Submitting form via Ajax isn't working
Hey,
I have a form and I want to submit it via Ajax:
wicket:panel
form wicket:id=form
div wicket:id=feedback/div
table width=100% cellpadding=2 cellspacing=2
tr
tdlabelwicket:message key=name/
/label/td
tdspan wicket:id=nameBorder
input type=text wicket:id=name//span/td
/tr
tr
tdwicket:message key=note//td
tdtextarea cols=20 rows=10
wicket:id=note/textarea/td
/tr
tr
td colspan=2
input wicket:id=create type=button value=Create Group//td
/tr
/table
/form
/wicket:panel
public CreateGroupPanel(String id) {
super(id);
setOutputMarkupId(true);
final Form form = new Form(form,
new CompoundPropertyModel(new Group()));
add(form);
form.add(new FeedbackPanel(feedback));
form.add(new
FormComponentFeedbackBorder(nameBorder).add(new
TextField(name).setRequired(true)));
form.add(new TextArea(note));
form.add(new AjaxSubmitLink(create) {
@Override
protected void onSubmit(AjaxRequestTarget target,
Form form) {
Group group = (Group) form.getModelObject();
System.out.println(Logging: + group);
}
});
}
But nothing is got print on the console.
Any ideas what is going wrong?
FireFox 3.0.7
Ubuntu 8.10
Wicket 1.3.5
Thanks.
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Re: Submitting form via Ajax isn't working
You should implement the onError method of the button and update
feedback panel to see possible validation errors.
**
Martin
2009/4/19 HHB hubaghd...@yahoo.ca:
Hey,
I have a form and I want to submit it via Ajax:
wicket:panel
form wicket:id=form
div wicket:id=feedback/div
table width=100% cellpadding=2 cellspacing=2
tr
tdlabelwicket:message key=name/
/label/td
tdspan wicket:id=nameBorder
input type=text wicket:id=name//span/td
/tr
tr
tdwicket:message key=note//td
tdtextarea cols=20 rows=10
wicket:id=note/textarea/td
/tr
tr
td colspan=2
input wicket:id=create type=button value=Create Group//td
/tr
/table
/form
/wicket:panel
public CreateGroupPanel(String id) {
super(id);
setOutputMarkupId(true);
final Form form = new Form(form,
new CompoundPropertyModel(new Group()));
add(form);
form.add(new FeedbackPanel(feedback));
form.add(new
FormComponentFeedbackBorder(nameBorder).add(new
TextField(name).setRequired(true)));
form.add(new TextArea(note));
form.add(new AjaxSubmitLink(create) {
@Override
protected void onSubmit(AjaxRequestTarget target,
Form form) {
Group group = (Group) form.getModelObject();
System.out.println(Logging: + group);
}
});
}
But nothing is got print on the console.
Any ideas what is going wrong?
FireFox 3.0.7
Ubuntu 8.10
Wicket 1.3.5
Thanks.
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
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Re: Submitting form via Ajax isn't working
All looks good to me, my guess is that you aren't entering in a name,
and so you're failing validation, but you haven't implemented onError
to add the feedback panel to the target in that case. Also, your
feedback panel probably needs setOutputMarkupId(true) to be of any
use, given that you're submitting with ajax.
-Clint
On Sun, Apr 19, 2009 at 9:11 AM, HHB hubaghd...@yahoo.ca wrote:
Hey,
I have a form and I want to submit it via Ajax:
wicket:panel
form wicket:id=form
div wicket:id=feedback/div
table width=100% cellpadding=2 cellspacing=2
tr
tdlabelwicket:message key=name/
/label/td
tdspan wicket:id=nameBorder
input type=text wicket:id=name//span/td
/tr
tr
tdwicket:message key=note//td
tdtextarea cols=20 rows=10
wicket:id=note/textarea/td
/tr
tr
td colspan=2
input wicket:id=create type=button value=Create Group//td
/tr
/table
/form
/wicket:panel
public CreateGroupPanel(String id) {
super(id);
setOutputMarkupId(true);
final Form form = new Form(form,
new CompoundPropertyModel(new Group()));
add(form);
form.add(new FeedbackPanel(feedback));
form.add(new
FormComponentFeedbackBorder(nameBorder).add(new
TextField(name).setRequired(true)));
form.add(new TextArea(note));
form.add(new AjaxSubmitLink(create) {
�...@override
protected void onSubmit(AjaxRequestTarget target,
Form form) {
Group group = (Group) form.getModelObject();
System.out.println(Logging: + group);
}
});
}
But nothing is got print on the console.
Any ideas what is going wrong?
FireFox 3.0.7
Ubuntu 8.10
Wicket 1.3.5
Thanks.
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
Re: Submitting form via Ajax isn't working
Yes, you are right.
My isssue is solved now, thanks.
cpopetz wrote:
All looks good to me, my guess is that you aren't entering in a name,
and so you're failing validation, but you haven't implemented onError
to add the feedback panel to the target in that case. Also, your
feedback panel probably needs setOutputMarkupId(true) to be of any
use, given that you're submitting with ajax.
-Clint
On Sun, Apr 19, 2009 at 9:11 AM, HHB hubaghd...@yahoo.ca wrote:
Hey,
I have a form and I want to submit it via Ajax:
wicket:panel
form wicket:id=form
div wicket:id=feedback/div
table width=100% cellpadding=2 cellspacing=2
tr
tdlabelwicket:message key=name/
/label/td
td
input type=text wicket:id=name//td
/tr
tr
tdwicket:message key=note//td
tdtextarea cols=20 rows=10
wicket:id=note/textarea/td
/tr
tr
td colspan=2
input wicket:id=create type=button value=Create Group//td
/tr
/table
/form
/wicket:panel
public CreateGroupPanel(String id) {
super(id);
setOutputMarkupId(true);
final Form form = new Form(form,
new CompoundPropertyModel(new Group()));
add(form);
form.add(new FeedbackPanel(feedback));
form.add(new
FormComponentFeedbackBorder(nameBorder).add(new
TextField(name).setRequired(true)));
form.add(new TextArea(note));
form.add(new AjaxSubmitLink(create) {
�...@override
protected void onSubmit(AjaxRequestTarget target,
Form form) {
Group group = (Group) form.getModelObject();
System.out.println(Logging: + group);
}
});
}
But nothing is got print on the console.
Any ideas what is going wrong?
FireFox 3.0.7
Ubuntu 8.10
Wicket 1.3.5
Thanks.
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
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