Re: [Wien] question about optical properties

2014-11-09 Thread Mona Rahimian


hi
I relax my supercell. when I want to initial my nano layer, I have this error 
in nn
 case.inst not consistent with Z 

edit case.inst and rerun lstart:
which parameter should be chang?
thanks
 
-- 

Mona Rahimian MSc Student

Physics Department,

College of Sciences

Shiraz University, Shiraz, Iran

E-mail address:rahimia...@ymail.com 




 From: ‪Peter Blaha‬ ‪pbl...@theochem.tuwien.ac.at‬
To: ‪A Mailing list for WIEN2k users‬ ‪wien@zeus.theochem.tuwien.ac.at‬ 
Sent: Tuesday, 28 October 2014, 4:41:30
Subject: Re: [Wien] question about optical properties
 


In practice they are the same.


In principle you have to calculate in addition the interband transitions 

(6 in joint) and get the plasma frequency.


This plasma frequency should be added as input in case.inkram, but I 

guess it is not programmed for a spin-polarized case.


As it concerns only a small region around E=0, you probably can forget 

it (it depends on what you want to calculate exactly.


On 10/07/2014 03:50 PM, ben amara imen wrote:

 Dear all ,



 I'm working on magnetic semiconductor: it is a half metal :  a

 semiconductor for spin up and a metal for spin down.



 When I calculate the optical properties , I do it for spin up ( a

 semiconducting aspect )  and for spin down ( metallic aspect) , then I

 addjoint the two spin up-dn

 *My question is:*

 The calculation steps are the same for spin up and down? there is no

 difference between them . I mean : in the case of spin down when the

 compound is a metal, I introduce the intraband transitions even if the

 compound is a semi metal??



 Waiting your reply and thanks in advance



 Best Regards

 Imen





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Re: [Wien] question about optical properties

2014-10-28 Thread Peter Blaha

In practice they are the same.

In principle you have to calculate in addition the interband transitions 
(6 in joint) and get the plasma frequency.


This plasma frequency should be added as input in case.inkram, but I 
guess it is not programmed for a spin-polarized case.


As it concerns only a small region around E=0, you probably can forget 
it (it depends on what you want to calculate exactly.


On 10/07/2014 03:50 PM, ben amara imen wrote:

Dear all ,

I'm working on magnetic semiconductor: it is a half metal :  a
semiconductor for spin up and a metal for spin down.

When I calculate the optical properties , I do it for spin up ( a
semiconducting aspect )  and for spin down ( metallic aspect) , then I
addjoint the two spin up-dn
*My question is:*
The calculation steps are the same for spin up and down? there is no
difference between them . I mean : in the case of spin down when the
compound is a metal, I introduce the intraband transitions even if the
compound is a semi metal??

Waiting your reply and thanks in advance

Best Regards
Imen


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--

  P.Blaha
--
Peter BLAHA, Inst.f. Materials Chemistry, TU Vienna, A-1060 Vienna
Phone: +43-1-58801-165300 FAX: +43-1-58801-165982
Email: bl...@theochem.tuwien.ac.atWIEN2k: http://www.wien2k.at
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[Wien] question about optical properties

2014-10-07 Thread ben amara imen
Dear all ,

I'm working on magnetic semiconductor: it is a half metal :  a
semiconductor for spin up and a metal for spin down.

When I calculate the optical properties , I do it for spin up ( a
semiconducting aspect )  and for spin down ( metallic aspect) , then I
addjoint the two spin up-dn
*My question is:*
The calculation steps are the same for spin up and down? there is no
difference between them . I mean : in the case of spin down when the
compound is a metal, I introduce the intraband transitions even if the
compound is a semi metal??

Waiting your reply and thanks in advance

Best Regards
Imen
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