Re: Quoting and string comparison

Stupid me, everything makes sense now. Thanks for explaining and sorry for the trouble! 2018-02-08 19:56 GMT+01:00 Ilkka Virta : > On 8.2. 15:05, Jaan Vajakas wrote: > >> Hi! >> >> I noticed a weird behavior. Is it a bug? >> >> Namely, why does >> >> echo "$(for f in a b c; do

Re: Quoting and string comparison

On 8.2. 15:05, Jaan Vajakas wrote: Hi! I noticed a weird behavior. Is it a bug? Namely, why does echo "$(for f in a b c; do if [[ \"$f\" > b ]]; then echo "$f > b"; else echo "$f <= b"; fi; done)" If I'm not mistaken, what you're doing is essentially this: $ for f in '"a"' '"b"' '"c"'; do

Re: Quoting and string comparison

On Thu, Feb 8, 2018 at 4:27 PM, Jaan Vajakas wrote: > So should Bash report a syntax error? > You do not have a syntax error, the rules for quoting inside $( ) are the same as outside, whether you use outside quotes "$( )" or not So in your case you are escaping the

Re: Quoting and string comparison

So should Bash report a syntax error? 2018-02-08 15:24 GMT+01:00 Clark Wang : > On Thu, Feb 8, 2018 at 9:05 PM, Jaan Vajakas > wrote: > >> Hi! >> >> I noticed a weird behavior. Is it a bug? >> >> Namely, why does >> >> echo "$(for f in a b c; do if [[

Re: Quoting and string comparison

On Thu, Feb 8, 2018 at 9:05 PM, Jaan Vajakas wrote: > Hi! > > I noticed a weird behavior. Is it a bug? > > Namely, why does > > echo "$(for f in a b c; do if [[ \"$f\" > b ]]; then echo "$f > b"; else > echo "$f <= b"; fi; done)" > Should be: echo "$(for f in a b c;

Quoting and string comparison

Hi! I noticed a weird behavior. Is it a bug? Namely, why does echo "$(for f in a b c; do if [[ \"$f\" > b ]]; then echo "$f > b"; else echo "$f <= b"; fi; done)" output a <= b b > b c > b ? I would have expected the same output as one of echo "$(for f in a b c; do if [[ "$f" > b ]]; then