Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-05 Thread Carfield Yim
On 1/5/07, Matej Knopp <[EMAIL PROTECTED]> wrote:
> Navigating to different page is a bit tricky unfortunately. There is no
> easy way of disabling the alert. This should be addressed in future
> version. For now I'd suggest you to try to close the window
> (ModalWindow.close(...)) and navigate to the target page in modal window
> onclose handler.
>
Thx, that should work for me

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Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-05 Thread Matej Knopp
Navigating to different page is a bit tricky unfortunately. There is no 
easy way of disabling the alert. This should be addressed in future 
version. For now I'd suggest you to try to close the window 
(ModalWindow.close(...)) and navigate to the target page in modal window 
onclose handler.

-Matej

Carfield Yim wrote:
> Ok, I finally find out what going wrong, it is the AjaxSubmitButton
> only trigger the onError() method but not onSubmit() method, is it the
> excepted behaviour?
> 
> By the way, after the form process finished it will forward to another
> page ( actually after add a new account it will redirect to edit page
> of that account ) . It work ok but wicket will popup an alarm box
> about ModalWindows closing, can I suppress this warning?
> 
> On 1/5/07, Igor Vaynberg <[EMAIL PROTECTED]> wrote:
>> On 1/4/07, Carfield Yim <[EMAIL PROTECTED]> wrote:
>>> On 1/4/07, Igor Vaynberg <[EMAIL PROTECTED]> wrote:
 you click on the wicket ajax debug link at the bottom of the page and it
 should open. then look for errors in the output.

>>> There is not error, just info, and I don't understand the meaning of
>>> those info message, do you know if there reference
>> you can paste the output if you want here
>>
 or better yet create a quickstart that reproduces the problem - that is
 probably the fastest way to get help

>>> quickstart? you mean a simple application and put it some where at web
>>> and post the link here?
>> yep
>>
>> -igor
>>
>>
>> -
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>>
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> 
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Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-05 Thread Carfield Yim
Ok, I finally find out what going wrong, it is the AjaxSubmitButton
only trigger the onError() method but not onSubmit() method, is it the
excepted behaviour?

By the way, after the form process finished it will forward to another
page ( actually after add a new account it will redirect to edit page
of that account ) . It work ok but wicket will popup an alarm box
about ModalWindows closing, can I suppress this warning?

On 1/5/07, Igor Vaynberg <[EMAIL PROTECTED]> wrote:
> On 1/4/07, Carfield Yim <[EMAIL PROTECTED]> wrote:
> > On 1/4/07, Igor Vaynberg <[EMAIL PROTECTED]> wrote:
> > > you click on the wicket ajax debug link at the bottom of the page and it
> > > should open. then look for errors in the output.
> > >
> > There is not error, just info, and I don't understand the meaning of
> > those info message, do you know if there reference
>
> you can paste the output if you want here
>
> > > or better yet create a quickstart that reproduces the problem - that is
> > > probably the fastest way to get help
> > >
> > quickstart? you mean a simple application and put it some where at web
> > and post the link here?
>
> yep
>
> -igor
>
>
> >
> -
> > Take Surveys. Earn Cash. Influence the Future of IT
> > Join SourceForge.net's Techsay panel and you'll get the chance to share
> your
> > opinions on IT & business topics through brief surveys - and earn cash
> >
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> > ___
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> >
>
>
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>
>

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Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-04 Thread Igor Vaynberg

On 1/4/07, Carfield Yim <[EMAIL PROTECTED]> wrote:


On 1/4/07, Igor Vaynberg <[EMAIL PROTECTED]> wrote:
> you click on the wicket ajax debug link at the bottom of the page and it
> should open. then look for errors in the output.
>
There is not error, just info, and I don't understand the meaning of
those info message, do you know if there reference



you can paste the output if you want here


or better yet create a quickstart that reproduces the problem - that is
> probably the fastest way to get help
>
quickstart? you mean a simple application and put it some where at web
and post the link here?



yep

-igor


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Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-04 Thread Carfield Yim
On 1/4/07, Igor Vaynberg <[EMAIL PROTECTED]> wrote:
> you click on the wicket ajax debug link at the bottom of the page and it
> should open. then look for errors in the output.
>
There is not error, just info, and I don't understand the meaning of
those info message, do you know if there reference

> or better yet create a quickstart that reproduces the problem - that is
> probably the fastest way to get help
>
quickstart? you mean a simple application and put it some where at web
and post the link here?

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Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-03 Thread Igor Vaynberg

you click on the wicket ajax debug link at the bottom of the page and it
should open. then look for errors in the output.

or better yet create a quickstart that reproduces the problem - that is
probably the fastest way to get help

-igor


On 1/3/07, Carfield Yim <[EMAIL PROTECTED]> wrote:


On 1/4/07, Igor Vaynberg <[EMAIL PROTECTED]> wrote:
> http://woogle.billen.dk/search/q/listview%20ajax
>
Have tried
http://cwiki.apache.org/WICKET/how-to-repaint-a-listview-via-ajax.html
but fail. How can I use the AJAX debug window to see what going wrong?

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Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-03 Thread Carfield Yim
On 1/4/07, Igor Vaynberg <[EMAIL PROTECTED]> wrote:
> http://woogle.billen.dk/search/q/listview%20ajax
>
Have tried 
http://cwiki.apache.org/WICKET/how-to-repaint-a-listview-via-ajax.html
but fail. How can I use the AJAX debug window to see what going wrong?

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Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-03 Thread Igor Vaynberg

http://woogle.billen.dk/search/q/listview%20ajax

sigh

-igor


On 1/3/07, Carfield Yim <[EMAIL PROTECTED]> wrote:


My gmail crop my message but I can see it at sourceforge archive... I
don't know why. So I just resend my message again in case another
people only see an empty message

I have refer to


http://www.wicket-library.com/wicket-examples/ajax?wicket:bookmarkablePage=:wicket.examples.ajax.builtin.FormPage

and


http://www.wicket-library.com/wicket-examples/ajax?wicket:bookmarkablePage=:wicket.examples.ajax.builtin.ClockPage


But I cannot make the ModalWIndow updatable, Basically it is a form
contain a listview which will update after the user make some search, I
added an AjaxSelfUpdatingTimerBehavior to that listview and try to make
it update after the form submit, but it don't work, would you let me
know what am I doing wrong? BTW, I have validate that
AjaxSubmitButton.onsubmit is executed


public NewAccount(String id) {
super(id);
WicketUtil.standardHeader(this);
add(new NewAccountForm("form"));
add(new FeedbackPanel("feedback"));
add(userListView = new ListView("users", userList) {
private static final long serialVersionUID = 1L;

public void populateItem(final ListItem listItem) {
final User user = (User) listItem.getModelObject();
listItem.add(new Link("href") {
private static final long serialVersionUID = 1L;

@Override
public void onClick() {
try {
final Account account = new Account();
account.setAccountID(WicketUtil.getAccountId());
WicketUtil.addAccountForUser(user, account);
redirectToInterceptPage(new Edit(account));
} catch (SQLException e) {
throw new RuntimeException(e);
}
}
}.add(new Label("label", user.getUsername(;
}
});
userListView.add(new
AjaxSelfUpdatingTimerBehavior(Duration.seconds(1)));
}

public final class NewAccountForm extends Form {
private static final long serialVersionUID = 1L;

private String keyword;

public String getKeyword() {
return keyword;
}

public String getKeywordWildcard() {
return keyword == null ? "%" : "%" + keyword.toLowerCase() +
"%";
}

public void setKeyword(String keyword) {
this.keyword = keyword;
}

public NewAccountForm(final String id) {
super(id);
final TextField username;
add(username = new RequiredTextField("keyword", new
PropertyModel(this, "keyword")));
add(new AjaxSubmitButton("ajax-submit-button", this) {
private static final long serialVersionUID = 1L;
protected void onSubmit(AjaxRequestTarget target, Form
form) {
try {
final boolean isNew =
Boolean.parseBoolean(getRequest().getParameter("isnew"));
if (isNew) {

if(UsernameValidator.userNameDuplication(username, null))
NewAccount.this.error("user with same
username already exist");
else {
final User user = new User();
user.setUsername(getKeyword());
final Account account = new Account();

account.setAccountID(WicketUtil.getAccountId());
if
(WicketUtil.addCustomer(NewAccount.this, user, account, true))
redirectToInterceptPage(new
Edit(account));
}
} else {
userList.clear();

userList.addAll(Application.sqlMap.queryForList("searchUserByNameOrEmail",

getKeywordWildcard()));
if (userList.size() > 0) {
NewAccount.this.info("Just click at the
username to add new account for that user");
}
userListView.modelChanged();
target.addComponent(userListView);
}
} catch (SQLException e) {
throw new RuntimeException(e);
}
}
});
}
}

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Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-03 Thread Carfield Yim
My gmail crop my message but I can see it at sourceforge archive... I
don't know why. So I just resend my message again in case another
people only see an empty message

I have refer to

http://www.wicket-library.com/wicket-examples/ajax?wicket:bookmarkablePage=:wicket.examples.ajax.builtin.FormPage

 and

http://www.wicket-library.com/wicket-examples/ajax?wicket:bookmarkablePage=:wicket.examples.ajax.builtin.ClockPage


But I cannot make the ModalWIndow updatable, Basically it is a form
contain a listview which will update after the user make some search, I
added an AjaxSelfUpdatingTimerBehavior to that listview and try to make
it update after the form submit, but it don't work, would you let me
know what am I doing wrong? BTW, I have validate that
AjaxSubmitButton.onsubmit is executed


public NewAccount(String id) {
super(id);
WicketUtil.standardHeader(this);
add(new NewAccountForm("form"));
add(new FeedbackPanel("feedback"));
add(userListView = new ListView("users", userList) {
private static final long serialVersionUID = 1L;

public void populateItem(final ListItem listItem) {
final User user = (User) listItem.getModelObject();
listItem.add(new Link("href") {
private static final long serialVersionUID = 1L;

@Override
public void onClick() {
try {
final Account account = new Account();
account.setAccountID(WicketUtil.getAccountId());
WicketUtil.addAccountForUser(user, account);
redirectToInterceptPage(new Edit(account));
} catch (SQLException e) {
throw new RuntimeException(e);
}
}
}.add(new Label("label", user.getUsername(;
}
});
userListView.add(new
AjaxSelfUpdatingTimerBehavior(Duration.seconds(1)));
}

public final class NewAccountForm extends Form {
private static final long serialVersionUID = 1L;

private String keyword;

public String getKeyword() {
return keyword;
}

public String getKeywordWildcard() {
return keyword == null ? "%" : "%" + keyword.toLowerCase() +
"%";
}

public void setKeyword(String keyword) {
this.keyword = keyword;
}

public NewAccountForm(final String id) {
super(id);
final TextField username;
add(username = new RequiredTextField("keyword", new
PropertyModel(this, "keyword")));
add(new AjaxSubmitButton("ajax-submit-button", this) {
private static final long serialVersionUID = 1L;
protected void onSubmit(AjaxRequestTarget target, Form
form) {
try {
final boolean isNew =
Boolean.parseBoolean(getRequest().getParameter("isnew"));
if (isNew) {

if(UsernameValidator.userNameDuplication(username, null))
NewAccount.this.error("user with same
username already exist");
else {
final User user = new User();
user.setUsername(getKeyword());
final Account account = new Account();

account.setAccountID(WicketUtil.getAccountId());
if
(WicketUtil.addCustomer(NewAccount.this, user, account, true))
redirectToInterceptPage(new
Edit(account));
}
} else {
userList.clear();

userList.addAll(Application.sqlMap.queryForList("searchUserByNameOrEmail",

getKeywordWildcard()));
if (userList.size() > 0) {
NewAccount.this.info("Just click at the
username to add new account for that user");
}
userListView.modelChanged();
target.addComponent(userListView);
}
} catch (SQLException e) {
throw new RuntimeException(e);
}
}
});
}
}

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Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-03 Thread Matej Knopp
This doesn't really make sense. Why are you using self updating
behavior? Why don't you just update the listview when user submits the
form? And you can't ajax-update a repeater (ListView) directly. You have
to put the listview to e.g. WebMarkupContainer and add the container to
the AjaxRequestTarget.

-Matej

Carfield Yim wrote:
> I have refer to
> 
> http://www.wicket-library.com/wicket-examples/ajax?wicket:bookmarkablePage=:wicket.examples.ajax.builtin.FormPage
> and
> http://www.wicket-library.com/wicket-examples/ajax?wicket:bookmarkablePage=:wicket.examples.ajax.builtin.ClockPage
> 
> But I cannot make the ModalWIndow updatable, Basically it is a form
> contain a listview which will update after the user make some search, I
> added an AjaxSelfUpdatingTimerBehavior to that listview and try to make
> it update after the form submit, but it don't work, would you let me
> know what am I doing wrong? BTW, I have validate that
> AjaxSubmitButton.onsubmit is executed
> 
> 
> public NewAccount(String id) {
> super(id);
> WicketUtil.standardHeader(this);
> add(new NewAccountForm("form"));
> add(new FeedbackPanel("feedback"));
> add(userListView = new ListView("users", userList) {
> private static final long serialVersionUID = 1L;
> 
> public void populateItem(final ListItem listItem) {
> final User user = (User) listItem.getModelObject();
> listItem.add(new Link("href") {
> private static final long serialVersionUID = 1L;
> 
> @Override
> public void onClick() {
> try {
> final Account account = new Account();
> account.setAccountID(WicketUtil.getAccountId());
> WicketUtil.addAccountForUser(user, account);
> redirectToInterceptPage(new Edit(account));
> } catch (SQLException e) {
> throw new RuntimeException(e);
> }
> }
> }.add(new Label("label", user.getUsername(;
> }
> });
> userListView.add(new
> AjaxSelfUpdatingTimerBehavior(Duration.seconds(1)));
> }
> 
> public final class NewAccountForm extends Form {
> private static final long serialVersionUID = 1L;
> 
> private String keyword;
> 
> public String getKeyword() {
> return keyword;
> }
> 
> public String getKeywordWildcard() {
> return keyword == null ? "%" : "%" + keyword.toLowerCase() +
> "%";
> }
> 
> public void setKeyword(String keyword) {
> this.keyword = keyword;
> }
> 
> public NewAccountForm(final String id) {
> super(id);
> final TextField username;
> add(username = new RequiredTextField("keyword", new
> PropertyModel(this, "keyword")));
> add(new AjaxSubmitButton("ajax-submit-button", this) {
> private static final long serialVersionUID = 1L;
> protected void onSubmit(AjaxRequestTarget target, Form
> form) {
> try {
> final boolean isNew =
> Boolean.parseBoolean(getRequest().getParameter("isnew"));
> if (isNew) {
> 
> if(UsernameValidator.userNameDuplication(username, null))
> NewAccount.this.error("user with same
> username already exist");
> else {
> final User user = new User();
> user.setUsername(getKeyword());
> final Account account = new Account();
> 
> account.setAccountID(WicketUtil.getAccountId());
> if
> (WicketUtil.addCustomer(NewAccount.this, user, account, true))
> redirectToInterceptPage(new
> Edit(account));
> }
> } else {
> userList.clear();
> 
> userList.addAll(Application.sqlMap.queryForList("searchUserByNameOrEmail",
> 
> getKeywordWildcard()));
> if (userList.size() > 0) {
> NewAccount.this.info("Just click at the
> username to add new account for that user");
> }
> userListView.modelChanged();
> target.addComponent(userListView);
> }
> } catch (SQLException e) {
> throw new RuntimeException(e);
> }
> }
> });
> }
> }
> 
> On 1/3/07, Martijn Dashorst <[EMAIL PROTECTED]> wrote:
>> You can't.
>>
>> You have to submit the form using ajax.
>>
>> Martijn
>>
>> On 1/3/07

Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-03 Thread Carfield Yim
I have refer to

http://www.wicket-library.com/wicket-examples/ajax?wicket:bookmarkablePage=:wicket.examples.ajax.builtin.FormPage
and
http://www.wicket-library.com/wicket-examples/ajax?wicket:bookmarkablePage=:wicket.examples.ajax.builtin.ClockPage

But I cannot make the ModalWIndow updatable, Basically it is a form
contain a listview which will update after the user make some search, I
added an AjaxSelfUpdatingTimerBehavior to that listview and try to make
it update after the form submit, but it don't work, would you let me
know what am I doing wrong? BTW, I have validate that
AjaxSubmitButton.onsubmit is executed


public NewAccount(String id) {
super(id);
WicketUtil.standardHeader(this);
add(new NewAccountForm("form"));
add(new FeedbackPanel("feedback"));
add(userListView = new ListView("users", userList) {
private static final long serialVersionUID = 1L;

public void populateItem(final ListItem listItem) {
final User user = (User) listItem.getModelObject();
listItem.add(new Link("href") {
private static final long serialVersionUID = 1L;

@Override
public void onClick() {
try {
final Account account = new Account();
account.setAccountID(WicketUtil.getAccountId());
WicketUtil.addAccountForUser(user, account);
redirectToInterceptPage(new Edit(account));
} catch (SQLException e) {
throw new RuntimeException(e);
}
}
}.add(new Label("label", user.getUsername(;
}
});
userListView.add(new
AjaxSelfUpdatingTimerBehavior(Duration.seconds(1)));
}

public final class NewAccountForm extends Form {
private static final long serialVersionUID = 1L;

private String keyword;

public String getKeyword() {
return keyword;
}

public String getKeywordWildcard() {
return keyword == null ? "%" : "%" + keyword.toLowerCase() +
"%";
}

public void setKeyword(String keyword) {
this.keyword = keyword;
}

public NewAccountForm(final String id) {
super(id);
final TextField username;
add(username = new RequiredTextField("keyword", new
PropertyModel(this, "keyword")));
add(new AjaxSubmitButton("ajax-submit-button", this) {
private static final long serialVersionUID = 1L;
protected void onSubmit(AjaxRequestTarget target, Form
form) {
try {
final boolean isNew =
Boolean.parseBoolean(getRequest().getParameter("isnew"));
if (isNew) {

if(UsernameValidator.userNameDuplication(username, null))
NewAccount.this.error("user with same
username already exist");
else {
final User user = new User();
user.setUsername(getKeyword());
final Account account = new Account();

account.setAccountID(WicketUtil.getAccountId());
if
(WicketUtil.addCustomer(NewAccount.this, user, account, true))
redirectToInterceptPage(new
Edit(account));
}
} else {
userList.clear();

userList.addAll(Application.sqlMap.queryForList("searchUserByNameOrEmail",

getKeywordWildcard()));
if (userList.size() > 0) {
NewAccount.this.info("Just click at the
username to add new account for that user");
}
userListView.modelChanged();
target.addComponent(userListView);
}
} catch (SQLException e) {
throw new RuntimeException(e);
}
}
});
}
}

On 1/3/07, Martijn Dashorst <[EMAIL PROTECTED]> wrote:
> You can't.
>
> You have to submit the form using ajax.
>
> Martijn
>
> On 1/3/07, Carfield Yim <[EMAIL PROTECTED]> wrote:
> > If I have a form inside a ModalWindow, submit the form will cause the
> > ModalWindow close. Can I prevent this behaviour?
> >
> >
-
> > Take Surveys. Earn Cash. Influence the Future of IT
> > Join SourceForge.net's Techsay panel and you'll get the chance to
share your
> > opinions on IT & business topics through brief surveys - and earn cash
> >
http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV
> > 

Re: [Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-03 Thread Martijn Dashorst
You can't.

You have to submit the form using ajax.

Martijn

On 1/3/07, Carfield Yim <[EMAIL PROTECTED]> wrote:
> If I have a form inside a ModalWindow, submit the form will cause the
> ModalWindow close. Can I prevent this behaviour?
>
> -
> Take Surveys. Earn Cash. Influence the Future of IT
> Join SourceForge.net's Techsay panel and you'll get the chance to share your
> opinions on IT & business topics through brief surveys - and earn cash
> http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV
> ___
> Wicket-user mailing list
> Wicket-user@lists.sourceforge.net
> https://lists.sourceforge.net/lists/listinfo/wicket-user
>


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-
Take Surveys. Earn Cash. Influence the Future of IT
Join SourceForge.net's Techsay panel and you'll get the chance to share your
opinions on IT & business topics through brief surveys - and earn cash
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[Wicket-user] Submit a form at ModalWindow cause the ModalWindow close.

2007-01-03 Thread Carfield Yim
If I have a form inside a ModalWindow, submit the form will cause the
ModalWindow close. Can I prevent this behaviour?

-
Take Surveys. Earn Cash. Influence the Future of IT
Join SourceForge.net's Techsay panel and you'll get the chance to share your
opinions on IT & business topics through brief surveys - and earn cash
http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV
___
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