you can grow a collection implicitly using bracket notation.
quote:
If this element index is beyond the last existing element of the collection,
the collection is automatically resized and all new intermediary elements get
the null value
Hi Jim,
I haven't worked with Storage very much because frankly it's a pain and
it's slow. I get why it's a pain and has so much overhead. Every single
object has to have its own lock/unlock ('locker') mechanism and it works
between preemptive processes. So cool for that - no small thing. For me
On Sep 9, 2019, at 9:55 PM, Keisuke Miyako via 4D_Tech <4d_tech@lists.4d.com>
wrote:
>
>> So it looks like you can’t .push() a shared object onto a shared collection.
>
> not quite.
>
> a shared object is either single (solo) or multiple (once belonged to a group)
> if an object joins a group,
> So it looks like you can’t .push() a shared object onto a shared collection.
not quite.
a shared object is either single (solo) or multiple (once belonged to a group)
if an object joins a group, it is free to leave it, but it can't join another
group.
i.e. once you divorce your spouse,
you
So what doesn’t work is:
$sharedObj:=New Shared Collection
OB_CopyToSharedObject ($catalogObj;$sharedObj)
Use (Storage.MySharedCollection)
Storage.MySharedCollection.push($sharedObj)
End use
What does work is:
Storage.MySharedCollection.push(New shared object)
Use
I’m retrieving some info from an API that I’d like to cache, and I’m using v17,
so I thought Storage might be a nice alternative to a process or interprocess
variable. The first obstacle is that I can’t add an object from the API
response to a shared collection. I found a KB article with a
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