Re: [asterisk-users] if statement with true value that contains a colon

2019-09-13 Thread Brian J. Murrell 
On Fri, 2019-09-13 at 14:21 +0200, Administrator TOOTAI wrote:
> 
> Escape it with \

Tried that.  It doesn't work.

Cheers,
b.



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Re: [asterisk-users] if statement with true value that contains a colon

2019-09-13 Thread Administrator TOOTAI 

Le 13/09/2019 à 14:03, Brian J. Murrell a écrit :

How can I use an IF statement with a true value being a variable that
has a colon in it?  The colon in the true value variable is being taken
as the delimiter for the false value.

The only solution I came up with was some hackery to use STRREPLACE to
replace the : with a % before the IF statement and then use STRREPLACE
again after to change the % back to a :.

i.e.:

 Set(dialexts=${STRREPLACE(dialexts,:,%)});
 Set(dialexts=${IFTIME(8:00-22:00?${dialexts}&${MBDR}:${dialexts})});
 Set(dialexts=${STRREPLACE(dialexts,%,:)});


Is there no better alternative?


Escape it with \

--
Daniel

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[asterisk-users] if statement with true value that contains a colon

2019-09-13 Thread Brian J. Murrell 
How can I use an IF statement with a true value being a variable that
has a colon in it?  The colon in the true value variable is being taken
as the delimiter for the false value.

The only solution I came up with was some hackery to use STRREPLACE to
replace the : with a % before the IF statement and then use STRREPLACE
again after to change the % back to a :.

i.e.:

Set(dialexts=${STRREPLACE(dialexts,:,%)});
Set(dialexts=${IFTIME(8:00-22:00?${dialexts}&${MBDR}:${dialexts})});
Set(dialexts=${STRREPLACE(dialexts,%,:)});


Is there no better alternative?

Cheers,
b.



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