Tatavarty Kalyan schrieb am 08.09.2006 um 11:44:47 (+0800):
It is because the string
a{b,c}
is outside of the quotes. So the brace expansion comes first and
duplicates
the arguments to the echo call.
Yes, as you said the brace expansion is outside the double quotes so
shouldn't it
Chris F.A. Johnson wrote:
Quote them, and they do expand:
$ foo() { echo ${1:-a{b,c}} ; }
$ foo
ab ac
Brace expansion is essentially separate from the rest of the expansions:
in fact, it's designed to be part of a separate library if desired. As
such, it doesn't implement all of the
Tatavarty Kalyan schrieb am 07.09.2006 um 14:20:43 (+0800):
On 9/6/06, Chris F.A. Johnson [EMAIL PROTECTED] wrote:
On 2006-09-06, Andreas Schwab wrote:
[EMAIL PROTECTED] (Paul Jarc) writes:
Mike Frysinger [EMAIL PROTECTED] wrote:
this little bit of code doesnt work right:
foo() {
On 9/8/06, Alexander Elgert [EMAIL PROTECTED] wrote:
Tatavarty Kalyan schrieb am 07.09.2006 um 14:20:43 (+0800):
On 9/6/06, Chris F.A. Johnson [EMAIL PROTECTED] wrote:
On 2006-09-06, Andreas Schwab wrote:
[EMAIL PROTECTED] (Paul Jarc) writes:
Mike Frysinger [EMAIL PROTECTED] wrote:
[EMAIL PROTECTED] (Paul Jarc) writes:
Mike Frysinger [EMAIL PROTECTED] wrote:
this little bit of code doesnt work right:
foo() { echo ${1:-a{b,c}} ; }
Brace expansion happens before parameter expansion (man bash,
EXPANSION).
Brace expansion doesn't come into play here, because the braces
On Wednesday 06 September 2006 05:04, Andreas Schwab wrote:
[EMAIL PROTECTED] (Paul Jarc) writes:
Mike Frysinger [EMAIL PROTECTED] wrote:
this little bit of code doesnt work right:
foo() { echo ${1:-a{b,c}} ; }
Brace expansion happens before parameter expansion (man bash,
EXPANSION).
On 2006-09-06, Andreas Schwab wrote:
[EMAIL PROTECTED] (Paul Jarc) writes:
Mike Frysinger [EMAIL PROTECTED] wrote:
this little bit of code doesnt work right:
foo() { echo ${1:-a{b,c}} ; }
The first '}' is interpreted as the end of the parameter expansion.
Brace expansion happens before
this little bit of code doesnt work right:
foo() { echo ${1:-a{b,c}} ; }
$ foo
a{b,c}
$ foo 1
a}
tested with bash-3.1.17
-mike
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Mike Frysinger [EMAIL PROTECTED] wrote:
this little bit of code doesnt work right:
foo() { echo ${1:-a{b,c}} ; }
Brace expansion happens before parameter expansion (man bash,
EXPANSION). So the first } ends the parameter expression, and the
second } isn't special. The result of parameter
