[web2py] unittest application modules
Hi *, reading the manual I couldn't understand how to do what I need or at least if I'm looking in the wrong direction... I want to write some unittests for an application module that uses current.db so I think it needs to be run under my application environment. What's the right way to do it? Thanks a lot Manuele -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Hide a form field in view
I don't think I can use it because 'show_if' still happens in the controller. On Sunday, August 3, 2014 4:03:59 AM UTC+3, 黄祥 wrote: perhaps you can use, show_if. ref: http://web2py.com/books/default/chapter/29/07/forms-and-validators#Conditional-fields best regards, stifan -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Hide a form field in view
Haven't tried it, but maybe add the value to form.vars via an onvalidation function: def add_dynamic_value(form): form.vars.dynamic_field = [value calculated from existing form.vars] form = SQLFORM(db.mytable).process(onvalidation=add_dynamic_value) Anthony On Sunday, August 3, 2014 1:28:46 AM UTC+2, desta wrote: Is it possible, when creating a form with SQLFORM to set a field as hidden? In my application I have a form which one of its fields, has to be completed automatically i.e. not by the user. The problem is that the data that goes into that field is dynamic (depends on the actions of the user) and it is not known when the form is constructed in the controller. That means that the field has to be in the html and hidden. *readable=False* and *writable=False* don't work in this case. Any suggestions? Thank you. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Switch off cookies unless the user logs in?
How can i switch off (session) cookies unless a user logs in? Thanks! -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Switch off cookies unless the user logs in?
In the beginning of your controller (e.g.): def index(): if not auth.is_logged_in(): session.forget(response) Regards On Sunday, August 3, 2014 2:11:29 PM UTC+2, Thomas Wimmer wrote: How can i switch off (session) cookies unless a user logs in? Thanks! -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Scheduler, modules, and database calls
there's nothing different in running the function in the web2py shell. global variables defined in models are available in the scheduler. On Friday, August 1, 2014 11:36:36 PM UTC+2, Bilal Hasan wrote: So I'm trying to set up a scheduler, which makes calls to the module. Problem is, it keeps failing. And since it's the scheduler, it's super hard to debug if not almost impossible. Within the module, it makes db calls. Now since db is a global variable, which module CANNOT access. I have to pass in db through its function calls. So I have that part figured out. My question is, when scheduler runs its function, does it have accses to the same global db instance that's a part of web2py? Since scheduler runs on its own process I have reason to believe whenever scheduler runs, it doesn't have access to db, request, etc. Any ideas on what's a good way of going about running a scheduler that calls a function in a module which makes calls to the database using the global db variable. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: How do you gracefully terminate a scheduled task
task status is normally set to failed if the task raises an exception. You can't however ask a thing made to run over and over in a loop (the scheduler) to stop at the first task that raises an exception, else every other queued task won't be processed. On Friday, August 1, 2014 5:01:56 PM UTC+2, Stephen Weiss wrote: I understand that's what stetting STOP_TASK to do. However, what I'm in search of is a way for the worker task to cleanly stop processing on its own, setting the state to FAILED. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: SQLFORM.grid, how to edit non-visible field in the onvalidate function?
Thank you very much.
But seems following works for me too:
form = SQLFORM.factory(
Field('find_contact_string', label=Choose from contacts),
Field('contact_id', readable=False, writable=False),
hidden=dict(contact_id='')
)
if form.process(onvalidation=_validate_form).accepted:
db.invoice[request.args(0)] = dict(contact_id=form.vars.contact_id)
redirect(URL(..))
return dict(form=form)
def _validate_form(form):
if request.vars.contact_id:
form.vars.contact_id = request.vars.contact_id
else:
form.errors.find_contact_string = Enter a text to find the
customer
I assign the errors message to the visible field (find_contact_string).
contact_id I change with jQuery:
$('[name=contact_id]').val(2);
Dne neděle, 9. února 2014 17:26:27 UTC+1 A36_Marty napsal(a):
A little more progress -- hopefully to help someone else that Googles for
this and ends up stumped like I was... I've spent an inordinate amount of
time and frustration figuring out little nuances that I wouldn't wish upon
anyone...
Gotca's that I learned:
1) To hide a field, first remove it from the fields to be shown in the
SQLFORM, then add it back with the hidden= attribute. Just specifying it
as hidden does not remove it.
i.e. This does NOT work, the field 'hidden' is shown to the user:
db.define_table('person',
Field('name', 'string'),
Field('hidden', 'string'))
def index():
form = SQLFORM(db.person, hidden=dict(hidden=Default hidden text))
form.vars.hidden = request.vars.
This DOES work:
db.define_table('person',
Field('name', 'string'),
Field('hidden', 'string'))
def index():
form = SQLFORM(db.person, fields=['name'], hidden=dict(hidden=Default
hidden text))
form.vars.hidden = request.vars.
2) To get a list of fields to show (from a larger table definition, so as
to not hand-type each field name), you must get a copy of the fields from
the table object, not just a reference to the fields.
i.e. This DOES NOT work. The field will be be removed and unseen by the
user, however since Python works by reference, the field is removed from
the table definition and the form.accepted() will fail as web2py will try
to insert a value into field that no longer exists.
db.define_table('person',
Field('name', 'string'),
Field('hidden', 'string'))
def index():
fields_to_show = db.person.fields
fields_to_show.remove('hidden')
form = SQLFORM(db.person, fields= fields_to_show,
hidden=dict(hidden=Default
hidden text))
form.vars.hidden = request.vars.Enter code here...
This DOES work (only 3 characters difference) - making a copy of the
fields list instead of getting it by reference:
db.define_table('person',
Field('name', 'string'),
Field('hidden', 'string'))
def index():
fields_to_show = db.person.fields*[:]*
fields_to_show.remove('hidden')
form = SQLFORM(db.person, fields= fields_to_show,
hidden=dict(hidden=Default
hidden text))
form.vars.hidden = request.vars.Enter code here...
3. To update the value of the hidden fields (or any fields), the form.vars
modification must be before the form.process call.
i.e. This DOES NOT work.
db.define_table('person',
Field('name', 'string'),
Field('hidden', 'string'))
def index():
form = SQLFORM(db.person, fields=['name'], hidden=dict(hidden=Default
hidden text))
form.vars.hidden = request.vars.
if form.process(onvalidation=validate_form).accepted:
pass
return dict(form=form)
def validate_form(form):
*form.vars.hidden = Changed hidden text #Never gets written to
database*
form.accepted = True
This does work:
db.define_table('person',
Field('name', 'string'),
Field('hidden', 'string'))
def index():
form = SQLFORM(db.person, fields=['name'], hidden=dict(hidden=Default
hidden text))
form.vars.hidden = request.vars.
*form.vars.hidden = Changed hidden text #Successfully written to
database*
if form.process(onvalidation=validate_form).accepted:
pass
return dict(form=form)
def validate_form(form):
form.accepted = True
Take care...
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[web2py] emailing a pdf view as an attachment
I have a form, and i display the details entered in the form on .pdf views page. Is it possible to use web2py to email that generated pdf page to someone? what I want to achieve is to allow users to fill the form and then click a button to send the pdf containing the entered details without downloading the pdf and re-uploading it... it's about the best solution I've come up with so far but that's not what I want to achieve. It'll be too much hustle for users (even I wouldn't want to do that) -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Web2Py on BeagleBone Black Rev C - Debian
Anyone had success getting Web2Py running as the default site (port 80) on a BB Rev C running debian? I used the ubuntu install script from the Web2Py docs and seem to have a conflict with the default website that comes pre-installed on the BBB Rev C. The script seems to have completed successfully, but I can't connect to the web2py admin page. Any suggestions on how to validate the install and config or to look for where conflicts can occur (maybe competing web servers?) would be much appreciated. Thanks for the help, -p -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] cvs web2py model
hello,
i tried tu create webpy model from csv file with this command :
/home/csvstudio# for line in open('db_departement.py','r'): print line,
the terminal answer- bash: Erreur de syntaxe près du symbole inattendu «
( »
somebody look where my error.
thanks
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[web2py] Re: Question about FORM
Yes, thank you, it is the second way to get. First, as I understand it is
more suitable for the form, which is filled.
The only time The blue button is turned. And underlined font, that I did
not point
суббота, 2 августа 2014 г., 22:43:00 UTC+3 пользователь Massimo Di Pierro
написал:
form = FORM()
makes a form but you are making a form that contains no
input/select/texarea/buttons.
form.add_button('Click', URL ('first'))
adds a button after the submit button in the previous form, but that form
does not have a submit button.
If you really want a form, you should put something in the form:
form = FORM(INPUT(_type=Submit)
form.add_button('Click', URL ('first'))
or do not use a form but, for example, a DIV
form = DIV()
form.append(A('Click', _href=URL ('first')))
On Saturday, 2 August 2014 12:58:04 UTC-5, tir...@gmail.com wrote:
Good evening, I just started learning this fremvork because questions
may seem childish, but still.
task:
Create a jump button (just to another page)
My solution, I wrote a similar code kontoroller
def index ():
form = FORM ()
form.add_button ('Click', URL ('first'))
return dict (form = form)
the error is
AttributeError: 'NoneType' object has no attribute 'parent'
Although the official documentation of such a method is listed as a way
to create simple buttons. I would be grateful for your help
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[web2py] PeerQuiz
hello , everybody, i looking for peerquiz web2py source http://vimeo.com/83536698 . i dont find in github. somebody know where i can find it ? thanks -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Strange ajax problem
Did you figure out what was wrong? I faced the same issue. Everything works
fine when I take out the ajax function.
On Sunday, May 4, 2014 9:33:05 AM UTC-4, John Drake wrote:
I've created a simple ajax form to update a post database. For some
strange reason when I post a new message, the button greys out.
Here is the model:
db.define_table('t_post',
Field('f_post', type='text',
label=T('Post')),
auth.signature,
format='%(f_post)s')
Here are my controller functions.
def ajax_post():
posts = crud.select(db.t_post, fields=['f_post'], query =
db.t_post.created_by == auth.user,
headers={'t_post.f_post': 'Post'}, orderby =
~db.t_post.created_on)
search = crud.search(db.t_post)
return dict(posts=posts, search=search)
def new_post():
postdata = request.vars.post
db.t_post.insert(f_post = postdata)
posts = crud.select(db.t_post, fields=['f_post'], query =
db.t_post.created_by == auth.user,
headers={'t_post.f_post': 'Post'}, orderby =
~db.t_post.created_on)
return posts
Here is the model:
{{extend 'layout.html'}}
h1This is the default/ajax_post.html template/h1
form onsubmit=return false
divPost : input name=post//div
divbutton onclick=ajax('new_post', ['post'],'results')Post
Message/button/div
/form
div id=results
{{=posts}}
/div
div
{{=search[0]}}
/div
At first I used an input field with type submit for the submit button.
When that happened, it would
grey out and the value would set to Working. At least now button
text doesn't change, but it
it still grey's out. Inspecting the element in Firefox I get:
button value=Working... class=btn disabled onclick=ajax('new_post',
['post'],'results')Post Message/button
Why? I didn't ask it to change the button's class to disabled. And it
stays greyed even though
the results have returned and my results div has been properly updated.
I can still click on
the button, but it just appears disabled.
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