[Zope3-Users] Zope 3 Boot Camp early bird registration deadline near
The early bird registration deadline for Camp 5 and the BBQ Sprint is Wednesday, February 14: http://trizpug.org/boot-camp/camp5/ You can save $50 by registering early. Registration ends Friday March 2. -- Sincerely, Chris Calloway http://www.seacoos.org office: 332 Chapman Hall phone: (919) 962-4323 mail: Campus Box #3300, UNC-CH, Chapel Hill, NC 27599 ___ Zope3-users mailing list Zope3-users@zope.org http://mail.zope.org/mailman/listinfo/zope3-users
[Zope3-Users] Re: How do I get the schema/field list from an instance?
Vinny wrote: In a ZPT I would do something like: for field in fieldsInObject(row) # which has (ordered?) fields th cell: field.name for row in rowView for field in fieldsInObject(row) # which has (ordered?) fields td cell: field.value I know the above is broken in several ways. I've been trying various methods all evening. The closest I get is the __dict__ usage. Ideally, I would get the interface provided by the object and feed that to form.Fields() but I can't determine how to get an interface value that can be fed to form.Fields(). iface = zope.interface.providedBy(obj) doesn't seem to work. By itself it won't work. You'll have to do a bit more. First of all, an object can provide 0, 1 or more interfaces. Second, schemas are just interfaces whose specifications are fields (a schema can also have method specifications, there's no restriction to mixing a traditional interface with a schema). Therefore: for iface in zope.interface.providedBy(obj): for name in iface: field = iface[name] if zope.schema.interfaces.IField.providedBy(field): # you've got a schema field, now you can work with # field.title, field.description, etc. (see IField) -- http://worldcookery.com -- Professional Zope documentation and training Next Zope 3 training at Camp5: http://trizpug.org/boot-camp/camp5 ___ Zope3-users mailing list Zope3-users@zope.org http://mail.zope.org/mailman/listinfo/zope3-users
[Zope3-Users] formlib vs. cancel button
Hi, I really thought I knew how to do this, but now I can't get it to work and I'm really confused. I have a formlib EditForm, with an action like this: @form.action(Cancel, validator=lambda *args, **kwargs: True) def handle_cancel_action(self, action, data): nextURL = self.nextURL() if nextURL: self.request.response.redirect(self.nextURL()) return '' However, I still get validation errors when I click Cancel. I also tried a validator to return None, and no validator at all, and validator=None, they all have the same effect. Is there a proper/easy way of doing this? Martin ___ Zope3-users mailing list Zope3-users@zope.org http://mail.zope.org/mailman/listinfo/zope3-users
Re: [Zope3-Users] formlib vs. cancel button
I dont know if it is the proper way, but when I return an empty string there is no validation error. This was also one of the strangest things I found out with formlib. Dennis Martin Aspeli escribió: Hi, I really thought I knew how to do this, but now I can't get it to work and I'm really confused. I have a formlib EditForm, with an action like this: @form.action(Cancel, validator=lambda *args, **kwargs: True) def handle_cancel_action(self, action, data): nextURL = self.nextURL() if nextURL: self.request.response.redirect(self.nextURL()) return '' However, I still get validation errors when I click Cancel. I also tried a validator to return None, and no validator at all, and validator=None, they all have the same effect. Is there a proper/easy way of doing this? Martin ___ Zope3-users mailing list Zope3-users@zope.org http://mail.zope.org/mailman/listinfo/zope3-users ___ Zope3-users mailing list Zope3-users@zope.org http://mail.zope.org/mailman/listinfo/zope3-users
[Zope3-Users] Zope 3.3.1 released
On behalf of the Zope Foundation I'm happy to announce the release of Zope 3.3.1, a bugfix release for the current stable 3.3.x line. Zope 3.3.1 contains a number of bugfixes, though most importantly it fixes compatibility with Python 2.4.4. You can find more information as well as a tarball for Unix and a Windows installer at http://www.zope.org/Products/Zope3/3.3.1. -- http://worldcookery.com -- Professional Zope documentation and training Next Zope 3 training at Camp5: http://trizpug.org/boot-camp/camp5 ___ Zope3-users mailing list Zope3-users@zope.org http://mail.zope.org/mailman/listinfo/zope3-users
Re: [Zope3-Users] Re: How do I get the schema/field list from an instance?
On Wed, 14 Feb 2007 19:22:53 +0100
Philipp von Weitershausen wrote:
Vinny wrote:
In a ZPT I would do something like:
for field in fieldsInObject(row) # which has (ordered?) fields
th cell: field.name
for row in rowView
for field in fieldsInObject(row) # which has (ordered?) fields
td cell: field.value
I know the above is broken in several ways. I've been
trying various methods all evening. The closest I get
is the __dict__ usage. Ideally, I would get the
interface provided by the object and feed that to
form.Fields() but I can't determine how to get an
interface value that can be fed to form.Fields().
iface = zope.interface.providedBy(obj)
doesn't seem to work.
By itself it won't work. You'll have to do a bit more. First of all,
an object can provide 0, 1 or more interfaces. Second, schemas are
just interfaces whose specifications are fields (a schema can also
have method specifications, there's no restriction to mixing a
traditional interface with a schema). Therefore:
for iface in zope.interface.providedBy(obj):
for name in iface:
field = iface[name]
if zope.schema.interfaces.IField.providedBy(field):
# you've got a schema field, now you can work with
# field.title, field.description, etc. (see IField)
Thank you Philipp,
I have achieved my goal of a generic page template and
sql container view. There are a few quick questions in the
example code below. Mainly on being more efficient. Here
are the results for everyone to use/comment on. Note that
if anyone wants the rest of the files for this app., just
let me know and I'll see what I can arrange. I still have
to test it with more tables.
== iso639.py snippet =
from zope.publisher.browser import BrowserView
from zope.security.proxy import removeSecurityProxy
from zope.app import zapi
import zope.interface
from zope.sequencesort import sort
from zope.app.preference import UserPreferences
class SQLAlchemyContainerView(BrowserView):
def __init__(self, context, request):
self.context = context
self.request = request
def rowView(self):
Presumably I have an instance of SQLAlchemyContainer
We will be yielding a list of dictionaries with name and value keys.
Philipp von Weitershausen provided some help on how to get to the
schema/IField interface.
sqlRecordObjects = [sqlRecordObject for sqlRecordObject in
self.context.values()]
sort_on = (('lookup', 'nocase', 'asc'),)
sorted_rows = sort(sqlRecordObjects, sort=sort_on)
#userPreferences = UserPreferences()
#print userPreferences.hello.sorting.sortGroups
#sorted_rows = sort(sqlRecordObjects,
sort=userPreferences.hello.sorting.sortGroups)
for sqlRecordObject in sorted_rows:
sqlRecordObject = removeSecurityProxy(sqlRecordObject)
nameValues = [] # A list of two-term dictionaries
for iface in zope.interface.providedBy(sqlRecordObject):
for name in iface:
field = iface[name]
if zope.schema.interfaces.IField.providedBy(field):
# We've got a schema field, now we can work with
# field.title, field.description, etc. (see IField)
# Since we get a 'bonus' item in our schema called
__name__
# we must ignore it. We use a list containment
condition in
# case we want to expand the list of ignored
if field.__name__ in ['__name__']:
pass
else:
#print (field.__name__,
sqlRecordObject.__dict__[field.__name__], )
nameValues.append({'name': field.title, 'value':
sqlRecordObject.__dict__[field.__name__]})
#print nameValues[key]
# At this point we yield a list of dictionaries.
# The dictionary has keys 'name' and 'value' and their values are,
# respectively, the schema field title and
# the value of the sql record's column
yield nameValues
def fieldsInObject(self):
objlist = [obj for obj in self.context.values()]
#oneLang = self.context.values(0)
sqlRecordObject = removeSecurityProxy(objlist[0])
# Note: there *must* be a better way of getting
# just one value from the container. Anyone have a
# quick clue for me?
fieldCount = 0
# I imagine there is a better way of getting the
# number of fields in a schema than that shown below.
for iface in zope.interface.providedBy(sqlRecordObject):
for name in iface:
field = iface[name]
if zope.schema.interfaces.IField.providedBy(field):
