Hans Ginzel wrote:
Hello!
Hello,
Is there a shorter way to write $a = ! $a, please?
Something analogous to ++ and -- operators like $a !! or !! $a would negate
the variable $a and return its previous or new value respectively.
You can do that if you use a reference to a scalar like this:
On 09/10/13 20:01, John W. Krahn wrote:
xor-equals IS assignment and has the same precedence as assignment:
Thanks!
David
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Hello!
Is there a shorter way to write $a = ! $a, please?
Something analogous to ++ and -- operators like $a !! or !! $a would
negate
the variable $a and return its previous or new value respectively.
Best regards
HG
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For additional
Hans Ginzel wrote:
Hello!
Hello,
Is there a shorter way to write $a = ! $a, please?
No.
John
--
Any intelligent fool can make things bigger and
more complex... It takes a touch of genius -
and a lot of courage to move in the opposite
direction. -- Albert Einstein
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To
On 09/09/2013 11:00, Hans Ginzel wrote:
Is there a shorter way to write $a = ! $a, please?
perl -le '
my @a = (undef, @ARGV);
for $a (@a) {
my @r; push @r, $a:;
for (1..3) {
push @r, $a^=1; # --
}
print @r;
}
' 0 1 2 3 -1
: 1 0 1
0: 1 0 1
1: 0 1 0
2: 3 2 3
3: 2 3
On Mon, 09 Sep 2013 11:00:31 +0200
Hans Ginzel h...@matfyz.cz wrote:
Is there a shorter way to write $a = ! $a, please?
Why?
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Shawn
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On Tue, Sep 10, 2013 at 08:29:00AM -0400, Shawn H Corey wrote:
On Mon, 09 Sep 2013 11:00:31 +0200
Hans Ginzel h...@matfyz.cz wrote:
Is there a shorter way to write $a = ! $a, please?
Why?
Because it's the sort of thing one might expect Perl to provide. I know
that I have thought that
On 09/10/13 14:59, David Christensen wrote:
Assuming canonical boolean values, post-invert semantics (save the new
value into another variable) ...
Pre-invert semantics (save the old value into another variable) ...
Oops -- it looks like I got my pre- and post- backwards...
And, dropping the
September 10, 2013 06:15 Hans Ginzel wrote:
Is there a shorter way to write $a = ! $a, please?
Something analogous to ++ and -- operators like $a !! or !! $a would
negate the variable $a and return its previous or new value
respectively.
I don't believe Perl has boolean pre-invert or
On Tue, 10 Sep 2013 17:04:07 -0700
David Christensen dpchr...@holgerdanske.com wrote:
scalar ($v ^= 1, !$v)
( ! ( $v ^= 1 ))
or
do { $v = ! $v; !$v }
TIM TOW TDI ;)
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Don't stop where the ink does.
Shawn
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For
beginners:
Here's a second try at using bitwise xor-equals to implement boolean
pre- and post-invert operations for variables containing canonical
boolean values (undef, empty string, zero, and one).
The pre-invert semantics case (invert, then use) uses the bitwise
xor-equals operator and
On Mon, Sep 9, 2013 at 6:00 AM, Hans Ginzel h...@matfyz.cz wrote:
Hello!
Is there a shorter way to write $a = ! $a, please?
Something analogous to ++ and -- operators like $a !! or !! $a would negate
the variable $a and return its previous or new value respectively.
Best regards
Not
On Mon, Sep 9, 2013 at 5:00 AM, Hans Ginzel h...@matfyz.cz wrote:
Hello!
Is there a shorter way to write $a = ! $a, please?
Something analogous to ++ and -- operators like $a !! or !! $a would negate
the variable $a and return its previous or new value respectively.
It sounds like what
David Christensen wrote:
September 10, 2013 06:15 Hans Ginzel wrote:
Is there a shorter way to write $a = ! $a, please?
Something analogous to ++ and -- operators like $a !! or !! $a would
negate the variable $a and return its previous or new value
respectively.
I don't believe Perl has
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