Hi Marcus
Sorry I think I made a mistake. I am not at my computer but pls try and put
a semicolon before the backslash in replace. So replace is semicolon plus
whatever was in brackets.
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On Fri, 10 May 2024 at 00:13, Marcus Abundis <55m...@gmail.com> wrote:
> Hi Kaveh,
>
>
Marcus,
I think that you may not realize that the backslash codes used in replacement
strings are not the same as the backslash codes used in search strings.
In a search string, there is a very rich collection of codes to describe the
things to be matched.
The result of the matching operation
Hi Kaveh,
Thanks much for your note!
Yeah, I see how " (\d\d\.\d\d\.\d\d\d\d, \d\d:\d\d, )" SHOULD work
with ";(\d\d\.\d\d\.\d\d\d\d, \d\d:\d\d, )" . . .
but I don't see how using a Backreference like "\1" applies to this
situation—how does this produce an ";" ?!
Am I missing something?
Can
Hey Rich,
Thanks much for looking at this issue!
Okay, I closely read the material in Chapter 8 and explored the Pattern
Playground, and I am pretty sure I understand what I read and saw.
I also feel I have a grasp of HOW wildcard Find and Replace commands are
SUPPOSED to work.
Using a
