Re: [Wikidata] CC-BY-SA
Okey, Just checking so let's say for: https://www.wikidata.org/wiki/Q2201 Narrative location (NY City) is from English Wikipedia, then it's CC BY SA? Thanks! On mar 12 2018, at 8:28 pm, Stas Malyshev wrote: > > Hi! > > Are all data that can be fetched via SPARQL CC0-licensed? > Data in the main namespace, without the use of federation - yes. > Federated data - https://query.wikidata.org/copyright.html, federated > endpoints can have different licenses, either CC0-like or CC-BY-SA like > (I don't think we accepted any that have anything stricter than that) > Category namespace - since it comes from Wikipedias, it's CC-BY-SA I > assume. > > -- > Stas Malyshev > smalys...@wikimedia.org > ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
Re: [Wikidata] CC-BY-SA
Oh okey, Thanks Stas! On mar 12 2018, at 8:55 pm, Stas Malyshev wrote: > > Hi! > > Just checking so let's say for: > > https://www.wikidata.org/wiki/Q2201 > > Narrative location (NY City) is from English Wikipedia, then it's CC BY SA? > > > No, it's CC0 since it's Wikidata data. Facts as such are not > copyrightable, so the fact that the particular movie is set in NYC is > not subject to any license. Specific arrangement (collection) of facts > can be copyrighted and licensed though and this specific one is > Wikidata, which is licensed under CC0. > > -- > Stas Malyshev > smalys...@wikimedia.org > ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
[Wikidata] CC-BY-SA
Hi, I have some questions, what namespaces are licensed under CC-BY-SA in the data? Are all data that can be fetched via SPARQL CC0-licensed? Thanks!___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
