Type first; read manual second :-(
At least my mind is in the right place. I must be getting old. It used to be in
the gutter.
Charles
-Original Message-
From: IBM Mainframe Assembler List [mailto:ASSEMBLER-LIST@LISTSERV.UGA.EDU] On
Behalf Of Steve Smith
Sent: Thursday, April 28,
Your mind is in the right place, but your text is not. You can LGF or LLGF
a fullword into a full register. LG loads a doubleword, whether you point
it at one or not. i.e. an LG Rx,=X'87654321' results in x'87654321garbage'.
There now exist LGH, LH, LLGH, LLH, LGB, LB, LLGC, and LLC for all
64 bits is 64 bits whether the high bit is a sign or part of the number.
Loading 64 bits into a register loads 64 bits unaltered. The high bit becomes
the high bit, 0 or 1.
As @Gary says, it only matters when the sending field is smaller than the
receiving register. (And then only when the
When loading 8 bytes into an 64-bit register, you needn't worry about
logical vs. arithmetic. The sign only makes a difference if it's less
than a doubleword being loaded. An LG will load it..
On 2022-04-28 5:20 p.m., Schmitt, Michael wrote:
How did you do it in COBOL?
Gary Weinhold
Senior
No need for logical loading of an 8 byte number. There is no sign propagation,
so a simple LG will do. The, the arithmetic would use ALG, SLG, etc.
Keith Moe
BMC Software (retired in 33 days)
On Thursday, April 28, 2022, 02:20:56 PM PDT, Schmitt, Michael
wrote:
How did you do it
On Apr 28, 2022, at 15:20:16, Schmitt, Michael wrote:
> ...
>In case it makes a difference, this value is a timestamp (presumably
> from the store-clock instruction) but it is stored in an 8-byte file field.
> Now I need to take the file field and turn it into a date and a time
How did you do it in COBOL?
-Original Message-
From: IBM Mainframe Assembler List On Behalf
Of Dave Clark
Sent: Tuesday, February 1, 2022 11:39 AM
To: ASSEMBLER-LIST@LISTSERV.UGA.EDU
Subject: Unsigned 64-bit numbers
I previously asked about 32-bit unsigned numbers and that
