--As of Thursday, September 9, 2004 9:24 AM -0500, Errin Larsen is alleged
to have said:
Excellent! Thank you. I knew it was something easy, just hadn't
kick-started my brain yet this morning. But I've got another one.
What if the user input, say, '007' on the command line? How can I
strip th
On Sep 9, Errin Larsen said:
>However, I need to pass that variable to another system command which
>expects any "day" value less than 10 to have a leading zero, so 7th
>day of the month should say '07'. How can I check for that leading
>zero? If it's missing, I know I could easily:
>
>$option =
Please bottom post
> Use the following:
>
> $option = "0" . $option if ($option / 10 < 1 && $option !~ /^0/);
>
Why divide by 10 first? Why not just check less than 10? Of course I
would probably drop the maths completely and use C,
perldoc -f sprintf
$option = sprintf('%02d', $option);
Excellent! Thank you. I knew it was something easy, just hadn't
kick-started my brain yet this morning. But I've got another one.
What if the user input, say, '007' on the command line? How can I
strip that off? I think I can check for it with something like this:
/^0?[1-9]/
But If I find i
Use the following:
$option = "0" . $option if ($option / 10 < 1 && $option !~ /^0/);
~Sid
On Thu, 9 Sep 2004 08:58:36 -0500, Errin Larsen <[EMAIL PROTECTED]> wrote:
> Hi All,
>
> I have a variable I'm reading off of the command line:
>
> my $option = shift;
>
> That variable should hold a num
