On 5/4/15 9:03 PM, James Caccese wrote:
I posted the following question to stackoverflow
(http://stackoverflow.com/questions/30042157/why-cant-i-use-declare-r-inside-a-function-fo-mark-a-variable-readonly-while)
and was advised the behavior I was witnessing was a bug in bash.
It's not a bug;
I posted the following question to stackoverflow
(http://stackoverflow.com/questions/30042157/why-cant-i-use-declare-r-inside-a-function-fo-mark-a-variable-readonly-while)
and was advised the behavior I was witnessing was a bug in bash.
With GNU bash, version 4.3.11(1)-release
On 5/1/15 2:26 PM, Dreamcat4 wrote:
Hello.
If you unset a function, then a variable argument (argv) specified after
that function will not be unset.
Thanks for the report. Yes, once you unset a function, it's as if you
supplied the `-f' option.
This came in as the result of a fix for the
On Tue, May 5, 2015 at 2:54 PM, Chet Ramey chet.ra...@case.edu wrote:
On 4/30/15 9:27 AM, Chet Ramey wrote:
On 4/29/15 10:31 PM, Rocky Bernstein wrote:
$ ./bash --debugger -i /tmp/foo.sh
hi
$ ./bash --debugger /tmp/foo.sh
bash debugger, bashdb, release 4.3-0.91
Copyright
On 4/30/15 9:27 AM, Chet Ramey wrote:
On 4/29/15 10:31 PM, Rocky Bernstein wrote:
$ ./bash --debugger -i /tmp/foo.sh
hi
$ ./bash --debugger /tmp/foo.sh
bash debugger, bashdb, release 4.3-0.91
Copyright 2002, 2003, 2004, 2006-2012, 2014 Rocky Bernstein
This is free software, covered
