RE: I post a text XML with Microsoft.XMLHTTP to servlet

2003-10-15 Thread Shapira, Yoav 

Howdy,
You should be able to test this using either MockObjects or Cactus,
before sending it to your clients ;)

Yoav Shapira
Millennium ChemInformatics


-Original Message-
From: Blackmore, John [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 14, 2003 2:01 PM
To: 'Tomcat Users List'
Subject: RE: I post a text XML with Microsoft.XMLHTTP to servlet

Sorry, I was mistaken - what little content was there was actually
another
form element which didn't belong. Looks like my XMLHTTP test app was
the
problem. I think I have it working with my second approach below,
however I
won't know for sure until the client tests it. Needless to say, they
expect it to work right the first time (sigh).

Thanks for the quick responses!

John

-Original Message-
From: Shapira, Yoav [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 14, 2003 9:24 AM
To: Tomcat Users List
Subject: RE: I post a text XML with Microsoft.XMLHTTP to servlet



Howdy,

Second, I tried to forcibly retrieve characters from the input stream,
one
by one.

  String xmlDocString = getXMLString((InputStream)
req.getInputStream());
  Document document = builder.parse(new
StringBufferInputStream(xmlDocString));

Note: the getXMLString() function is not very interesting... simply
has
a
loop as follows:

  while( (c=xmlInputStream.read())  0 )

When I try this, I get the same error, however I don't get an empty
string
-
xmlDocString has what looks like a URL encoded and truncated version
of
the
original string.

This is the approach I had in mind.  Then URL-decode it
(URLDecoder.decode(...)).  Why is it truncated?

Yoav Shapira



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Re: I post a text XML with Microsoft.XMLHTTP to servlet

2003-10-14 Thread Blackmore, John 
Hi,
I have the same problem. Can you elaborate on the ..., ie how to extract
the XML string from the request? I've tried a few different methods without
success. I'm running Tomcat 4.1.24-LE-jdk14 on Solaris. I have a servlet
that clients post XML to. One client uses XMLHTTP object to do the post, and
that's the one that's causing problems. All other clients are fine. I'd like
to post the two approaches I've tried to resolve this, then maybe someone
can tell me what I'm doing wrong or how to work around this? 

First, the simple, obvious approach - simply build a document from the input
stream:

DocumentBuilder builder =
DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document document = builder.parse(req.getInputStream());

When I try this, I get org.xml.sax.SAXParseException: Content is not
allowed in prolog. 

Second, I tried to forcibly retrieve characters from the input stream, one
by one.  

String xmlDocString = getXMLString((InputStream)
req.getInputStream());
Document document = builder.parse(new
StringBufferInputStream(xmlDocString));

Note: the getXMLString() function is not very interesting... simply has a
loop as follows:

while( (c=xmlInputStream.read())  0 ) 

When I try this, I get the same error, however I don't get an empty string -
xmlDocString has what looks like a URL encoded and truncated version of the
original string. 

I would really appreciate any insight as to why this happens, even if a
solution is not forthcoming. Thanks!

John Blackmore

-
Howdy,
You need to read the whole request into a String.  Then, since you want
a DOM document, use a DOM document builder to get it, e.g.
String xmlInput = ...
Reader reader = new Stringeader(xmlInput);
InputSource inputSource = new InputSource(reader);
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(inputSource)

(The above are mixed imports from java.io, javax.xml.parsers,
org.w3c.dom).

Yoav Shapira
Millennium ChemInformatics


-Original Message-
From: Jose Alanya [mailto:[EMAIL PROTECTED]
Sent: Thursday, October 09, 2003 6:21 PM
To: [EMAIL PROTECTED]
Subject: I post a text XML with Microsoft.XMLHTTP to servlet

Hi,

I post a text XML with  Microsoft.XMLHTTP to servlet,
As I can recover the value of object request from of servlet
This can :
something like  :  Document oDocument = xml.paser(objrequest)

Not getparameter, not getquerystring

Please  help me!
Thanks,

best regards,
Jose Alanya
From, Lima Peru





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RE: I post a text XML with Microsoft.XMLHTTP to servlet

2003-10-14 Thread Shapira, Yoav 

Howdy,

Second, I tried to forcibly retrieve characters from the input stream,
one
by one.

   String xmlDocString = getXMLString((InputStream)
req.getInputStream());
   Document document = builder.parse(new
StringBufferInputStream(xmlDocString));

Note: the getXMLString() function is not very interesting... simply has
a
loop as follows:

   while( (c=xmlInputStream.read())  0 )

When I try this, I get the same error, however I don't get an empty
string
-
xmlDocString has what looks like a URL encoded and truncated version of
the
original string.

This is the approach I had in mind.  Then URL-decode it
(URLDecoder.decode(...)).  Why is it truncated?

Yoav Shapira



This e-mail, including any attachments, is a confidential business communication, and 
may contain information that is confidential, proprietary and/or privileged.  This 
e-mail is intended only for the individual(s) to whom it is addressed, and may not be 
saved, copied, printed, disclosed or used by anyone else.  If you are not the(an) 
intended recipient, please immediately delete this e-mail from your computer system 
and notify the sender.  Thank you.


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RE: I post a text XML with Microsoft.XMLHTTP to servlet

2003-10-14 Thread erlis 
Try to call your XML in the internet explorer and see if that xml have
no errors..

It seems like the xml isn't well formed...

Sincerely
Erlis Vidal Santos

 -Original Message-
 From: Blackmore, John [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, October 14, 2003 9:22 AM
 To: '[EMAIL PROTECTED]'
 Subject: Re: I post a text XML with Microsoft.XMLHTTP to servlet
 
 Hi,
 I have the same problem. Can you elaborate on the ..., ie how to
extract
 the XML string from the request? I've tried a few different methods
 without
 success. I'm running Tomcat 4.1.24-LE-jdk14 on Solaris. I have a
servlet
 that clients post XML to. One client uses XMLHTTP object to do the
post,
 and
 that's the one that's causing problems. All other clients are fine.
I'd
 like
 to post the two approaches I've tried to resolve this, then maybe
someone
 can tell me what I'm doing wrong or how to work around this?
 
 First, the simple, obvious approach - simply build a document from the
 input
 stream:
 
   DocumentBuilder builder =
 DocumentBuilderFactory.newInstance().newDocumentBuilder();
   Document document = builder.parse(req.getInputStream());
 
 When I try this, I get org.xml.sax.SAXParseException: Content is not
 allowed in prolog.
 
 Second, I tried to forcibly retrieve characters from the input stream,
one
 by one.
 
   String xmlDocString = getXMLString((InputStream)
 req.getInputStream());
   Document document = builder.parse(new
 StringBufferInputStream(xmlDocString));
 
 Note: the getXMLString() function is not very interesting... simply
has a
 loop as follows:
 
   while( (c=xmlInputStream.read())  0 )
 
 When I try this, I get the same error, however I don't get an empty
string
 -
 xmlDocString has what looks like a URL encoded and truncated version
of
 the
 original string.
 
 I would really appreciate any insight as to why this happens, even if
a
 solution is not forthcoming. Thanks!
 
 John Blackmore
 
 -
 Howdy,
 You need to read the whole request into a String.  Then, since you
want
 a DOM document, use a DOM document builder to get it, e.g.
 String xmlInput = ...
 Reader reader = new Stringeader(xmlInput);
 InputSource inputSource = new InputSource(reader);
 DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
 DocumentBuilder db = dbf.newDocumentBuilder();
 Document doc = db.parse(inputSource)
 
 (The above are mixed imports from java.io, javax.xml.parsers,
 org.w3c.dom).
 
 Yoav Shapira
 Millennium ChemInformatics
 
 
 -Original Message-
 From: Jose Alanya [mailto:[EMAIL PROTECTED]
 Sent: Thursday, October 09, 2003 6:21 PM
 To: [EMAIL PROTECTED]
 Subject: I post a text XML with Microsoft.XMLHTTP to servlet
 
 Hi,
 
 I post a text XML with  Microsoft.XMLHTTP to servlet,
 As I can recover the value of object request from of servlet
 This can :
 something like  :  Document oDocument = xml.paser(objrequest)
 
 Not getparameter, not getquerystring
 
 Please  help me!
 Thanks,
 
 best regards,
 Jose Alanya
 From, Lima Peru
 
 
 
 
 


**
 This e-mail and any files transmitted with it may contain privileged
or
 confidential information. It is solely for use by the individual for
whom
 it is intended, even if addressed incorrectly. If you received this
e-mail
 in error, please notify the sender; do not disclose, copy, distribute,
or
 take any action in reliance on the contents of this information; and
 delete
 it from your system. Any other use of this e-mail is prohibited. Thank
you
 for your compliance.
 
 
 
 
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 To unsubscribe, e-mail: [EMAIL PROTECTED]
 For additional commands, e-mail: [EMAIL PROTECTED]


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RE: I post a text XML with Microsoft.XMLHTTP to servlet

2003-10-14 Thread Blackmore, John 
Sorry, I was mistaken - what little content was there was actually another
form element which didn't belong. Looks like my XMLHTTP test app was the
problem. I think I have it working with my second approach below, however I
won't know for sure until the client tests it. Needless to say, they
expect it to work right the first time (sigh). 

Thanks for the quick responses!

John

-Original Message-
From: Shapira, Yoav [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 14, 2003 9:24 AM
To: Tomcat Users List
Subject: RE: I post a text XML with Microsoft.XMLHTTP to servlet



Howdy,

Second, I tried to forcibly retrieve characters from the input stream,
one
by one.

   String xmlDocString = getXMLString((InputStream)
req.getInputStream());
   Document document = builder.parse(new
StringBufferInputStream(xmlDocString));

Note: the getXMLString() function is not very interesting... simply has
a
loop as follows:

   while( (c=xmlInputStream.read())  0 )

When I try this, I get the same error, however I don't get an empty
string
-
xmlDocString has what looks like a URL encoded and truncated version of
the
original string.

This is the approach I had in mind.  Then URL-decode it
(URLDecoder.decode(...)).  Why is it truncated?

Yoav Shapira



** 
This e-mail and any files transmitted with it may contain privileged or 
confidential information. It is solely for use by the individual for whom 
it is intended, even if addressed incorrectly. If you received this e-mail 
in error, please notify the sender; do not disclose, copy, distribute, or 
take any action in reliance on the contents of this information; and delete 
it from your system. Any other use of this e-mail is prohibited. Thank you 
for your compliance.




-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]

RE: I post a text XML with Microsoft.XMLHTTP to servlet

2003-10-10 Thread Shapira, Yoav 

Howdy,
You need to read the whole request into a String.  Then, since you want
a DOM document, use a DOM document builder to get it, e.g.
String xmlInput = ...
Reader reader = new Stringeader(xmlInput);
InputSource inputSource = new InputSource(reader);
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(inputSource)

(The above are mixed imports from java.io, javax.xml.parsers,
org.w3c.dom).

Yoav Shapira
Millennium ChemInformatics


-Original Message-
From: Jose Alanya [mailto:[EMAIL PROTECTED]
Sent: Thursday, October 09, 2003 6:21 PM
To: [EMAIL PROTECTED]
Subject: I post a text XML with Microsoft.XMLHTTP to servlet

Hi,

I post a text XML with  Microsoft.XMLHTTP to servlet,
As I can recover the value of object request from of servlet
This can :
something like  :  Document oDocument = xml.paser(objrequest)

Not getparameter, not getquerystring

Please  help me!
Thanks,

best regards,
Jose Alanya
From, Lima Peru



This e-mail, including any attachments, is a confidential business communication, and 
may contain information that is confidential, proprietary and/or privileged.  This 
e-mail is intended only for the individual(s) to whom it is addressed, and may not be 
saved, copied, printed, disclosed or used by anyone else.  If you are not the(an) 
intended recipient, please immediately delete this e-mail from your computer system 
and notify the sender.  Thank you.


-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]