I'm not sure I understand the question.  This script will generate a file
called "access" -- just place >this file in the file directory root of the
instance you need to access, make sure it has the correct >ownership
settings, and restart the instance.

Hi - Well I have a Zeo instance with a single zope instance within it which
is controlled by the scripts in /bin in the Zeo instance. When I ran the
zpasswd.py from within the zope instance it didn't affect the login for the
zope instance.

On 4/3/07, Ricardo Newbery <[EMAIL PROTECTED]> wrote:

 At 10:02 PM +0100 4/3/07, michael nt milne wrote:


On 4/3/07,* Ricardo Newbery* <[EMAIL PROTECTED]> wrote:

At 12:45 AM +0100 4/3/07, michael nt milne wrote:
>Hi
>
>I need to create an new user or an emergency user in a Zope instance
>outside of using ./zopectl adduser. I'm getting a 'resource not
>available' message for that. Is there another way of creating an
>emergency user in unix?


I haven't tried the zopectl method myself but I believe this is
supposed to create a real user with the Manager role -- this is not
an "emergency user" as the term is typically used.

If you mean instead to create an "emergency user", use the zpasswd.py
utility from the Zope installation.

  python zpasswd.py access

Read "SECURITY.txt" in your Zope installation for details.

Ric


thanks but how would you do change a pass for a zope instance within the
main instance using zpaasswd? it seems to control only the main instance



I'm not sure I understand the question.  This script will generate a file
called "access" -- just place this file in the file directory root of the
instance you need to access, make sure it has the correct ownership
settings, and restart the instance.

Incidentally, I believe you can also just create this file manually.  The
assumption is that if you have access to the file system, you naturally also
have permission to access the Zope instance.

Ric




--
michael
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