Re: bitwise xor operator - array

On Thu, Mar 20, 2008 at 2:17 AM, Rajanikanth Dandamudi <[EMAIL PROTECTED]> wrote: > > Hi Chas. Owens, > > Thanks a lot for the clarification. Finally I would like to understand how > to find that the character \x{01} is getting printed. It is not visible onto > the standard output display. snip

Re: bitwise xor operator - array

Hi Chas. Owens, Thanks a lot for the clarification. Finally I would like to understand how to find that the character \x{01} is getting printed. It is not visible onto the standard output display. Thanks and Regards, Rajanikanth -- Rajanikanth ASIC, Texas Instruments India Phone : +91-80-250

Re: bitwise xor operator - array

On Wed, Mar 19, 2008 at 9:32 AM, Rajanikanth Dandamudi <[EMAIL PROTECTED]> wrote: > Hi All, > > I would like to understand the behavior of the following program: snip > my @a=qw(1 0 0 0 0 0 0 1); > my @b=qw(0 0 0 0 0 0 0 0); snip > I would like to understand why $f does not have any value in th

bitwise xor operator - array

Hi All, I would like to understand the behavior of the following program: program start== #!/usr/local/bin/perl use strict; use integer; my @a=qw(1 0 0 0 0 0 0 1); my @b=qw(0 0 0 0 0 0 0 0); my $d=$a[0]; my $e=$b[0]; my $f=($d)^($e); print " 1 = $d , $e , $f\n"; $d=1; $e=0;