Re: Converting Apache log string into map using delimiter

2014-11-11 Thread YaoPau
OK I got it working with:

z.map(row = (row.map(element = element.split(=)(0)) zip row.map(element
= element.split(=)(1))).toMap)

But I'm guessing there is a more efficient way than to create two separate
lists and then zip them together and then convert the result into a map.



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Re: Converting Apache log string into map using delimiter

2014-11-11 Thread Sean Owen
I think it would be faster/more compact as:

z.map(_.map { element =
val tokens = element.split(=)
(tokens(0), tokens(1))
  }.toMap)

(That's probably 95% right but I didn't compile or test it.)

On Wed, Nov 12, 2014 at 12:18 AM, YaoPau jonrgr...@gmail.com wrote:

 OK I got it working with:

 z.map(row = (row.map(element = element.split(=)(0)) zip row.map(element
 = element.split(=)(1))).toMap)

 But I'm guessing there is a more efficient way than to create two separate
 lists and then zip them together and then convert the result into a map.



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