Re: [algogeeks] Re: question at K10

2011-02-16 Thread sunny agrawal
and also void change() { // Code here int x = 1; int*p= x; while(*p != 5) p++; *p = 10; } On Wed, Feb 16, 2011 at 8:02 AM, Balaji S balaji.ceg...@gmail.com wrote: The solution is.. _AX = 10; can anyone explain?? -- You received this message because you are subscribed to the

Re: [algogeeks] Re: question at K10

2011-02-16 Thread Balaji S
a one line solution is needed... -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more

[algogeeks] Re: question at K10

2011-02-16 Thread ankit sablok
AX is the low order accumulator register used in the microprocessor generally the value returned is from the accumulator if u modify that value it will return the value u set it to as the Register is Divided into 2 parts AH - higher order and AX - lower order the value 10 is stored in AX and is

[algogeeks] Re: question at K10

2011-02-16 Thread ankit sablok
nice solution On Feb 15, 11:22 pm, jagannath prasad das jpdasi...@gmail.com wrote: void change() {    #define i i=10,n} this will do.. On Tue, Feb 15, 2011 at 11:33 PM, Rel Guzman Apaza rgap...@gmail.comwrote: Nothing... 10 in base 5   =   5 in base 10. void change(){    

[algogeeks] Re: question at K10

2011-02-16 Thread Jammy
Nice solution. Similarly you could #define: void change() { #define change() i=10 } On Feb 16, 12:55 pm, ankit sablok ankit4...@gmail.com wrote: nice solution On Feb 15, 11:22 pm, jagannath prasad das jpdasi...@gmail.com wrote: void change() {    #define i i=10,n} this will

[algogeeks] Re: question at K10

2011-02-15 Thread Don
void change() { printf(10); while(1) {} } On Feb 15, 10:17 am, Balaji S balaji.ceg...@gmail.com wrote: Insert only one line in the function change() so that the output of the program is 10. You are not allowed to use exit(). You are not allowed to edit the function main() or to pass the

Re: [algogeeks] Re: question at K10

2011-02-15 Thread jalaj jaiswal
after termination of semicolon , that will be considered a separate line i guess On Tue, Feb 15, 2011 at 10:59 PM, Don dondod...@gmail.com wrote: void change() { printf(10); while(1) {} } On Feb 15, 10:17 am, Balaji S balaji.ceg...@gmail.com wrote: Insert only one line in the function

[algogeeks] Re: question at K10

2011-02-15 Thread Don
A semicolon is valid in the middle of a line in C or C++. For instance, no one says that for(i = 0; i 10; ++i) is three lines of code. Don On Feb 15, 11:31 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: after termination of semicolon , that will be considered a separate line i guess

Re: [algogeeks] Re: question at K10

2011-02-15 Thread Rel Guzman Apaza
Nothing... 10 in base 5 = 5 in base 10. void change(){ printf(); //...? } 2011/2/15 Don dondod...@gmail.com A semicolon is valid in the middle of a line in C or C++. For instance, no one says that for(i = 0; i 10; ++i) is three lines of code. Don On Feb 15, 11:31 am, jalaj

Re: [algogeeks] Re: question at K10

2011-02-15 Thread jagannath prasad das
void change() { #define i i=10,n } this will do.. On Tue, Feb 15, 2011 at 11:33 PM, Rel Guzman Apaza rgap...@gmail.comwrote: Nothing... 10 in base 5 = 5 in base 10. void change(){ printf(); //...? } 2011/2/15 Don dondod...@gmail.com A semicolon is valid in the middle of a

Re: [algogeeks] Re: question at K10

2011-02-15 Thread SUDHIR MISHRA
nice solution -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more

Re: [algogeeks] Re: question at K10

2011-02-15 Thread Balaji S
The solution is.. _AX = 10; can anyone explain?? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to