I have not see Andriod code yet. But I think it has such API for your
reqirement.
Let's walk through a voice call prcess:
1, an incoming voice call happened.
2, Get caller number. Turn on LCD.
3, Search this number in current contact records DB (display number/
number on LCD).
Get sth. now? Yes,
For your second req, you can just dial this number like dial it with
keypad. I am sure you can answer this call with such API, because you
can call a message sender in Message/Email application. Call
application has such functions , I am sure, you just need call it and
start a voice call.
On
For your second req, you can just dial this number like dial it with
keypad. I am sure you can answer this call with such API, because you
can call a message sender in Message/Email application. Call
application has such functions , I am sure, you just need call it and
start a voice call.
On
It is not possible to intercept an incoming call in this manner in the
current release of the SDK.
-Megha
On Wed, May 7, 2008 at 8:56 PM, Trey Ethridge [EMAIL PROTECTED] wrote:
Let's say that I want to send a caller straight to voicemail if I'm
watching my favorite movie. Is it possible to
In current phone platform design(not only android), incoming call
almost has the highest priority in all user applications. Block your
movie player and back it again after voice call was ended is more
reasonable.
If you want watching your movie and don't want to accept this call,
you can just
I had the same need but i didn't find how to intercept the phone call
before ringing.
Secopnd need, once you have intercepted the phone call you can anlize
the phone number but
how to communicate with the caller and so implement a answering
machine, I look for library in the SDK and I din't find
A utility I wanted to make, but found unsupported by the current SDK,
was location based ring tones. A primary use model is to go to silent
mode whenever in concert/recital hall church or fishing. A secondary
use model is to adjust the sound type or volume to make sure the tone
could always be
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