;c:\wstk\soap\l ib\smtp.jar;c:\wstk\soap\lib\mail.jar;c:\wstk\soap\lib\smtp.jar;c:\wstk\soap\lib\mailapi.jar;c:\wstk\soap\lib\activation.jar;c:\webservices\classes;c:\jsse\lib\jcert.jar;c:\jsse\li b\jnet.jar;c:\jsse\lib\jsse.jar;c:\tomcat\classes;c:\tomcat\lib\SERVLET.JAR;c:\tomcat\lib\PARSER.JAR;c:\tomcat\lib\JAXP.JAR;c:\tomcat\lib\ANT.JAR;c:\tomcat\lib\WEBSER~1.JAR;c:\tomc at\lib\JASPER.JAR;C:\jdk1.3\lib\tools.jar I am using tomcat_3_2,soap_2_2,jdk1.3 on Windows 98. I have tried palying with the Tomact configuration using Sun's Xml files instead of Tomact's etc but no success. Thanks all, Sanjay __ Do You Yahoo!? Find the one for you at Yahoo! Personals http://personals.yahoo.com -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
