Whats wrong with this code?

2002-06-10 Thread Juan 

This piece of code don't work if the '@' is not found:

  String em = usuario.getEmail();
  int p = em.indexOf('@');
  out.println(Integer.toString(p));

if the '@' is within the string, it works well. Why?

Thanks in advance,

Juan José Velázquez Garcia
Web Development
www.htmlspider.com.br



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RE: Whats wrong with this code?

2002-06-10 Thread Chris Campbell 


That part of the code looks ok. I suspect it is something after that which
gives you the problem - what else do you do with p? Remember indexOf returns
-1 if the substring is not found. This means that if you then use p to try
checking the name of the email like:

String namePart = em.substring(0, p); 

you will get an IndexOutOfBoundsException.

ChrisC


 This piece of code don't work if the '@' is not found:
 
   String em = usuario.getEmail();
   int p = em.indexOf('@');
   out.println(Integer.toString(p));
 
 if the '@' is within the string, it works well. Why?

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Re: Whats wrong with this code?

2002-06-10 Thread August Detlefsen 

What error are you getting? 



--- Juan [EMAIL PROTECTED] wrote:
 This piece of code don't work if the '@' is not found:
 
   String em = usuario.getEmail();
   int p = em.indexOf('@');
   out.println(Integer.toString(p));
 
 if the '@' is within the string, it works well. Why?
 
 Thanks in advance,
 
 Juan José Velázquez Garcia
 Web Development
 www.htmlspider.com.br
 
 
 
 --
 To unsubscribe, e-mail:  
 mailto:[EMAIL PROTECTED]
 For additional commands, e-mail:
 mailto:[EMAIL PROTECTED]
 


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