are
you looking for a number...... because there may be something else. check for
num....... then remove the third place ie
if
num[1,3] then print else error
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]On Behalf Of Marco Manyevere
Sent: Sunday, February 01, 2004 8:14 PM
To: [EMAIL PROTECTED]
Subject: The result of VARIABLE[1,3] + 0Hi All,What is the correct interpratation ofA = '0010000'B = A[1,3] + 0PRINT BOn UV 9.6 I get 0010 contrary to my expectation of 1. What is the logical explanation of this. Does UV use '+' for string concatenation as well? Then why doesnt '123' + '456' result in '123456' (I get a runtime error)?Regards,Marco
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