AW: How can I get the location of the webapps-directory?
Hi, with getServletContext() I get only the name of my running web-application; with getServerInfo() I get Apache Tomcat/4.0.3. But I don't get any directory name... Frank -Ursprüngliche Nachricht- Von: Scott Purcell [mailto:[EMAIL PROTECTED]] Gesendet am: Montag, 22. April 2002 18:32 An: Tomcat Users List Betreff: RE: How can I get the location of the webapps-directory? I think it is servletContext now. Check out the j2ee for servletContext that may be what you are looking for. my o'reilly book shows public String ServletContext.getServerInfo() if that don't fly, I can dig deeper, just yell Scott -Original Message- From: Eichfelder, Frank [mailto:[EMAIL PROTECTED]] Sent: Monday, April 22, 2002 9:15 AM To: [EMAIL PROTECTED] Subject: AW: How can I get the location of the webapps-directory? Hi, thanks for the reply, but I need the webapps-directory to read the existent subdirectories and/or war-files in order to make a list of all deployed web-applications. (In older versions of the Servlet-API, there was a method called getServletNames(), which is deprecated now and returns null) Does anybody have another suggestion? Thanks, Frank -Ursprüngliche Nachricht- Von: Rajesh Nair [mailto:[EMAIL PROTECTED]] Gesendet am: Montag, 22. April 2002 06:42 An: [EMAIL PROTECTED] Betreff: Re: How can I get the location of the webapps-directory? Hi I think u can try getContextPath() which will give u the root of ur web application .To get access to resources inside WAR or other archive files u can use the method getResource(String URIPath); If the context is in a different m/c u can use getContext() to get the context first and then use either getResource() or getResourceAsStream() methods *** REPLY SEPARATOR *** On 4/19/02 at 3:22 PM Eichfelder, Frank wrote: Hi, how can I get the location from the webapps-directory on my filesystem? It's easy, if I use String path = getServletContext().getRealPath(/); and then cut off the last part: int index = path.lastIndexOf(System.getProperty(file.separator), path.length()-2 ); path = path.substring(0, index); But this works only, if you have your webapplication unpacked in the file-system or if you have set unpackWars=true. Now, I have set unpackWars=false, and now I get null for getServletContext().getRealPath(/). Is there any possibility to get the name of the war-File an application is stored in or the name of the directory the war-file is stored in? Thanks, Frank -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: AW: How can I get the location of the webapps-directory?
Look at the method getRealPath() of class ServletContext. Erwin Am Dienstag, 23. April 2002 13:41 schrieben Sie: Hi, with getServletContext() I get only the name of my running web-application; with getServerInfo() I get Apache Tomcat/4.0.3. But I don't get any directory name... Frank -Ursprüngliche Nachricht- Von: Scott Purcell [mailto:[EMAIL PROTECTED]] Gesendet am: Montag, 22. April 2002 18:32 An: Tomcat Users List Betreff: RE: How can I get the location of the webapps-directory? I think it is servletContext now. Check out the j2ee for servletContext that may be what you are looking for. my o'reilly book shows public String ServletContext.getServerInfo() if that don't fly, I can dig deeper, just yell Scott -Original Message- From: Eichfelder, Frank [mailto:[EMAIL PROTECTED]] Sent: Monday, April 22, 2002 9:15 AM To: [EMAIL PROTECTED] Subject: AW: How can I get the location of the webapps-directory? Hi, thanks for the reply, but I need the webapps-directory to read the existent subdirectories and/or war-files in order to make a list of all deployed web-applications. (In older versions of the Servlet-API, there was a method called getServletNames(), which is deprecated now and returns null) Does anybody have another suggestion? Thanks, Frank -Ursprüngliche Nachricht- Von: Rajesh Nair [mailto:[EMAIL PROTECTED]] Gesendet am: Montag, 22. April 2002 06:42 An: [EMAIL PROTECTED] Betreff: Re: How can I get the location of the webapps-directory? Hi I think u can try getContextPath() which will give u the root of ur web application .To get access to resources inside WAR or other archive files u can use the method getResource(String URIPath); If the context is in a different m/c u can use getContext() to get the context first and then use either getResource() or getResourceAsStream() methods *** REPLY SEPARATOR *** On 4/19/02 at 3:22 PM Eichfelder, Frank wrote: Hi, how can I get the location from the webapps-directory on my filesystem? It's easy, if I use String path = getServletContext().getRealPath(/); and then cut off the last part: int index = path.lastIndexOf(System.getProperty(file.separator), path.length()-2 ); path = path.substring(0, index); But this works only, if you have your webapplication unpacked in the file-system or if you have set unpackWars=true. Now, I have set unpackWars=false, and now I get null for getServletContext().getRealPath(/). Is there any possibility to get the name of the war-File an application is stored in or the name of the directory the war-file is stored in? Thanks, Frank -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
AW: How can I get the location of the webapps-directory?
Hi, thanks for the reply, but I need the webapps-directory to read the existent subdirectories and/or war-files in order to make a list of all deployed web-applications. (In older versions of the Servlet-API, there was a method called getServletNames(), which is deprecated now and returns null) Does anybody have another suggestion? Thanks, Frank -Ursprüngliche Nachricht- Von: Rajesh Nair [mailto:[EMAIL PROTECTED]] Gesendet am: Montag, 22. April 2002 06:42 An: [EMAIL PROTECTED] Betreff: Re: How can I get the location of the webapps-directory? Hi I think u can try getContextPath() which will give u the root of ur web application .To get access to resources inside WAR or other archive files u can use the method getResource(String URIPath); If the context is in a different m/c u can use getContext() to get the context first and then use either getResource() or getResourceAsStream() methods *** REPLY SEPARATOR *** On 4/19/02 at 3:22 PM Eichfelder, Frank wrote: Hi, how can I get the location from the webapps-directory on my filesystem? It's easy, if I use String path = getServletContext().getRealPath(/); and then cut off the last part: int index = path.lastIndexOf(System.getProperty(file.separator), path.length()-2 ); path = path.substring(0, index); But this works only, if you have your webapplication unpacked in the file-system or if you have set unpackWars=true. Now, I have set unpackWars=false, and now I get null for getServletContext().getRealPath(/). Is there any possibility to get the name of the war-File an application is stored in or the name of the directory the war-file is stored in? Thanks, Frank -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
