[web2py] Re: Weird problems generating menu from database
Thank you so much, Massimo! That's what I need! -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
Replace:
response.menu = cache.ram('menu', lambda:build_menu(), None) # to cache it!
with
submenu = cache.ram('menu', lambda:build_menu(), None) # to cache it!
response.menu =[('Main', False, URL('default', 'index'), submenu]
On Monday, 14 August 2017 02:50:09 UTC-5, Вячеслав Анатольевич wrote:
>
> Hi Massimo! Thanks so much! It Works! But it generate menu in inline, like
> this:
>
> menu1 menu1menu1
>
> In menu1-menu2 in menu2-mnm_name (thats all right) But how menu1 insert in
>
> response.menu =[
>('Main', False, URL('default', 'index'), [here]]
>
>
>
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[web2py] Re: Weird problems generating menu from database
Hi! in that example - i have error: subsubmenu = [[key, None, link] for key, link in items] ValueError: too many values to unpack -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
So I think...
db = DAL('sqlite://storage.sqlite')
db.define_table('map',Field('menu1'),Field('menu2'),Field('mnm_name'),Field(
'link'))
import collections
def build_menu():
m1, m2 = [], [] # to preserve orders
m = collections.defaultdict(lambda: collections.defaultdict(list))
for row in db(db.map).select(orderby=db.map.menu1|db.map.menu2):
if not row.menu1 in m1: m1.append(row.menu1)
if not row.menu2 in m2: m2.append(row.menu2)
m[row.menu1][row.menu2].append((row.mnm_name, row.link))
menu = []
for a in m1:
submenu = []
menu.append([a, None, None, submenu])
for b, items in m[a].items():
subsubmenu = [[key, None, link] for key, link in items]
submenu.append([b, None, None, subsubmenu])
return menu
response.menu = cache.ram('menu', lambda:build_menu(), None) # to cache it!
On Sunday, 6 August 2017 04:31:00 UTC-5, Вячеслав Анатольевич wrote:
>
> Thanks, Massimo!
> So, i have a database table - named "map", in that table - three field -
> menu1, menu2, mnm_name.
> Menu mast be like that:
>
>- menu1
> - menu2
> -mnm_name
> In menu1 - menu2, in menu2 - mnm_name
>
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[web2py] Re: Weird problems generating menu from database
> > In Wiki menus: > - Home > @index - Info > @info - web2py > http://www.web2py.com - - About us > @aboutus - - - Contact us > @contactus - If I add a third minus - THIS NOT WORKED! -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
Thanks, Massimo! So, i have a database table - named "map", in that table - three field - menu1, menu2, mnm_name. Menu mast be like that: - menu1 - menu2 -mnm_name In menu1 - menu2, in menu2 - mnm_name -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
Yes. It is possible but I am a little confused by your model to be able to provide an example that works for you. Can you please provide your model again an example of data that should comprise the menu? Notice what you seek is done here: https://github.com/web2py/web2py/blob/master/gluon/tools.py#L6358 for the wiki menu, where the menu is parsed form the wiki-menu page. Massimo On Wednesday, 2 August 2017 21:55:07 UTC-5, Dave S wrote: > > > > On Wednesday, August 2, 2017 at 12:12:04 AM UTC-7, Вячеслав Анатольевич > wrote: >> >> Me personally, no, but I understand BS3 limits the number of menu levels. >>> >>> /dps >>> >>> >> >> So, it is inpossible or not? I'm ask because it's hard to puzzle over >> this or it's really impossible? >> > > Sorry, outside of my limited knowledge. I've added and subtracted items > from the regular navbar, and I remember a little of the conversation from > when the bs3 switch was made, but that's as far as I can go. For my own > purposes, regular A-tags in the left column are what I use, but I rarely > have more than 4 places to go from a page. > > You need an answer from an actual guru; Massimo himself, or Anthony or > Leone, or Michele C (mcm). Some of the other long-time users maybe, like > Richard or Joe. > > /dps > > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
On Wednesday, August 2, 2017 at 12:12:04 AM UTC-7, Вячеслав Анатольевич wrote: > > Me personally, no, but I understand BS3 limits the number of menu levels. >> >> /dps >> >> > > So, it is inpossible or not? I'm ask because it's hard to puzzle over > this or it's really impossible? > Sorry, outside of my limited knowledge. I've added and subtracted items from the regular navbar, and I remember a little of the conversation from when the bs3 switch was made, but that's as far as I can go. For my own purposes, regular A-tags in the left column are what I use, but I rarely have more than 4 places to go from a page. You need an answer from an actual guru; Massimo himself, or Anthony or Leone, or Michele C (mcm). Some of the other long-time users maybe, like Richard or Joe. /dps -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
> > Me personally, no, but I understand BS3 limits the number of menu levels. > > /dps > > So, it is inpossible or not? I'm ask because it's hard to puzzle over this or it's really impossible? -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
On Tuesday, August 1, 2017 at 11:21:03 PM UTC-7, Вячеслав Анатольевич wrote: > > Have some idea about this? > Me personally, no, but I understand BS3 limits the number of menu levels. /dps -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
Have some idea about this? -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
I understood what was the matter, it was styling!
But, how to add the third field:
if auth.is_logged_in():
rows = db(db.map).select(db.map.menu1, db.map.menu2, db.map.mnm_name,
orderby=db.map.num, distinct=True)
from collections import defaultdict
d = defaultdict(list)
for row in rows:
d[row.menu1].append(row.menu2)
response.menu = [('Shema', True, URL('default'),[
[key, False, None, [[sub, False, None, [[sub, False, 'link']]] for sub in
sorted(d[key])]] for key in sorted(d)])
]
in layout.html add style and js:
.dropdown-submenu{position:relative;}
.dropdown-submenu>.dropdown-menu{top:0;left:100%;margin-top:-6px;margin-left:-1px;-webkit-border-radius:0
6px 6px 6px;-moz-border-radius:0 6px 6px 6px;border-radius:0 6px 6px 6px;}
.dropdown-submenu:hover>.dropdown-menu{display:block;}
.dropdown-submenu>a:after{display:block;content:"
";float:right;width:0;height:0;border-color:transparent;border-style:solid;border-width:5px
0 5px 5px;border-left-color:#cc;margin-top:5px;margin-right:-10px;}
.dropdown-submenu:hover>a:after{border-left-color:#ff;}
.dropdown-submenu.pull-left{float:none;}.dropdown-submenu.pull-left>.dropdown-menu{left:-100%;margin-left:10px;-webkit-border-radius:6px
0 6px 6px;-moz-border-radius:6px 0 6px 6px;border-radius:6px 0 6px 6px;}
How to add db.map.mnm_name to row.menu2, somthing like that -
d[row.menu1].append(row.menu2).append(db.map.mnm_name) (i know - that's is not
working)
?
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[web2py] Re: Weird problems generating menu from database
> > I'm using bootstrap css/js form wellcom app, about stupid.css - now > reading, but it's a little different, > I need to build a menu from the database table (three fields), as in the > example above. > Somthing like this: topmenu |menu |-sibmenu | |- submenu > > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
On Monday, July 31, 2017 at 10:22:51 PM UTC-7, Вячеслав Анатольевич wrote: > > > Hi, Dave S, maybe you right! But How to create in submenuitem - > submenuitem? >> >> >> > Are you using the bootstrap css/js like the welcome app, or the stupic.css stuff from the examples app, or something else? /dps -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
Hi, Dave S, maybe you right! But How to create in submenuitem - submenuitem? > > > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
On Saturday, July 29, 2017 at 11:42:42 PM UTC-7, Вячеслав Анатольевич wrote: > > Thanks for the answer, Massimo! > > But this example makes the menu items in one line with one drop-down menu > item. > Like this: > > Menuitem Menuitem > - submenuitem- submenuitem > > I have three fields, they must be somthing like this (anothermenu - just for > example - to understand that is top menu): > > > > Menuitem > - submenuitem >- subsubmenuitem > - submenuitem > - submenuitem > Menuitem > -submenuitem > -submenuitem > - subsubmenuitem > - subsubmenuitem > - subsubmenuitem > -submenuitem > -submenuitem > > Please, can you tell me how to do this? > > Isn't that a CSS issue, like forms using COL3, etc? /dps -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
Thanks for the answer, Massimo! But this example makes the menu items in one line with one drop-down menu item. Like this: Menuitem Menuitem - submenuitem- submenuitem I have three fields, they must be somthing like this (anothermenu - just for example - to understand that is top menu): Menuitem - submenuitem - subsubmenuitem - submenuitem - submenuitem Menuitem -submenuitem -submenuitem - subsubmenuitem - subsubmenuitem - subsubmenuitem -submenuitem -submenuitem Please, can you tell me how to do this? -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
Let me assume there is only one level and this cannot be arbitrarily
nested. Also I assume the initial model of this thread:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
t = store_catalog
rows = db(t).select()
from collections import defaultdict
d=defaultdict(list)
for row in rows: d[row.maincategory].append(row.subcategory)
response.menu = [
[T(key), False, None, [[T(sub), False, 'link'] for sub in
sorted(d[key])]] for key in sorted(d)
]
On Saturday, 29 July 2017 08:00:40 UTC-5, Вячеслав Анатольевич wrote:
>
> Hi!
>
> Paraphrase the question, can anyone explain how to create
> a drop-down menu from a database table or show a working example?
>
>
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[web2py] Re: Weird problems generating menu from database
Hi! Paraphrase the question, can anyone explain how to create a drop-down menu from a database table or show a working example? -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Weird problems generating menu from database
> db.define_table('store_catalog',
>> Field('title'),
>> Field('slug',requires=IS_SLUG(),compute=lambda row:
>> IS_SLUG.urlify(row.titl\
>> e)),
>> Field('parent_id','reference store_catalog'))
>>
>> id1 = db.store_catalog.insert(title='main')
>> id2 = db.store_catalog.insert(title='one',parent_id=id1)
>> id3 = db.store_catalog.insert(title='two',parent_id=id2)
>>
>> def menu_rec(items): return
>> [(x.title,None,URL('action',args=x.slug),menu_rec(x\
>> .children)) for x in items or []]
>> response.menu = menu_rec(db(db.store_catalog).select().as_trees())
>> print response.menu
>>
>
Hi!
Is there a more modern solution to this issue?
Raises an error - need more than 0 values to unpack
If to substitute
return [((x.title,None,URL('action',args=x.slug),menu_rec(x.children)) for
x in items or []), False, URL('default')]
it shows - but an error
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[web2py] Re: Weird problems generating menu from database
Hi again all!
Upon further trying to expand and experiment I stuck at something that
maybe I need to be clarified on or I'm doing wrong.
Basically what I did is create a store.py in that I specified the
database exactly like it was in db.py (except. Then what I did in menu.py
was simply change:
response.menu = menu_rec(db(db.store_catalog).select().as_trees())
to
response.menu = menu_rec(store(store.store_catalog).select().as_trees())
However it immediately errors out in the shell claiming store is not
defined, as well as producing a ticket with the same error. When I change
it back to the original response.menu and I run the shell I can access
store.whatever. What am I not getting about this or is it not possible?
From the examples I've looked at it seems as though it should work. Can I
get pointed in the right direction or thinking on this please? Thanks!
On Thursday, January 23, 2014 6:40:53 AM UTC-6, web2pygroup wrote:
After disabling the key constraints none of those errors about it have
appeared. I am grateful for the assistance and will return it anyway I
can. I will post a summary here for anyone attempting this also. Thanks a
million!
On Wednesday, January 22, 2014 12:03:26 PM UTC-6, web2pygroup wrote:
That works great, thank you!!! My only remaining question is that when I
try to edit the first record main in the appadmin I get the foreign key
error. I read here -
https://groups.google.com/forum/#!topic/web2py/klspqXpha4E - about how
to disable it. Wasn't sure if I should do that or not... The other
records do not act up when changed, just that one so I'm sure I could work
around that but, just in case someone else manages the site... I'm not
sure. Thoughts?
On Tuesday, January 21, 2014 11:03:46 PM UTC-6, Massimo Di Pierro wrote:
Sorry typo. Let's try again:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.titl\
e)),
Field('parent_id','reference store_catalog'))
id1 = db.store_catalog.insert(title='main')
id2 = db.store_catalog.insert(title='one',parent_id=id1)
id3 = db.store_catalog.insert(title='two',parent_id=id2)
def menu_rec(items): return
[(x.title,None,URL('action',args=x.slug),menu_rec(x\
.children)) for x in items or []]
response.menu = menu_rec(db(db.store_catalog).select().as_trees())
print response.menu
On Tuesday, 21 January 2014 12:17:19 UTC-6, web2pygroup wrote:
Here's what I've tried so far and here's the results if it helps any to
get me on the right track, plus I hope this helps someone else looking for
this to because this is something very commonly done in PHP.
I have tried changing this:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3[-1]+=([(T(subcat.subcategory)), False, 'link',])
Which changes the output in the shell to:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
Which obviously isn't correct.
Continuing:
original:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
Gives this in the shell output:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals', False, 'link'],
[lazyT 'Dogs', False, 'link'],
[lazyT 'Cats', False, 'link']]
Again obviously incorrect. Continuing:
original:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
changed:
response.menu3[-1]+=((T(subcat.subcategory)), False, 'link',)
Shell output shows:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
I tried additional variations but, not sure how much space we have here
to keep going with my 2 weeks worth of work. Essentially the end result
is
the same a bracket missing to seperate the subcategories. I've been able
to modify and add to lists before, however I've never really experienced a
situation where the negative slice appears to be ignored (removing the
bracket at the end of dogs and beginning of cats as it is doing for the
main category Animals as can be seen), even removed the negative slice
([-1]) for the main categories iteration and when I do it clearly shows
that it is actually doing the negative slice properly because the brackets
come back at the end of Animals, unlike the subcategories that do not
appear to be removing the bracket(s)
On Monday, January 20, 2014 2:33:50 PM UTC-6, web2pygroup wrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop
down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
[web2py] Re: Weird problems generating menu from database
After disabling the key constraints none of those errors about it have
appeared. I am grateful for the assistance and will return it anyway I
can. I will post a summary here for anyone attempting this also. Thanks a
million!
On Wednesday, January 22, 2014 12:03:26 PM UTC-6, web2pygroup wrote:
That works great, thank you!!! My only remaining question is that when I
try to edit the first record main in the appadmin I get the foreign key
error. I read here -
https://groups.google.com/forum/#!topic/web2py/klspqXpha4E - about how
to disable it. Wasn't sure if I should do that or not... The other
records do not act up when changed, just that one so I'm sure I could work
around that but, just in case someone else manages the site... I'm not
sure. Thoughts?
On Tuesday, January 21, 2014 11:03:46 PM UTC-6, Massimo Di Pierro wrote:
Sorry typo. Let's try again:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.titl\
e)),
Field('parent_id','reference store_catalog'))
id1 = db.store_catalog.insert(title='main')
id2 = db.store_catalog.insert(title='one',parent_id=id1)
id3 = db.store_catalog.insert(title='two',parent_id=id2)
def menu_rec(items): return
[(x.title,None,URL('action',args=x.slug),menu_rec(x\
.children)) for x in items or []]
response.menu = menu_rec(db(db.store_catalog).select().as_trees())
print response.menu
On Tuesday, 21 January 2014 12:17:19 UTC-6, web2pygroup wrote:
Here's what I've tried so far and here's the results if it helps any to
get me on the right track, plus I hope this helps someone else looking for
this to because this is something very commonly done in PHP.
I have tried changing this:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3[-1]+=([(T(subcat.subcategory)), False, 'link',])
Which changes the output in the shell to:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
Which obviously isn't correct.
Continuing:
original:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
Gives this in the shell output:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals', False, 'link'],
[lazyT 'Dogs', False, 'link'],
[lazyT 'Cats', False, 'link']]
Again obviously incorrect. Continuing:
original:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
changed:
response.menu3[-1]+=((T(subcat.subcategory)), False, 'link',)
Shell output shows:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
I tried additional variations but, not sure how much space we have here
to keep going with my 2 weeks worth of work. Essentially the end result is
the same a bracket missing to seperate the subcategories. I've been able
to modify and add to lists before, however I've never really experienced a
situation where the negative slice appears to be ignored (removing the
bracket at the end of dogs and beginning of cats as it is doing for the
main category Animals as can be seen), even removed the negative slice
([-1]) for the main categories iteration and when I do it clearly shows
that it is actually doing the negative slice properly because the brackets
come back at the end of Animals, unlike the subcategories that do not
appear to be removing the bracket(s)
On Monday, January 20, 2014 2:33:50 PM UTC-6, web2pygroup wrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category
and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many
[web2py] Re: Weird problems generating menu from database
That works great, thank you!!! My only remaining question is that when I
try to edit the first record main in the appadmin I get the foreign key
error. I read here -
https://groups.google.com/forum/#!topic/web2py/klspqXpha4E - about how to
disable it. Wasn't sure if I should do that or not... The other records
do not act up when changed, just that one so I'm sure I could work around
that but, just in case someone else manages the site... I'm not sure.
Thoughts?
On Tuesday, January 21, 2014 11:03:46 PM UTC-6, Massimo Di Pierro wrote:
Sorry typo. Let's try again:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.titl\
e)),
Field('parent_id','reference store_catalog'))
id1 = db.store_catalog.insert(title='main')
id2 = db.store_catalog.insert(title='one',parent_id=id1)
id3 = db.store_catalog.insert(title='two',parent_id=id2)
def menu_rec(items): return
[(x.title,None,URL('action',args=x.slug),menu_rec(x\
.children)) for x in items or []]
response.menu = menu_rec(db(db.store_catalog).select().as_trees())
print response.menu
On Tuesday, 21 January 2014 12:17:19 UTC-6, web2pygroup wrote:
Here's what I've tried so far and here's the results if it helps any to
get me on the right track, plus I hope this helps someone else looking for
this to because this is something very commonly done in PHP.
I have tried changing this:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3[-1]+=([(T(subcat.subcategory)), False, 'link',])
Which changes the output in the shell to:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
Which obviously isn't correct.
Continuing:
original:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
Gives this in the shell output:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals', False, 'link'],
[lazyT 'Dogs', False, 'link'],
[lazyT 'Cats', False, 'link']]
Again obviously incorrect. Continuing:
original:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
changed:
response.menu3[-1]+=((T(subcat.subcategory)), False, 'link',)
Shell output shows:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
I tried additional variations but, not sure how much space we have here
to keep going with my 2 weeks worth of work. Essentially the end result is
the same a bracket missing to seperate the subcategories. I've been able
to modify and add to lists before, however I've never really experienced a
situation where the negative slice appears to be ignored (removing the
bracket at the end of dogs and beginning of cats as it is doing for the
main category Animals as can be seen), even removed the negative slice
([-1]) for the main categories iteration and when I do it clearly shows
that it is actually doing the negative slice properly because the brackets
come back at the end of Animals, unlike the subcategories that do not
appear to be removing the bracket(s)
On Monday, January 20, 2014 2:33:50 PM UTC-6, web2pygroup wrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
-
[web2py] Re: Weird problems generating menu from database
I attempted to copy/paste what you have so I can modify it for my needs.
However it immediately errors out with:
AttributeError: 'Table' object has no attribute 'parent'
So I thought I would comment out everything for the menu except
response.menu = [] and populate the database (have done this before and the
site comes up just no menu as expected).
I then decided to try and populate the database fields.
However when I try to populate it I immediately get an error
IntegrityError: FOREIGN KEY constraint failed. What I did was, put
Animals for the title, for description I put Main Animals Category,
then for the parent catelog I put Animals again. Upon seeing this I'm
confused as to how a subcategory would get identified. So I also tried
just putting Animals for the title, and filling in the description as
above, but leaving the parent catelog blank, it to also failed with exactly
the same error IntegrityError: FOREIGN KEY constraint failed. So
effectively I'm unable to even put anything in the fields, an issue I never
had so I'm unsure what the problem is.
Would it be possible to use the fields I have already established to
populate the menu? Since you have 3 fields identified in your table albeit
with slight differences, would it be possible to somehow incorporate that
into what I have? Could you also explain why you used += instead of
append? Maybe I could figure out something from that.
Thanks
On Tuesday, January 21, 2014 12:11:59 AM UTC-6, James Burke wrote:
Hi,
I managed to get one working a little while ago doing this. This has been
adapted for your situation, may require some tweaking:
_tables.py - model
db.define_table('store_catelog')
db.define_table('store_catelog',
Field('title', 'string'),
Field('description', 'text'),
Field('parent_catelog', 'reference store_catelog', default=None),
format='%(title)s',
redefine=True)
menu.py - model
response.menu = []
categories = db(db.store_catelog.parent == None).select(orderby=db.
store_catelog.id)
for category in categories:
response.menu+=[ (T(category.title), True if active_page == str(
category.title.lower()) else False, URL('default','page/%s' % (category.
title.lower())), [
(T(i.title), True if active_page == str(i.id) else False, URL(
'default','page/%s' % (i.id)), []) for i in db((db.stored_category.parent
== category.id)).select(db.store_category.ALL) if i.parent == category.id
]) ]
The query returns any categories without a parent and adds them to the
menu. While doing so looks for any subcategories using the category as a
parent.
Hope that helps you out.
-James
On Tuesday, January 21, 2014 9:33:50 AM UTC+13, americ...@gmail.com wrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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[web2py] Re: Weird problems generating menu from database
First of all notice that if you use web2py2.8.2 you can do this:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.title)),
Field('parent_id','reference store_catalog'))
def menu_rec(items): return
[(x.title,None,URL('action',args=x.slug),menu_rec(x.children)) for x in
items or []]
response.menu = menu_rec(db(db.store_catalog).select().as_tree())
And you get a recursive menu with arbitrary depth and a web interface to
edit it with slugs.
On Tuesday, 21 January 2014 00:11:59 UTC-6, James Burke wrote:
Hi,
I managed to get one working a little while ago doing this. This has been
adapted for your situation, may require some tweaking:
_tables.py - model
db.define_table('store_catelog')
db.define_table('store_catelog',
Field('title', 'string'),
Field('description', 'text'),
Field('parent_catelog', 'reference store_catelog', default=None),
format='%(title)s',
redefine=True)
menu.py - model
response.menu = []
categories = db(db.store_catelog.parent == None).select(orderby=db.
store_catelog.id)
for category in categories:
response.menu+=[ (T(category.title), True if active_page == str(
category.title.lower()) else False, URL('default','page/%s' % (category.
title.lower())), [
(T(i.title), True if active_page == str(i.id) else False, URL(
'default','page/%s' % (i.id)), []) for i in db((db.stored_category.parent
== category.id)).select(db.store_category.ALL) if i.parent == category.id
]) ]
The query returns any categories without a parent and adds them to the
menu. While doing so looks for any subcategories using the category as a
parent.
Hope that helps you out.
-James
On Tuesday, January 21, 2014 9:33:50 AM UTC+13, americ...@gmail.com wrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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You received this message because you are subscribed to the Google Groups
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[web2py] Re: Weird problems generating menu from database
I am unable to make it past the point of the database definition. I put
exactly what you have below in my db.py, and in my menu.py I left
response.menu=[] so that I could populate the database because the function
def menu_rec doesn't have anything so I thought to just avoid errors and
for simplicity sake start with the db. However immediately upon attempting
to put data in the field with the editor I get the same:
IntegrityError('FOREIGN KEY constraint failed',) error message.
Not sure how I can test/incorporate anything with both suggestions causing
an error immediately upon clicking submit for simply putting data in the
field as is needed.
Yes I am using the latest web2py 2.8.2.
Totally confused because I've never seen any of my database setups act like
that and I have a few other tables I setup for the products, etc. Not a
one has ever complained about a foreign key...
??
On Tuesday, January 21, 2014 9:45:27 AM UTC-6, Massimo Di Pierro wrote:
First of all notice that if you use web2py2.8.2 you can do this:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.title)),
Field('parent_id','reference store_catalog'))
def menu_rec(items): return
[(x.title,None,URL('action',args=x.slug),menu_rec(x.children)) for x in
items or []]
response.menu = menu_rec(db(db.store_catalog).select().as_tree())
And you get a recursive menu with arbitrary depth and a web interface to
edit it with slugs.
On Tuesday, 21 January 2014 00:11:59 UTC-6, James Burke wrote:
Hi,
I managed to get one working a little while ago doing this. This has been
adapted for your situation, may require some tweaking:
_tables.py - model
db.define_table('store_catelog')
db.define_table('store_catelog',
Field('title', 'string'),
Field('description', 'text'),
Field('parent_catelog', 'reference store_catelog', default=None),
format='%(title)s',
redefine=True)
menu.py - model
response.menu = []
categories = db(db.store_catelog.parent == None).select(orderby=db.
store_catelog.id)
for category in categories:
response.menu+=[ (T(category.title), True if active_page == str(
category.title.lower()) else False, URL('default','page/%s' % (category.
title.lower())), [
(T(i.title), True if active_page == str(i.id) else False, URL(
'default','page/%s' % (i.id)), []) for i in db((db.stored_category.parent
== category.id)).select(db.store_category.ALL) if i.parent == category.id
]) ]
The query returns any categories without a parent and adds them to the
menu. While doing so looks for any subcategories using the category as a
parent.
Hope that helps you out.
-James
On Tuesday, January 21, 2014 9:33:50 AM UTC+13, americ...@gmail.comwrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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[web2py] Re: Weird problems generating menu from database
My code above seems to only be lacking the proper embedded if conditional
statement. I am able to output the same info I need without repeating it
like in this example:
rows = db(db.store_categories).select()
for menucatchoice in rows:
if menucatchoice['subcategory'] == '':
print Main - %s % menucatchoice['maincategory']
if menucatchoice['subcategory']:
print SubCategory -- %s % menucatchoice['subcategory']
Which prints out:
Main - Animals
SubCategory -- Dogs
SubCategory -- Cats
Why can't I get it to go like that with my code above?
My code is much smaller and actually works for seeing what happens.
With the suggested code that isn't working I'm unable to see anything and
therefore unable to even debug it since it crashes immediately.
Also I was wondering if there was any actual way to see what MENU helper
actually sees, and not just using the shell. For example when you click on
the response in the ticket it shows the menu but doesn't show the actual
received output. When I view that in the shell and make adjustments such
as adding/subtracting []] or similar it is difficult to deduce what MENU
has determined as a link, false, or whatever. I have also tried other
variations such as:
menu.py
response.menu = [T('Catalog'), False, '',[]]
maininfo=db(db.store_categories.subcategory=='').select(db.store_categories.maincategory)
for maincat in maininfo:
response.menu[-1]+=([(T(maincat.maincategory)), False, 'link'])
for subcat in
db(db.store_categories.subcategory!='').select(db.store_categories.subcategory):
response.menu[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
Which gets me this in the shell:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
[lazyT 'Dogs', False, 'link'],
[lazyT 'Cats', False, 'link']]]
And for the astute observer you can see the correct way (i statically
created and works):
[(lazyT 'Catalog',
False,
'',
[(lazyT 'Animals',
False,
'/beta/default/Animals',
[(lazyT 'Dogs', False, '/beta/default/Dogs'),
(lazyT 'Cats', False, '/beta/default/Cats')])])]
You can see the slight differences so obviously I am very close. For
further clarity for myself and anyone else reading this(it has become clear
others have tried this extensively), you can see I need to have one less
bracket (if I'm correct). I say this because in the working/correct
version you can clearly see that the last entry (lazyT 'Cats', False,
'/beta/default/Cats')])])] is missing the bracket that my generated one
has [lazyT 'Cats', False, 'link']]]. I realize the () aren't the
same however I noticed that in the shell unless the structure shows
correctly as outlined above that it does not work regardless of the ().
You can also see that the bracket only encompasses the subcategories. So
I'm wondering how I can get that one bracket out of here (again if I'm
correct about the format). I appreciate all the code samples but, it
appears I'm doing something trivially wrong which doesn't suffice replacing
the whole thing for (in my opinion due to one bracket being off).
On Monday, January 20, 2014 2:33:50 PM UTC-6, web2pygroup wrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
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[web2py] Re: Weird problems generating menu from database
Here's what I've tried so far and here's the results if it helps any to get
me on the right track, plus I hope this helps someone else looking for this
to because this is something very commonly done in PHP.
I have tried changing this:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3[-1]+=([(T(subcat.subcategory)), False, 'link',])
Which changes the output in the shell to:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
Which obviously isn't correct.
Continuing:
original:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
Gives this in the shell output:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals', False, 'link'],
[lazyT 'Dogs', False, 'link'],
[lazyT 'Cats', False, 'link']]
Again obviously incorrect. Continuing:
original:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
changed:
response.menu3[-1]+=((T(subcat.subcategory)), False, 'link',)
Shell output shows:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
I tried additional variations but, not sure how much space we have here to
keep going with my 2 weeks worth of work. Essentially the end result is
the same a bracket missing to seperate the subcategories. I've been able
to modify and add to lists before, however I've never really experienced a
situation where the negative slice appears to be ignored (removing the
bracket at the end of dogs and beginning of cats as it is doing for the
main category Animals as can be seen), even removed the negative slice
([-1]) for the main categories iteration and when I do it clearly shows
that it is actually doing the negative slice properly because the brackets
come back at the end of Animals, unlike the subcategories that do not
appear to be removing the bracket(s)
On Monday, January 20, 2014 2:33:50 PM UTC-6, web2pygroup wrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
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[web2py] Re: Weird problems generating menu from database
Sorry, I had the parent declared as catelog_parent in the table. If you
change it to parent it should work ;)
Also += is the same as append.
On Wednesday, January 22, 2014 3:35:29 AM UTC+13, web2pygroup wrote:
I attempted to copy/paste what you have so I can modify it for my needs.
However it immediately errors out with:
AttributeError: 'Table' object has no attribute 'parent'
So I thought I would comment out everything for the menu except
response.menu = [] and populate the database (have done this before and the
site comes up just no menu as expected).
I then decided to try and populate the database fields.
However when I try to populate it I immediately get an error
IntegrityError: FOREIGN KEY constraint failed. What I did was, put
Animals for the title, for description I put Main Animals Category,
then for the parent catelog I put Animals again. Upon seeing this I'm
confused as to how a subcategory would get identified. So I also tried
just putting Animals for the title, and filling in the description as
above, but leaving the parent catelog blank, it to also failed with exactly
the same error IntegrityError: FOREIGN KEY constraint failed. So
effectively I'm unable to even put anything in the fields, an issue I never
had so I'm unsure what the problem is.
Would it be possible to use the fields I have already established to
populate the menu? Since you have 3 fields identified in your table albeit
with slight differences, would it be possible to somehow incorporate that
into what I have? Could you also explain why you used += instead of
append? Maybe I could figure out something from that.
Thanks
On Tuesday, January 21, 2014 12:11:59 AM UTC-6, James Burke wrote:
Hi,
I managed to get one working a little while ago doing this. This has been
adapted for your situation, may require some tweaking:
_tables.py - model
db.define_table('store_catelog')
db.define_table('store_catelog',
Field('title', 'string'),
Field('description', 'text'),
Field('parent_catelog', 'reference store_catelog', default=None),
format='%(title)s',
redefine=True)
menu.py - model
response.menu = []
categories = db(db.store_catelog.parent == None).select(orderby=db.
store_catelog.id)
for category in categories:
response.menu+=[ (T(category.title), True if active_page == str(
category.title.lower()) else False, URL('default','page/%s' % (category.
title.lower())), [
(T(i.title), True if active_page == str(i.id) else False, URL(
'default','page/%s' % (i.id)), []) for i in db((db.stored_category.parent
== category.id)).select(db.store_category.ALL) if i.parent == category.id
]) ]
The query returns any categories without a parent and adds them to the
menu. While doing so looks for any subcategories using the category as a
parent.
Hope that helps you out.
-James
On Tuesday, January 21, 2014 9:33:50 AM UTC+13, americ...@gmail.comwrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
You received this message because you are subscribed to the Google Groups
web2py-users group.
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[web2py] Re: Weird problems generating menu from database
Getting:
global name 'active_page' is not defined
What did you have for that so I can incorporate it? Or do I even need that
since I'm not really caring at the moment about which page they're on (if I
understand that variable correctly). How would I remove it to still
achieve the same effect? Thanks
On Tuesday, January 21, 2014 12:29:04 PM UTC-6, James Burke wrote:
Sorry, I had the parent declared as catelog_parent in the table. If you
change it to parent it should work ;)
Also += is the same as append.
On Wednesday, January 22, 2014 3:35:29 AM UTC+13, web2pygroup wrote:
I attempted to copy/paste what you have so I can modify it for my needs.
However it immediately errors out with:
AttributeError: 'Table' object has no attribute 'parent'
So I thought I would comment out everything for the menu except
response.menu = [] and populate the database (have done this before and the
site comes up just no menu as expected).
I then decided to try and populate the database fields.
However when I try to populate it I immediately get an error
IntegrityError: FOREIGN KEY constraint failed. What I did was, put
Animals for the title, for description I put Main Animals Category,
then for the parent catelog I put Animals again. Upon seeing this I'm
confused as to how a subcategory would get identified. So I also tried
just putting Animals for the title, and filling in the description as
above, but leaving the parent catelog blank, it to also failed with exactly
the same error IntegrityError: FOREIGN KEY constraint failed. So
effectively I'm unable to even put anything in the fields, an issue I never
had so I'm unsure what the problem is.
Would it be possible to use the fields I have already established to
populate the menu? Since you have 3 fields identified in your table albeit
with slight differences, would it be possible to somehow incorporate that
into what I have? Could you also explain why you used += instead of
append? Maybe I could figure out something from that.
Thanks
On Tuesday, January 21, 2014 12:11:59 AM UTC-6, James Burke wrote:
Hi,
I managed to get one working a little while ago doing this. This has
been adapted for your situation, may require some tweaking:
_tables.py - model
db.define_table('store_catelog')
db.define_table('store_catelog',
Field('title', 'string'),
Field('description', 'text'),
Field('parent_catelog', 'reference store_catelog', default=None),
format='%(title)s',
redefine=True)
menu.py - model
response.menu = []
categories = db(db.store_catelog.parent == None).select(orderby=db.
store_catelog.id)
for category in categories:
response.menu+=[ (T(category.title), True if active_page == str(
category.title.lower()) else False, URL('default','page/%s' % (category.
title.lower())), [
(T(i.title), True if active_page == str(i.id) else False, URL(
'default','page/%s' % (i.id)), []) for i in db((db.stored_category.parent
== category.id)).select(db.store_category.ALL) if i.parent == category.
id
]) ]
The query returns any categories without a parent and adds them to the
menu. While doing so looks for any subcategories using the category as a
parent.
Hope that helps you out.
-James
On Tuesday, January 21, 2014 9:33:50 AM UTC+13, americ...@gmail.comwrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category
and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
-
[web2py] Re: Weird problems generating menu from database
You could simply declare it for testing purposes. Set it to false. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
[web2py] Re: Weird problems generating menu from database
Ok that works, and I'm curious about that variable if you could please
explain maybe I could use it and not have to ask to many more questions :)
Also I was wondering how I could incorporate what I had also posted
originally - ([T('
Catalog'), False, '' - where this was the heading for the menu then the
rest of the items come after it. So instead of animals being first it
would show catalog, then when the user puts the mouse over it drops down
showing, animals, etc.
I tried changing the brackets around but to no avail. Any pointers? I
tried using what I had originally created but all it does is create a
seperate catalog right next to animals on the navbar with animals
being the only thing doing the drop down.
Thanks again for your code it was nice to see it working unlike mine.
On Tuesday, January 21, 2014 12:52:35 PM UTC-6, James Burke wrote:
You could simply declare it for testing purposes.
Set it to false.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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[web2py] Re: Weird problems generating menu from database
I decided to try and make Catalog my first choice in the menu by setting it as the first entry in the DB. Then I put Animals with Catalog as its parent, then I added Dogs and set that with Animals as the parent. Unfortunately it does not show the Dogs category. Have I possibly done something? I'm not seeing Dogs in the shell when I look at the response.menu... I do see it in the DB though. On Tuesday, January 21, 2014 12:52:35 PM UTC-6, James Burke wrote: You could simply declare it for testing purposes. Set it to false. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
[web2py] Re: Weird problems generating menu from database
I have also been trying your solution and have gotten to this point, when I
try to run the shell to test it errors out immediately with:
AttributeError: 'Rows' object has no attribute 'as_tree'
Any hints on how to fix? Or something else I might try? I do have the
2.8.2 version.. I noticed when I do a db.store_catalog.tab key (within
ipython2) I get this as options .as_dict, as_json, .as_xml, .as_yaml. The
only thing I'm familiar with that might be a tree is the .as_xml, is that
what you meant?
Thanks for any/all time you can help it's greatly appreciated!
On Tuesday, January 21, 2014 9:45:27 AM UTC-6, Massimo Di Pierro wrote:
First of all notice that if you use web2py2.8.2 you can do this:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.title)),
Field('parent_id','reference store_catalog'))
def menu_rec(items): return
[(x.title,None,URL('action',args=x.slug),menu_rec(x.children)) for x in
items or []]
response.menu = menu_rec(db(db.store_catalog).select().as_tree())
And you get a recursive menu with arbitrary depth and a web interface to
edit it with slugs.
On Tuesday, 21 January 2014 00:11:59 UTC-6, James Burke wrote:
Hi,
I managed to get one working a little while ago doing this. This has been
adapted for your situation, may require some tweaking:
_tables.py - model
db.define_table('store_catelog')
db.define_table('store_catelog',
Field('title', 'string'),
Field('description', 'text'),
Field('parent_catelog', 'reference store_catelog', default=None),
format='%(title)s',
redefine=True)
menu.py - model
response.menu = []
categories = db(db.store_catelog.parent == None).select(orderby=db.
store_catelog.id)
for category in categories:
response.menu+=[ (T(category.title), True if active_page == str(
category.title.lower()) else False, URL('default','page/%s' % (category.
title.lower())), [
(T(i.title), True if active_page == str(i.id) else False, URL(
'default','page/%s' % (i.id)), []) for i in db((db.stored_category.parent
== category.id)).select(db.store_category.ALL) if i.parent == category.id
]) ]
The query returns any categories without a parent and adds them to the
menu. While doing so looks for any subcategories using the category as a
parent.
Hope that helps you out.
-James
On Tuesday, January 21, 2014 9:33:50 AM UTC+13, americ...@gmail.comwrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
You received this message because you are subscribed to the Google Groups
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[web2py] Re: Weird problems generating menu from database
Ok figured out I needed to change that to as_trees. However the database
suggestion you gave is causing a
IntegrityError: FOREIGN KEY constraint failed
error immediately upon trying to put any data into any field. For example
if I put Animals in the title and leave the other field parent_id blank
it gives me the error. If I put a number in parent_id with the title an
error, and if I just put a number in the parent_id field also an error.
Any ideas?
Thanks
On Tuesday, January 21, 2014 9:45:27 AM UTC-6, Massimo Di Pierro wrote:
First of all notice that if you use web2py2.8.2 you can do this:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.title)),
Field('parent_id','reference store_catalog'))
def menu_rec(items): return
[(x.title,None,URL('action',args=x.slug),menu_rec(x.children)) for x in
items or []]
response.menu = menu_rec(db(db.store_catalog).select().as_tree())
And you get a recursive menu with arbitrary depth and a web interface to
edit it with slugs.
On Tuesday, 21 January 2014 00:11:59 UTC-6, James Burke wrote:
Hi,
I managed to get one working a little while ago doing this. This has been
adapted for your situation, may require some tweaking:
_tables.py - model
db.define_table('store_catelog')
db.define_table('store_catelog',
Field('title', 'string'),
Field('description', 'text'),
Field('parent_catelog', 'reference store_catelog', default=None),
format='%(title)s',
redefine=True)
menu.py - model
response.menu = []
categories = db(db.store_catelog.parent == None).select(orderby=db.
store_catelog.id)
for category in categories:
response.menu+=[ (T(category.title), True if active_page == str(
category.title.lower()) else False, URL('default','page/%s' % (category.
title.lower())), [
(T(i.title), True if active_page == str(i.id) else False, URL(
'default','page/%s' % (i.id)), []) for i in db((db.stored_category.parent
== category.id)).select(db.store_category.ALL) if i.parent == category.id
]) ]
The query returns any categories without a parent and adds them to the
menu. While doing so looks for any subcategories using the category as a
parent.
Hope that helps you out.
-James
On Tuesday, January 21, 2014 9:33:50 AM UTC+13, americ...@gmail.comwrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
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[web2py] Re: Weird problems generating menu from database
Sorry typo. Let's try again:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.titl\
e)),
Field('parent_id','reference store_catalog'))
id1 = db.store_catalog.insert(title='main')
id2 = db.store_catalog.insert(title='one',parent_id=id1)
id3 = db.store_catalog.insert(title='two',parent_id=id2)
def menu_rec(items): return
[(x.title,None,URL('action',args=x.slug),menu_rec(x\
.children)) for x in items or []]
response.menu = menu_rec(db(db.store_catalog).select().as_trees())
print response.menu
On Tuesday, 21 January 2014 12:17:19 UTC-6, web2pygroup wrote:
Here's what I've tried so far and here's the results if it helps any to
get me on the right track, plus I hope this helps someone else looking for
this to because this is something very commonly done in PHP.
I have tried changing this:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3[-1]+=([(T(subcat.subcategory)), False, 'link',])
Which changes the output in the shell to:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
Which obviously isn't correct.
Continuing:
original:
response.menu3[-1]+=([[(T(subcat.subcategory)), False, 'link',]])
to this:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
Gives this in the shell output:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals', False, 'link'],
[lazyT 'Dogs', False, 'link'],
[lazyT 'Cats', False, 'link']]
Again obviously incorrect. Continuing:
original:
response.menu3+=([[(T(subcat.subcategory)), False, 'link',]])
changed:
response.menu3[-1]+=((T(subcat.subcategory)), False, 'link',)
Shell output shows:
[lazyT 'Catalog',
False,
'',
[lazyT 'Animals',
False,
'link',
lazyT 'Dogs',
False,
'link',
lazyT 'Cats',
False,
'link']]
I tried additional variations but, not sure how much space we have here to
keep going with my 2 weeks worth of work. Essentially the end result is
the same a bracket missing to seperate the subcategories. I've been able
to modify and add to lists before, however I've never really experienced a
situation where the negative slice appears to be ignored (removing the
bracket at the end of dogs and beginning of cats as it is doing for the
main category Animals as can be seen), even removed the negative slice
([-1]) for the main categories iteration and when I do it clearly shows
that it is actually doing the negative slice properly because the brackets
come back at the end of Animals, unlike the subcategories that do not
appear to be removing the bracket(s)
On Monday, January 20, 2014 2:33:50 PM UTC-6, web2pygroup wrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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[web2py] Re: Weird problems generating menu from database
Hi,
I managed to get one working a little while ago doing this. This has been
adapted for your situation, may require some tweaking:
_tables.py - model
db.define_table('store_catelog')
db.define_table('store_catelog',
Field('title', 'string'),
Field('description', 'text'),
Field('parent_catelog', 'reference store_catelog', default=None),
format='%(title)s',
redefine=True)
menu.py - model
response.menu = []
categories = db(db.store_catelog.parent == None).select(orderby=db.
store_catelog.id)
for category in categories:
response.menu+=[ (T(category.title), True if active_page == str(category
.title.lower()) else False, URL('default','page/%s' % (category.title.lower
())), [
(T(i.title), True if active_page == str(i.id) else False, URL(
'default','page/%s' % (i.id)), []) for i in db((db.stored_category.parent
==category
.id)).select(db.store_category.ALL) if i.parent == category.id
]) ]
The query returns any categories without a parent and adds them to the
menu. While doing so looks for any subcategories using the category as a
parent.
Hope that helps you out.
-James
On Tuesday, January 21, 2014 9:33:50 AM UTC+13, americ...@gmail.com wrote:
Hi all,
I have been trying for a little over 2 weeks to figure this out...
I'm trying to generate a menu that drops down, I have been able to
statically create it by overwriting sample app that has the same drop down
menu like the web2py.com site.
I have this in my db.py:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
in my menu.py I have gotten this so far:
response.menu=[]
response.menu.append([T('Catalog'), False, '',
[(T('%s' % menucatchoice['maincategory']), False, 'link',
[(T('%s' % menucatchoice['subcategory']), False,
'link'),]) for menucatchoice in rows ] ])
It gets me a drop down menu except that for each subcategory it repeats
adding it to the main category. Let's say there is only 1 main category and
2 subs that go after that
Catalog (this just shows with the caret next to it as intended)
MainCategory
Sub
Sub
What I have does put the Catalog for the first but, what I get is:
MainCategory
(blank)
MainCategory(don't want this it's being repeated)
Subcategory
MainCategory(and this one is also a repeat)
Subcategory
I have tried to break out the response.menu with so many different
.appends it's not funny. I have also tried adding the [-1]. This was
the closest I have gotten to what I want it to look like. I'm at an
absolute loss on this, any and all help would be greatly appreciated.
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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