On 8/28/2020 1:00 AM, Gabriel Winkler wrot > # Causes error > test=0 > ((test++)) > echo $? > 1 > echo $test > 1 > "((...))" is the "test form" for an integer expression. That means it will return true if the value of the interior, "...", of "((...))" is non-zero and return false if ((... == 0)). Remember "$?==0" == true and "$?!=0" == false,
so if "..." is an expression then for: ... is 0 is non-0 then ((...)) is false is true $? is 1 is 0 deciding that ((non-zero)) = true was consistent with most programmers' expectations from other languages that 0 was false and non-zero was true (which is opposite of the final value of "$?").
