On 12/12/19 9:57 PM, L A Walsh wrote:
The backquote is in [6], and the backslash disappears, you just get the
pair of quotes in [2] because that's how printf %q outputs an empty string.
-
I'm sorry, but you are mistaken.
The characters from 'Z' (0x5A) through 'z' (0x61) are:
On 12/12/19 9:57 PM, L A Walsh wrote:
>
>
> On 2019/12/12 13:01, Ilkka Virta wrote:
>> On 12.12. 21:43, L A Walsh wrote:
>>
>>> On 2019/12/06 14:14, Chet Ramey wrote:
>>>
>>> Seems very hard to print out that backquote though. Closest I got
>>> was bash converting it to "''":
>>>
>>
>>
On 2019/12/12 13:01, Ilkka Virta wrote:
On 12.12. 21:43, L A Walsh wrote:
On 2019/12/06 14:14, Chet Ramey wrote:
Seems very hard to print out that backquote though. Closest I got
was bash converting it to "''":
The backquote is in [6], and the backslash disappears, you just get
On 12.12. 21:43, L A Walsh wrote:
On 2019/12/06 14:14, Chet Ramey wrote:
Seems very hard to print out that backquote though. Closest I got
was bash converting it to "''":
The backquote is in [6], and the backslash disappears, you just get the
pair of quotes in [2] because that's how printf
On Thu, Dec 12, 2019 at 11:43:58AM -0800, L A Walsh wrote:
> > read -r -a a< <(printf "%q " {Z..a})
> > my -p a
> declare -a a=([0]="Z" [1]="\\[" [2]="''" [3]="\\]" [4]="\\^" [5]="_"
> [6]="\\\`" [7]="a")
Nice try. I guess the takeaway from this thread is: "You cannot mix
capital and lowercase
On 2019/12/06 14:14, Chet Ramey wrote:
Seems very hard to print out that backquote though. Closest I got
was bash converting it to "''":
read -r -a a< <(printf "%q " {Z..a})
my -p a
declare -a a=([0]="Z" [1]="\\[" [2]="''" [3]="\\]" [4]="\\^" [5]="_"
[6]="\\\`" [7]="a")
#2 is where
