Hi Marco,
Would you mind giving a brief code snippet of how this might work? I've been
trying to get a similar function to run faster but when I use the bitmap the
values I thought were written by the canvas aren't there.
Kind regards,
Gav
On Tue, Apr 21, 2009 at 12:21 AM, Marco Nelissen
- Create a mutable bitmap from immutable. But instead of a copy, just
create an empty one with the same width and height as the original
one.
- Create a canvas from this mutable bitmap (new Canvas(mutable));
- Create a ColorFilter object. Set its saturation to 0 (this is one
way of doing this).
Thanks for the fast response. I can't seem to saw the changes made by the
canvas in the original bitmap, my code is as follows;
int old = input.getPixel(0, 0);
Canvas c = new Canvas(input);
c.drawARGB(a, r, g, b);
int n = input.getPixel(0, 0);
if(old==n)
Are you sure your canvas' clip-rect is not empty?
Most calls to Canvas.clip() *intersect* with the old clip-
rect... not replace the old clip-rect.
Call Canvas.getClipBounds() to make sure.
On May 28, 2:44 pm, Gavin Aiken gavin.ai...@imperial.ac.uk wrote:
Thanks for the fast response. I
The problem is my Bitmap was immutable. I made it mutable.
I also used pixels array.
Initially by bitmap is taken from source. Then Im setting it to
mutable as follows:
mutable = immutable.copy(Config.RGB_565, true);
But now, my image is coming blue-scaled. Why?
Solved. The problem was in the parameters of Color.rgb.
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To
for(int y = 0; y imgH; y++)
for(int x = 0; x imgW; x++)
{
int color = bitmap.getPixel(x, y);
int r = (color 16) 0xff;
int g = (color 8) 0xff;
int b = color 0xff;
color = Color.rgb(r/3, g/3,
You can do this more efficiently by using a Paint and a ColorFilter.
On Mon, Apr 20, 2009 at 3:59 PM, sm12 mata...@gmail.com wrote:
Solved. The problem was in the parameters of Color.rgb.
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