Configuration Information [Automatically generated, do not change]:
Machine: i586
OS: linux-gnu
Compiler:
gcc -I/usr/src/packages/BUILD/bash-3.2
-L/usr/src/packages/BUILD/bash-3.2/../readline-5.2
Compilation
CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i586' -DCONF_OSTYPE='linux-gnu'
Problem:
typeset, when used in a function should always mark the variable as local.
When bash is in ksh mode, it fails to do this.
Previous versions did not have this problem, e.g.
GNU bash, version 3.00.15(1)-release (i386-redhat-linux-gnu)
Recent versions of ksh seem to be exhibiting the same
Hi all,
I am trying to integrate bash with a Java application, i.e. bash is started
as a process and the Java application sends data to the process's stdin and
reads data from stdout/stderr. This works reasonably well, but I am having a
problem with completion, e.g. the user pressing TAB to
raner [EMAIL PROTECTED] wrote:
The completion seems to work, but I do not receive the completed filename
from the shell's stdout.
It's written to stderr, not stdout.
paul
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Bug-bash@gnu.org
Paul Jarc wrote:
raner [EMAIL PROTECTED] wrote:
The completion seems to work, but I do not receive the completed filename
from the shell's stdout.
It's written to stderr, not stdout.
Thanks for your reply, Paul. I'm reading stderr, too, and it doesn't show up
there either. I am
Clay Harris wrote:
Problem:
typeset, when used in a function should always mark the variable as local.
When bash is in ksh mode, it fails to do this.
I can't reproduce this with bash-3.0, bash-3.1, or bash-3.2 (all patched)
on MacOS X and FC6. Bash does not have a `ksh mode'.
Chet
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