On Sat, Aug 13, 2022 at 06:51:04AM +0700, Budi wrote:
> It doesn't work means no use on set -x, no value is shown
set -x shows the command being executed, with arguments expanded.
unicorn:~$ cat foo
#!/bin/bash
set -x
a=5
b=7
c=$((a * b))
echo "$c"
unicorn:~$ ./foo
+ a=5
+ b=7
+ c=35
+ echo 35
On Fri, Aug 12, 2022, at 7:40 PM, Dennis Williamson wrote:
> It works for me. What are you expecting?
>
> It would help if you show what you're doing, the result you're getting and
> what you expect instead.
I'm guessing that instead of, for example
% bash -xc 'a="(x=1)" b="2*3";
On Fri, Aug 12, 2022 at 6:51 PM Budi wrote:
> It doesn't work means no use on set -x, no value is shown
>
> On 8/13/22, Dennis Williamson wrote:
> > On Fri, Aug 12, 2022, 6:28 PM Budi wrote:
> >
> >> How come math/arithmetic ((i=k+l)) cannot make use of set -x
> >>
> >> Please help..
> >> (so
It doesn't work means no use on set -x, no value is shown
On 8/13/22, Dennis Williamson wrote:
> On Fri, Aug 12, 2022, 6:28 PM Budi wrote:
>
>> How come math/arithmetic ((i=k+l)) cannot make use of set -x
>>
>> Please help..
>> (so annoying).
>>
>
>
> It works for me. What are you expecting?
>
On Fri, Aug 12, 2022, 6:28 PM Budi wrote:
> How come math/arithmetic ((i=k+l)) cannot make use of set -x
>
> Please help..
> (so annoying).
>
It works for me. What are you expecting?
It would help if you show what you're doing, the result you're getting and
what you expect instead.
"It
How come math/arithmetic ((i=k+l)) cannot make use of set -x
Please help..
(so annoying).
On 8/11/22 5:56 PM, Koichi Murase wrote:
I agree with option 4. Thank you for all your explanations.
--
Can we also change the behavior of TERM in a similar way with option
4?
I'll look at that for the next version.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
