>
> As always, thank you so much!
>
As always, you're welcome!
As a follow up, for my layman's thinking about XPath/XQuery, is this
>> effectively creating a sequence
>
>
It does. The expression is completely equivalent to, and just another
writing for: tokenize($s, "/").
Christian -
As always, thank you so much!
On Wed, Mar 31, 2021 at 10:35 AM Christian Grün
wrote:
> Dear Bridger,
>
> > I was wondering if anyone would have an insight for me as to why the
> following expression is wrong:
> >
> > for $s in ("/a/b/c", "/1/2/3")
> > let $t := $s =>
Dear Bridger,
> I was wondering if anyone would have an insight for me as to why the
> following expression is wrong:
>
> for $s in ("/a/b/c", "/1/2/3")
> let $t := $s => tokenize("/")[last()]
> return $t
This is due to the grammar rules of XQuery 3.1, which mandate that
“=>” is followed by an
Hi all -
I was wondering if anyone would have an insight for me as to why the
following expression is wrong:
```
for $s in ("/a/b/c", "/1/2/3")
let $t := $s => tokenize("/")[last()]
return $t
```
This is because of the predicate filter, but I'm not clear on *why* it's
because of that :)
Thanks
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