thanks
Megha Joshi wrote:
2008/8/26 Sylvester Steele [EMAIL PROTECTED]
Hi,
this might seem silly, but I can't get the SMS app to work. Issues:
1. Can't type in the To field. Worked around by selecting a contact
from the addressbook.
2. Can't type a message! How do I select
is there a way to type, while keeping it vertical?
Sylvester
On Aug 27, 8:36 pm, Sylvester Steele [EMAIL PROTECTED]
wrote:
thanks
Megha Joshi wrote:
2008/8/26 Sylvester Steele [EMAIL PROTECTED]
Hi,
this might seem silly, but I can't get the SMS app to work. Issues:
1. Can't type
Hi,
I want the user to be able to select text from the screen..much like
we do when we copy paste from one document to another. Is there an
easy way to do this? I need to know the exact string selected by the
user.
Thanks,
Sylvester
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You
I don't know how you have created your Adapter for supplying to your
ListView subclass. I am assuming that you implemented an Adapter
subclass
that overrode getView() and is returning your row objects on demand,
perhaps instantiated via ViewInflate.
arrayAdapter1= new ArrayAdapter String(this,
Mark, a couple of questions:
1. I looked at the getView funtcion:ViewgetView(int position,
View convertView, ViewGroup parent).
I can understand that position refers to the particular element on
the list and ViewGroup parent to the custom view I am using for the
list items. But what
It is unclear who this is in this.findViewById(R.id.dButton).
referred to the activity in the above post.
But changed it now to:
deleteButton1=
(Button)customComponent.findViewById(R.id.deleteButton);
customComponent is initialized as:
customComponent= new ConversationListView(this);
dButton= (Button)this.findViewById(R.id.dButton); is I think where it
problem is. I played around a bit with it and realized that other
functions were also throwing up an exception. Then I just created a
new button, using new Button(this); and it worked fine.
So, why is dButton=
I have a custom component with a texttView and a button. I want to
display this in a simple list.
customComponent = new conversationListView (this, blah);
arrayAdapter1= new ArrayAdapter String(this,
customComponent.getId(), customComponent.textView.getId());
I get an error saying some
Hi, I want to create an experimental custom component which consists
of just one EditText and one TextView. So I did this:
package com.customcomponent;
import android.app.Activity;
import android.content.Context;
import android.util.Log;
import android.widget.AbsoluteLayout;
import
I made the changes you suggested:
I got rid of the XML file. My calling class looks like:
Log.v(Main activity,before new CustomEditText (this));
customEditText = new CustomEditText (this);
//customEditText =
(CustomEditText)this.findViewById(R.layout.component);
1. It used to be that your custom component subclassed AbsoluteLayout.
If it still does, I suspect you cannot use LinearLayout.LayoutParams
with an AbsoluteLayout. You should make those consistent, either by
changing the superclass, or by changing the LayoutParams.
I just changed it from
((Cursor)fruitsAdapter.getItem(position)).getString(columnNo)
This works. Is this the right way?
Sylvester
On Jun 27, 11:52 pm, Mark Murphy [EMAIL PROTECTED] wrote:
ArrayAdapter does not create a Cursor behind the scenes.
Whoops, I think I was confusing two threads. Sorry about that.
--
Is it possible to get the phone number of an incoming call that is
currently ringing?
Thanks,
Sylvester
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Thanks.
Sylvester
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Actually, they both return a View. You need to cast the View to the
type
you created as your entries (e.g., TextView), then get the data out of
there (e.g., getText().toString()). If you're relying on the adapter's
built-in row types, they'll be TextView instances.
Yes, I did do that, it
Is there any way to get the item name at a particular position from a
ListView? If I can't get it from the listView itself, how do I do it?
the .getItem function returns a weird String, not the actual string
you see on the screen.
Sylvester
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My code is:
activity.setContentView(R.layout.contacts);
//activity.setContentView(R.id.contactsList);
String[] projection = new String[] {
android.provider.BaseColumns._ID,
android.provider.Contacts.PeopleColumns.NAME
I have also tried:
activity.setContentView(R.layout.contacts);
Cursor C = activity.getContentResolver().query(People.CONTENT_URI,
null, null, null, null);
activity.startManagingCursor(C);
String[] columns = new String[] {People.NAME};
int[] names = new int[]
Could there be any other problem?
Thanks,
Sylvester
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change the layout parameters from your
code using getLayoutParams() and then setting the height to the height
you computed dynamically.
Fine, but in that case what is the purpose of the setHeight function?
Is there any other way to display rather than setContentView for which
this function
() and then setting the height to the height
you computed dynamically. You may also use the android:layout_weight
attribute, provided by LinearLayout.
On Sun, Jun 8, 2008 at 8:07 PM, Sylvester Steele
[EMAIL PROTECTED] wrote:
Try putting your EditText inside a
LinearLayout, setting
I see a normal black background with white text. Basically no change.
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To
Hi,
I've been trying to display contacts in a list. Here's what I did:
activity.setContentView(R.layout.contacts);
String[] projection = new String[] {
android.provider.BaseColumns._ID,
hi,
I am trying to use System.out.print , but the console does not show
any output. My exact line is:
System.out.print(activity.getTitle().toString()); but I haven't had
luck with any other System.out.print(*whatever*); statement either.
1. Is there a better way of doing this?
2. Am I doing
Hi,
The cursorAdapter constructor format is really simple but its just not
working!
private CursorAdapter ABC;
ABC= new CursorAdapter (myCursor, myActivity);
note: the activity is passed on to this class from another class
the myCursor is not initialized, but is returned by a function ie i
Can you elaborate on how it is not working?
ABC= new __CursorAdapter__ (myCursor, myActivity);
__ - redline under that. message: can not instantiate the type
CursorAdapter
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I was tinkering around with it and realized that just extending the
Activity does not give the exception
What I do is:
1 A class that extends Activity starts executing.
2 it instantiates another class. The instantiated class does not take
any parameters in the constructor.
3 Inside the
The log shows this:
[2008-06-04 20:48:40 - begin1] --
[2008-06-04 20:48:40 - begin1] Android Launch!
[2008-06-04 20:48:40 - begin1] adb is running normally.
[2008-06-04 20:48:40 - begin1] Launching:
com.google.begin1Package.begin1Activity
[2008-06-04 20:48:40 -
I think I used inappropriate terminology. I am getting an exception
during runtime (as soon as it starts).
my java code is:
package com.google.begin1Package;
import android.app.Activity;
import android.os.Bundle;
import android.widget.*;
public class begin1Activity extends Activity {
A big thank you to you Mark! It works well now!
Sylvester Steele
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Is it possible to work with lists (ListView) without extending
ActivityList?
If not, does this mean that a different class has to be created just
to make a list?
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