Re: Dynamic clay in a datatable

[Gary VanMatre]

From: Daniel del Río [EMAIL PROTECTED] 

 Hello, I know similar questions was made in the past but I haven't found 
 a response. I'm trying to render an HTML that depends of the current 
 datatable row value, but the result is that all render the same page: 
 
This is the code:


t:dataTable value=#{home.banners} var=c
   t:column
clay:clay id=prueba jsfid=WDynamicClay managedBeanName=c
   c:symbol name=page 
value=[EMAIL PROTECTED]/
   /clay:clay
   /t:column
/t:dataTable


And WDynamicClay is an xml component definition:


component jsfid=WDynamicClay extends=clay
 attributes
set name=clayJsfid value=@page/
/attributes
/component

 
 The managedBeanName's attribute jsfid returns a different clay html 
 template 
 but always the last template is rendered. 
 I tried other alternatives but always with identical result: 
 

Unfortunately, you can not use Clay this way in a dataTable.  A data table is a 
UIData component.  These types of components implement the flyweight pattern.  
One set of component definitions for a column is applied to each row as the 
model as it is iterated over.  For this to work, the clay component would need 
to rebuild the subtree for each row.  I'm pretty sure that only one attempt to 
find the clay config beans that build the subtree is made.  The subtree creates 
first class components that are added to the component tree under the clay 
component (children).  A dynamic subtree in a datatable would most likely cause 
all kinds of problems with state saving too.
   

 - Using a ShapeValidator 
 - Create a JSF component that adds a clay component 
 - Extending the Clay component 
 
 Thanks in advance. 
 Daniel del Río. 
 

Gary

Re: Dynamic clay in a datatable

[Ryan Wynn]

Could you try first this more direct way and see what happens?


t:dataTable value=#{home.banners} var=c
   t:column
   clay:clay id=prueba jsfid=#{c.jsfid}/clay:clay
   /t:column
/t:dataTable


Not sure that the symbol tag is being evaluated in time to be
available for the clay component.

I have not used clay's jsp tags but have done something like this
before with html templates.

Ryan




On Jan 18, 2008 1:46 PM, Daniel del Río [EMAIL PROTECTED] wrote:
 Hello, I know similar questions was made in the past but I haven't found
 a response. I'm trying to render an HTML that depends of the current
 datatable row value,  but the result is that all render the same page:

 This is the code:

 
 t:dataTable value=#{home.banners} var=c
 t:column
 clay:clay id=prueba jsfid=WDynamicClay 
 managedBeanName=c
 c:symbol name=page value=[EMAIL PROTECTED]/
 /clay:clay
 /t:column
 /t:dataTable
 

 And WDynamicClay is an xml component definition:

 
 component jsfid=WDynamicClay extends=clay
 attributes
 set name=clayJsfid value=@page/
 /attributes
 /component
 

 The managedBeanName's attribute jsfid returns a different clay html 
 template but always the last template is rendered.
 I tried other alternatives but always with identical result:

 - Using a ShapeValidator
 - Create a JSF component that adds a clay component
 - Extending the Clay component

 Thanks in advance.
 Daniel del Río.

Dynamic clay in a datatable

[Daniel del Río]

Hello, I know similar questions was made in the past but I haven't found
a response. I'm trying to render an HTML that depends of the current
datatable row value,  but the result is that all render the same page:

This is the code:


t:dataTable value=#{home.banners} var=c
t:column
clay:clay id=prueba jsfid=WDynamicClay managedBeanName=c
c:symbol name=page value=[EMAIL PROTECTED]/
/clay:clay
/t:column
/t:dataTable


And WDynamicClay is an xml component definition:


component jsfid=WDynamicClay extends=clay
attributes
set name=clayJsfid value=@page/
/attributes
/component


The managedBeanName's attribute jsfid returns a different clay html template 
but always the last template is rendered. 
I tried other alternatives but always with identical result:

- Using a ShapeValidator
- Create a JSF component that adds a clay component
- Extending the Clay component

Thanks in advance.
Daniel del Río.