Re: [AngularJS] ngrx

2019-05-04 Thread Ajeniya oladimeji
You can try this link https://malcoded.com/posts/angular-ngrx-guide/ Cheers On Sat, May 4, 2019, 6:28 PM Dev C wrote: > hello > > i want to kearn ngrx, could you please provide me link for this? ( easily > understable) > > thanks > devsur > > > -- > Sent from my mi note 4 phone. > > -- > You

[AngularJS] ngrx

2019-05-04 Thread Dev C
hello i want to kearn ngrx, could you please provide me link for this? ( easily understable) thanks devsur -- Sent from my mi note 4 phone. -- You received this message because you are subscribed to the Google Groups "Angular and AngularJS discussion" group. To unsubscribe from this group

Re: [AngularJS] Angular, call method sync

2019-05-04 Thread Scott Logsdon
You need to return the HTTP and Subscribe. Something like this. (UNTESTED) service getUtenti() : Utente[]{ > return this.http.get(this.API).then((data) => { > let output = data['utenti']; > for (var i = 0; i < output.length; i++) { > let utente = output[i]; >

Re: [AngularJS] Angular, call method sync

2019-05-04 Thread Scott Logsdon
You need to subscribe. Something like this (UNTESTED). service getUtenti() : Utente[]{ > return this.http.get(this.API).subscribe((data) => { > let output = data['utenti']; > for (var i = 0; i < output.length; i++) { > let utente = output[i]; >

Re: [AngularJS] Angular, call method sync

2019-05-04 Thread Scott Logsdon
You need to subscribe. Something like this (untested) ''' getUtenti() : Utente[]{ return this.http.get(this.API).subscribe((data) => { let output = data['utenti']; for (var i = 0; i < output.length; i++) { let utente = output[i];

Re: [AngularJS] Angular, call method sync

2019-05-04 Thread graydiamond87
Thanks Kalyan for you answer, In the end I used the async wait. Is it a good solution? Il giorno sabato 4 maggio 2019 06:12:55 UTC+2, Kalyan T ha scritto: > > Return http from service and subscribe it in component > > On Fri, 3 May, 2019, 8:53 AM , > wrote: > >> Hi everyone, >> I have recently