Re: Internationalization: dynamic message for feedback Panel
I just happened to be in that part of my code , so here goes :
MapString, String map = new HashMapString, String();
map.put(username, user.getDisplayName);
MapModelString, String values = new MapModelString, String(map);
String message = getLocalizer().getString(deleteConfirm, values);
etc...
--
Eugene
On 03 Dec 2010, at 8:01 AM, Ernesto Reinaldo Barreiro wrote:
What do you want to use instead? A map? I think it will also work with
a map: map.put(name, Bla Bla). If not I think old Java style
properties are also supported (thought I'm not 100% sure)
property = The user {0} will be deleted. Proceed?
and then passing an array of Object.
Ernesto
On Fri, Dec 3, 2010 at 1:47 PM, sap2000 sap2...@indiatimes.com wrote:
ok. thank you.
but is there any way when you don't have a bean?
- Shantanu
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Re: Internationalization: dynamic message for feedback Panel
I just happened to be in that part of my code , so here goes :
MapString, String map = new HashMapString, String();
map.put(username, user.getDisplayName);
MapModelString, String values = new MapModelString, String(map);
String message = getLocalizer().getString(deleteConfirm, values);
etc...
--
Eugene
On 03 Dec 2010, at 8:01 AM, Ernesto Reinaldo Barreiro wrote:
What do you want to use instead? A map? I think it will also work with
a map: map.put(name, Bla Bla). If not I think old Java style
properties are also supported (thought I'm not 100% sure)
property = The user {0} will be deleted. Proceed?
and then passing an array of Object.
Ernesto
On Fri, Dec 3, 2010 at 1:47 PM, sap2000 sap2...@indiatimes.com wrote:
ok. thank you.
but is there any way when you don't have a bean?
- Shantanu
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Re: IMarkupResourceStreamProvider for ListView
You might want to check that you are adding your components in the correct
place, hierarchically speaking...
I always forget to add elements to the item like so...
protected abstract void populateItem(final ListItemT item){
item.add(new Component(...)); -- correct
add(new Component(...)); --- WRONG
I imagine getMarkupResourceStream is not called because one of the validations
that check the tree of components failed.
--
Eugene
On 03 Dec 2010, at 9:36 AM, alex shubert wrote:
Hello
I got the following error trying to provide custom render for ListView
WicketMessage: The component(s) below failed to render. A common problem is
that you have added a component in code but forgot to reference it in the
markup (thus the component will never be rendered).
New class signature is
private abstract class EnumListViewT extends ListViewT implements
IMarkupResourceStreamProvider
I was sure getMarkupResourceStream will be called then EnumListView is
to be added to a page.
But it never happens, debug pointer never suspends execution at this point.
What may be wrong? (except my English ofc)
--
Best regards
Alex
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Re: IMarkupResourceStreamProvider for ListView
Alex, please ignore me listen to Martin. My english reading skills need
improving :-)
On 03 Dec 2010, at 9:47 AM, Eugene Malan wrote:
You might want to check that you are adding your components in the correct
place, hierarchically speaking...
I always forget to add elements to the item like so...
protected abstract void populateItem(final ListItemT item){
item.add(new Component(...)); -- correct
add(new Component(...)); --- WRONG
I imagine getMarkupResourceStream is not called because one of the
validations that check the tree of components failed.
--
Eugene
On 03 Dec 2010, at 9:36 AM, alex shubert wrote:
Hello
I got the following error trying to provide custom render for ListView
WicketMessage: The component(s) below failed to render. A common problem
is that you have added a component in code but forgot to reference it in
the markup (thus the component will never be rendered).
New class signature is
private abstract class EnumListViewT extends ListViewT implements
IMarkupResourceStreamProvider
I was sure getMarkupResourceStream will be called then EnumListView is
to be added to a page.
But it never happens, debug pointer never suspends execution at this point.
What may be wrong? (except my English ofc)
--
Best regards
Alex
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Re: wicket question
I took a look at the site and I have started implementing something similar. I use a normal non-wicket form on the home page that posts to my mounted wicket page with the login form on it. I mounted my login registration page to memberRegistration form method=post action=memberRegistration label for=userUser/label input id=user type=text name=user label for=pwdPassword/label input id=pwd type=password name=pwd input class=button value=Log in type=submit /form http://croptrak.emalan.com/Home -- Eugene On 01 Dec 2010, at 11:23 AM, 96silvia wrote: I have this wicket form I want to use wicket to pass the phone number and contact email. wicket:extend form wicket:id=test method=post action=http://www.mypage.com; input type=hidden wicket:id =phoneNumber name=phoneNumber input type=hidden wicket:id =contactEmail name=email /form /wicket:extend my question is my java code passes the correct parameters for the phone number and the contact email. but overwrites the form action and places wicket:interface=:10:opcForward::IFormSubmitListener:: I don't want this to happen I need to post these values to www.mypage.com is there a way to do this? I am using wicket 1.4.5, jdk6 -- View this message in context: http://apache-wicket.1842946.n4.nabble.com/wicket-question-tp3067609p3067609.html Sent from the Users forum mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: wicket question
I see your problem... In my case I am posting from a simple form (no validation or pre-populated values) that just needs to pass the parameters to my wicket form on a secure page. So.. it is back to your main question, how to stop the wicket form from posting to itself, but to get it to post to different url. You could try something suggested by Igor http://apache-wicket.1842946.n4.nabble.com/RelativePathPrefixHandler-and-form-quot-action-quot-attributes-td1867803.html override oncomponenttag() of the form and call super followed by tag.put(action, whateverurl); -igor - On 01 Dec 2010, at 12:26 PM, 96silvia wrote: the problem is the hidden input values are coming from a wicket session. so if I use a non wicket form how do I get the values from a wicket session to the non wicket form? -- View this message in context: http://apache-wicket.1842946.n4.nabble.com/wicket-question-tp3067609p3067719.html Sent from the Users forum mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: component .... not found on page
cresc,
Make sure you do not have any broken links in your header section,
like the one I had.
link rel=shortcut icon href= type=images/x-icon /
It is broken because there is a space in the rel= part of it.
Also make sure you do not have empty image src img src=/ (per :
Thomas Kappler )
You could also add a debug points to check if you are getting page
reloads (This was my problem). So if you see the debug twice when
there should only be one --- then you know the page is reloading.
@Override
protected void onBeforeRender() {
log.debug(Page is being rendered: + getPage());
super.onBeforeRender();
}
Good luck...
--
Eugene
On 02 Feb 2010, at 8:45 PM, cresc wrote:
I am sorry, I did not understand the solution. I searched for
quickstart in
jira issue but found one link which says to use patch
https://issues.apache.org/jira/secure/attachment/12417508/WICKET-2404-1.4.patch
So I modified my html tag in homepage to
html
xmlns:wicket=http://wicket.apache.org/dtds.data/wicket-xhtml1.4-strict.dtd
But still not resovled..
Can you give me more details...
- cresc
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Re: component .... not found on page
I am wrestling with the same Exception. I think I am doing something
similar, in that I have a DataView with a link to a detail Page and
then I return to the list page usingsetResponsePage(returnPage);
Different browsers react differently. On my Mac...
Chrome: gives the Exception on first load of the page.
Safari: gives Exception after a few renderings of the Page.
Firefox: Cannot re-create the Exception.
What browser are you using?
In my instance it is a Link that cannot be found
item.add(new LinkEntry(entryName, new ModelEntry(entry)){
@Override
public void onClick() {
setResponsePage(new OBOEntryViewPage(entry, getPage()));
}
@Override
protected void onComponentTagBody(MarkupStream markupStream,
ComponentTag openTag) {
replaceComponentTagBody(markupStream, openTag,
getModelObject().getName());
}
});
On 02 Feb 2010, at 9:57 AM, cresc wrote:
Forgot to copy the error message.
Root cause:
org.apache.wicket.WicketRuntimeException: component
content-panel:table-container:table-content:tcontainer:list:
1:viewDetail not
found on page com.mypackage.ordertracking.client.TrackingHomePage[id
= 3],
listener interface = [RequestListenerInterface name=IBehaviorListener,
method=public abstract void
org.apache.wicket.behavior.IBehaviorListener.onRequest()]
at
org
.apache
.wicket
.request
.AbstractRequestCycleProcessor
.resolveListenerInterfaceTarget(AbstractRequestCycleProcessor.java:
426)
at
org
.apache
.wicket
.request
.AbstractRequestCycleProcessor
.resolveRenderedPage(AbstractRequestCycleProcessor.java:471)
at
org
.apache
.wicket
.protocol
.http.WebRequestCycleProcessor.resolve(WebRequestCycleProcessor.java:
144)
at org.apache.wicket.RequestCycle.step(RequestCycle.java:1310)
at org.apache.wicket.RequestCycle.steps(RequestCycle.java:1428)
at org.apache.wicket.RequestCycle.request(RequestCycle.java:545)
So
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Re: component .... not found on page
I get the same behavior in 1.4.4 1.4.5 1.4.6
On 02 Feb 2010, at 12:20 PM, Riyad Kalla wrote:
What version of Wicket?
On Tue, Feb 2, 2010 at 10:11 AM, Eugene Malan eug...@emalan.com
wrote:
I am wrestling with the same Exception. I think I am doing something
similar, in that I have a DataView with a link to a detail Page and
then I
return to the list page usingsetResponsePage(returnPage);
Different browsers react differently. On my Mac...
Chrome: gives the Exception on first load of the page.
Safari: gives Exception after a few renderings of the Page.
Firefox: Cannot re-create the Exception.
What browser are you using?
In my instance it is a Link that cannot be found
item.add(new LinkEntry(entryName, new ModelEntry(entry)){
@Override
public void onClick() {
setResponsePage(new OBOEntryViewPage(entry,
getPage()));
}
@Override
protected void onComponentTagBody(MarkupStream markupStream,
ComponentTag openTag) {
replaceComponentTagBody(markupStream, openTag,
getModelObject().getName());
}
});
On 02 Feb 2010, at 9:57 AM, cresc wrote:
Forgot to copy the error message.
Root cause:
org.apache.wicket.WicketRuntimeException: component
content-panel:table-container:table-content:tcontainer:list:
1:viewDetail
not
found on page
com.mypackage.ordertracking.client.TrackingHomePage[id = 3],
listener interface = [RequestListenerInterface
name=IBehaviorListener,
method=public abstract void
org.apache.wicket.behavior.IBehaviorListener.onRequest()]
at
org
.apache
.wicket
.request
.AbstractRequestCycleProcessor
.resolveListenerInterfaceTarget(AbstractRequestCycleProcessor.java:
426)
at
org
.apache
.wicket
.request
.AbstractRequestCycleProcessor
.resolveRenderedPage(AbstractRequestCycleProcessor.java:471)
at
org
.apache
.wicket
.protocol
.http
.WebRequestCycleProcessor.resolve(WebRequestCycleProcessor.java:144)
at org.apache.wicket.RequestCycle.step(RequestCycle.java:1310)
at org.apache.wicket.RequestCycle.steps(RequestCycle.java:1428)
at org.apache.wicket.RequestCycle.request(RequestCycle.java:545)
So
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Re: component .... not found on page
Of course the quickstart worked just fine, so I had to add the layers
of junk back on to find out where it was going wrong.
Eventually the last thing I added back on was the cause a broken
link in the head section.
link rel=shortcut icon href= type=images/x-icon /
Lesson : Make sure you have valid html. It can manifest itself in non-
obvious ways...
--
Eugene
PS To the Core Wicket devs --- Thanks for your hard-work, you make
people like me look good as we churn out features quickly.
On 02 Feb 2010, at 1:02 PM, Igor Vaynberg wrote:
jira issue, quickstart...
-igor
On Tue, Feb 2, 2010 at 9:31 AM, Eugene Malan eug...@emalan.com
wrote:
I get the same behavior in 1.4.4 1.4.5 1.4.6
On 02 Feb 2010, at 12:20 PM, Riyad Kalla wrote:
What version of Wicket?
On Tue, Feb 2, 2010 at 10:11 AM, Eugene Malan eug...@emalan.com
wrote:
I am wrestling with the same Exception. I think I am doing
something
similar, in that I have a DataView with a link to a detail Page
and then
I
return to the list page usingsetResponsePage(returnPage);
Different browsers react differently. On my Mac...
Chrome: gives the Exception on first load of the page.
Safari: gives Exception after a few renderings of the Page.
Firefox: Cannot re-create the Exception.
What browser are you using?
In my instance it is a Link that cannot be found
item.add(new LinkEntry(entryName, new ModelEntry(entry)){
@Override
public void onClick() {
setResponsePage(new OBOEntryViewPage(entry,
getPage()));
}
@Override
protected void onComponentTagBody(MarkupStream markupStream,
ComponentTag openTag) {
replaceComponentTagBody(markupStream, openTag,
getModelObject().getName());
}
});
On 02 Feb 2010, at 9:57 AM, cresc wrote:
Forgot to copy the error message.
Root cause:
org.apache.wicket.WicketRuntimeException: component
content-panel:table-container:table-content:tcontainer:list:
1:viewDetail
not
found on page
com.mypackage.ordertracking.client.TrackingHomePage[id =
3],
listener interface = [RequestListenerInterface
name=IBehaviorListener,
method=public abstract void
org.apache.wicket.behavior.IBehaviorListener.onRequest()]
at
org
.apache
.wicket
.request
.AbstractRequestCycleProcessor
.resolveListenerInterfaceTarget
(AbstractRequestCycleProcessor.java:426)
at
org
.apache
.wicket
.request
.AbstractRequestCycleProcessor
.resolveRenderedPage(AbstractRequestCycleProcessor.java:471)
at
org
.apache
.wicket
.protocol
.http
.WebRequestCycleProcessor.resolve(WebRequestCycleProcessor.java:
144)
at org.apache.wicket.RequestCycle.step(RequestCycle.java:1310)
at org.apache.wicket.RequestCycle.steps(RequestCycle.java:1428)
at org.apache.wicket.RequestCycle.request(RequestCycle.java:545)
So
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Re: Updating Form Elements by Ajax with new POJO-Model
Try replacing the Model's object instead of the actual Model.
private EditFormModel editFormModel = new
CompoundPropertyModelFunctionsbereich(el);
replace
//f.setModel(new CompoundPropertyModelFunctionsbereich(el));
editFormModel.setObject(el);
On 16 Dec 2009, at 6:27 AM, Martin U wrote:
Iam totally confused.
Iam using the Todo-List-Example from here :
http://www.wicket-library.com/wicket-examples/ajax/todo-list.0
to play around with wicket.
This example works, but i want to display a list of Entities from the
Backend and edit one of them with my new-entity-Form.
So i want to click on edit in a row and want to use the *same*
*form *as i
use to add a entity. How could i handle this?
I tried sooo much but nothing works right.
The addForm (showForm(target)) function works right. But in public
void
showForm(AjaxRequestTarget _t, Functionsbereich el)
i deliver el which is my POJO and i cant figure out how to treat
the Form
to use now my new Model...
I tried with modelChange() und mondelChanging() but nothing works
=( allways
the empty Form is shown ;(
Thanks a lot for any help!!
private final class FormContainer extends WebMarkupContainer{
private EditForm f;
public FormContainer(String id) {
super(id);
setOutputMarkupId(true);
add(f = (EditForm) new EditForm(form).setVisible(false));
add(new AjaxFallbackLinkObject(link){
@Override
public void onClick(AjaxRequestTarget target) {
showForm(target);
}
});
}
public void showForm(AjaxRequestTarget _t){
f.setVisible(true);
_t.addComponent(this);
}
/** Shows form with entity **/
public void showForm(AjaxRequestTarget _t, Functionsbereich
el){
//add(f = new EditForm(link, el));
f.modelChanging();
f.setModel(new
CompoundPropertyModelFunctionsbereich(el));
f.modelChanged();
f.setVisible(true);
_t.addComponent(this);
}
}
private final class EditForm extends FormFunctionsbereich{
public EditForm(String id){
this(id, new CompoundPropertyModelFunctionsbereich(new
Functionsbereich()));
}
public EditForm(String id, Functionsbereich _el){
super(id,new
CompoundPropertyModelFunctionsbereich(_el) );
}
public EditForm(String id,
CompoundPropertyModelFunctionsbereich
_model) {
super(id, _model);
setOutputMarkupId(true);
add( new TextFieldObject(form_text,
_model.bind(label)));
//add(new Label(vendor, _model.bind(vendor.name)));
}
}
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Re: Updating Form Elements by Ajax with new POJO-Model
I think you might have to use setVisibilityAllowed(true), otherwise
the html does not make it onto the page.
Maybe this is better...
f = new EditFormFunctionsbereich(form,new
CompoundPropertyModelFunctionsbereich(el));
f.setVisible(false);
f.setVisibilityAllowed(true);
and then for Ajax...
f.setModelObject(e);
On 16 Dec 2009, at 7:09 AM, Eugene Malan wrote:
Try replacing the Model's object instead of the actual Model.
private EditFormModel editFormModel = new
CompoundPropertyModelFunctionsbereich(el);
replace
//f.setModel(new CompoundPropertyModelFunctionsbereich(el));
editFormModel.setObject(el);
On 16 Dec 2009, at 6:27 AM, Martin U wrote:
Iam totally confused.
Iam using the Todo-List-Example from here :
http://www.wicket-library.com/wicket-examples/ajax/todo-list.0
to play around with wicket.
This example works, but i want to display a list of Entities from the
Backend and edit one of them with my new-entity-Form.
So i want to click on edit in a row and want to use the *same*
*form *as i
use to add a entity. How could i handle this?
I tried sooo much but nothing works right.
The addForm (showForm(target)) function works right. But in
public void
showForm(AjaxRequestTarget _t, Functionsbereich el)
i deliver el which is my POJO and i cant figure out how to treat
the Form
to use now my new Model...
I tried with modelChange() und mondelChanging() but nothing works
=( allways
the empty Form is shown ;(
Thanks a lot for any help!!
private final class FormContainer extends WebMarkupContainer{
private EditForm f;
public FormContainer(String id) {
super(id);
setOutputMarkupId(true);
add(f = (EditForm) new EditForm(form).setVisible(false));
add(new AjaxFallbackLinkObject(link){
@Override
public void onClick(AjaxRequestTarget target) {
showForm(target);
}
});
}
public void showForm(AjaxRequestTarget _t){
f.setVisible(true);
_t.addComponent(this);
}
/** Shows form with entity **/
public void showForm(AjaxRequestTarget _t, Functionsbereich
el){
//add(f = new EditForm(link, el));
f.modelChanging();
f.setModel(new
CompoundPropertyModelFunctionsbereich(el));
f.modelChanged();
f.setVisible(true);
_t.addComponent(this);
}
}
private final class EditForm extends FormFunctionsbereich{
public EditForm(String id){
this(id, new CompoundPropertyModelFunctionsbereich(new
Functionsbereich()));
}
public EditForm(String id, Functionsbereich _el){
super(id,new
CompoundPropertyModelFunctionsbereich(_el) );
}
public EditForm(String id,
CompoundPropertyModelFunctionsbereich
_model) {
super(id, _model);
setOutputMarkupId(true);
add( new TextFieldObject(form_text,
_model.bind(label)));
//add(new Label(vendor, _model.bind(vendor.name)));
}
}
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