On Jun 15, 2001, Steve M. Robbins [EMAIL PROTECTED] wrote:
I normally want the program-specific flags _in addition_ to the
generic flags. So I *always* have $(LDADD) in $foo_LDADD.
But consider the case of not wanting $(LDADD) in foo_LDADD. Or
consider cases in which the order matters, and
Steve == Steve M Robbins [EMAIL PROTECTED] writes:
Steve Given the following Makefile.am
Steve bin_PROGRAMS = foo
Steve foo_SOURCES = foo.c sub/foo2.c
Steve it turns out that foo.c is compiled using $(COMPILE), and hence
Steve includes AM_CFLAGS. However, foo2.c is compiled *without*
Steve
Steve == Steve M Robbins [EMAIL PROTECTED] writes:
Steve The upshot is that foo.c is compiled using AM_CFLAGS but NOT
Steve foo_CFLAGS, while foo2.c is compiled NOT using AM_CFLAGS but using
Steve foo_CFLAGS.
I'm checking in a fix for this.
Tom
On Thu, Jun 14, 2001 at 06:51:09PM -0600, Tom Tromey wrote:
Steve == Steve M Robbins [EMAIL PROTECTED] writes:
Steve Given the following Makefile.am
Stevebin_PROGRAMS = foo
Stevefoo_SOURCES = foo.c sub/foo2.c
Steve it turns out that foo.c is compiled using $(COMPILE), and