Re: Replacing '%' in a text file
--- Tim Chase [EMAIL PROTECTED] wrote: I have to replace every occurrence of % in a file with % |. I have been effectively replacing text using the following construct: :%s/\text\/replacement/g However when I try to do the following: :%s/\%\/% |/g I am greeted by an error message. Obviously, the % character needs to be treated differently for being replaced. Escap sequence? The error message returned should give a clue regarding the problem (E486: Pattern not found: \%\). Your pattern \text\ works well for words, ensuring that you don't find them as a sub-portion of some other word (such as finding the foo in food, snafoo, or confoosion). However, the \ and \ tokens require a transition from a non-word-character to a word-character (or vice-versa). The % character, by default, is not a key-word character (though this can be altered by changing the 'iskeyword' setting). Unless there is some context in which you *don't* want to replace a % with % |, you can just use :%s/%/% |/g without the \ and \ markers. You can read more about the problematic operators at :help /\ or making them part of the set of characters that constitute a keyword, by reading at :help 'iskeyword' HTH, -tim Thanks. The problem is now resolved. -- Muhammad Farooq-i-Azam __ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com
Replacing '%' in a text file
I have to replace every occurrence of % in a file with % |. I have been effectively replacing text using the following construct: :%s/\text\/replacement/g However when I try to do the following: :%s/\%\/% |/g I am greeted by an error message. Obviously, the % character needs to be treated differently for being replaced. Escap sequence? I cannot figure out how to do it. May be trivial for the gurus here. I will be thankful for a hint. Many thanks in advance. -- Muhammad Farooq-i-Azam __ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com
Re: Replacing '%' in a text file
Hi, Muhammad Farooq-i-Azam wrote: I have to replace every occurrence of % in a file with % |. I have been effectively replacing text using the following construct: :%s/\text\/replacement/g However when I try to do the following: :%s/\%\/% |/g I am greeted by an error message. Obviously, the % character needs to be treated differently for being replaced. Escap sequence? I cannot figure out how to do it. May be trivial for the gurus here. I will be thankful for a hint. normally % is not included in the 'iskeyword' option so it is not considered part of a word. Therefore there can not be the beginning of a word right in front of %. The same is for true for the end of a word immediately after a %. You either have to include % in the 'iskeyword' option by issuing a :set iskeyword+=% before executing your substitute command or use :%s/%/% |/g without '\' and '\', respectively. Regards, Jürgen -- Sometimes I think the surest sign that intelligent life exists elsewhere in the universe is that none of it has tried to contact us. (Calvin)
Re: Replacing '%' in a text file
I have to replace every occurrence of % in a file with % |. I have been effectively replacing text using the following construct: :%s/\text\/replacement/g However when I try to do the following: :%s/\%\/% |/g I am greeted by an error message. Obviously, the % character needs to be treated differently for being replaced. Escap sequence? The error message returned should give a clue regarding the problem (E486: Pattern not found: \%\). Your pattern \text\ works well for words, ensuring that you don't find them as a sub-portion of some other word (such as finding the foo in food, snafoo, or confoosion). However, the \ and \ tokens require a transition from a non-word-character to a word-character (or vice-versa). The % character, by default, is not a key-word character (though this can be altered by changing the 'iskeyword' setting). Unless there is some context in which you *don't* want to replace a % with % |, you can just use :%s/%/% |/g without the \ and \ markers. You can read more about the problematic operators at :help /\ or making them part of the set of characters that constitute a keyword, by reading at :help 'iskeyword' HTH, -tim
Re: Replacing '%' in a text file
I create a test file and was able to replace all % with % | by doing this: :%s/%/% |/g You shouldn't need to escape the % Muhammad Farooq-i-Azam wrote: I have to replace every occurrence of % in a file with % |. I have been effectively replacing text using the following construct: :%s/\text\/replacement/g However when I try to do the following: :%s/\%\/% |/g I am greeted by an error message. Obviously, the % character needs to be treated differently for being replaced. Escap sequence? I cannot figure out how to do it. May be trivial for the gurus here. I will be thankful for a hint. Many thanks in advance. -- Muhammad Farooq-i-Azam __ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com -- Scot P. Floess 27 Lake Royale Louisburg, NC 27549 252-478-8087 (Home) 919-754-4592 (Work) Chief Architect JPlate http://sourceforge.net/projects/jplate Chief Architect JavaPIM http://sourceforge.net/projects/javapim
Re: Replacing '%' in a text file
Muhammad Farooq-i-Azam wrote: I have to replace every occurrence of % in a file with % |. I have been effectively replacing text using the following construct: :%s/\text\/replacement/g However when I try to do the following: :%s/\%\/% |/g I am greeted by an error message. Obviously, the % character needs to be treated differently for being replaced. Escap sequence? I cannot figure out how to do it. May be trivial for the gurus here. I will be thankful for a hint. Many thanks in advance. -- Muhammad Farooq-i-Azam Which message do you encounter? If it's E486: Pattern not found: \%\ it means that Vim doesn't find a match. I guess the boundary between space and %, or % and space, is not seen as a word boundary. What is 'iskeyword' set to? By default, nothing lower than 48 (0x30 i.e., the digit zero) is a keyword character. Now % is 0x25, i.e., it is not included. Thus it is not seen as part of a word, and therefore it cannot be preceded by a begin-of word or followed by an end-of-word. I suggest the following code snippet: let save_isk = isk setlocal isk+=% %s/\%\/% |/g let l:isk = save_isk If you can afford to replace every percent sign regardless of what precedes or follows it, you can do simply :%s/%/% |/g Best regards, Tony.
