Re: if, -n string
Jan Schampera wrote: coubeatczech wrote: c...@notas:~$ if [ -z $variable ]; then echo true; fi true c...@notas:~$ Can anybody explain to me this behaviour? I would expect not any output in the last command...? The variable is set to zero and there is the condition is still true...? http://bash-hackers.org/wiki/doku.php/commands/classictest#number_of_arguments_rules You'd need some quoting. Jan aka TheBonsai Thanks, I'm understanding it now. -- View this message in context: http://www.nabble.com/if%2C--n-%3Cstring%3E-tp21764081p21774953.html Sent from the Gnu - Bash mailing list archive at Nabble.com.
Re: if, -n string
coubeatczech wrote: c...@notas:~$ if [ -z $variable ]; then echo true; fi true c...@notas:~$ Can anybody explain to me this behaviour? I would expect not any output in the last command...? The variable is set to zero and there is the condition is still true...? http://bash-hackers.org/wiki/doku.php/commands/classictest#number_of_arguments_rules You'd need some quoting. Jan aka TheBonsai
Re: if, -n string
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 According to coubeatczech on 1/31/2009 7:24 AM: c...@notas:~$ variable= c...@notas:~$ if [ -n $variable ]; then echo true; fi true This is equivalent to 'if [ -n ]; then echo true; fi'; in other words, because there is only one argument (-n), and it is not empty, it is true. You meant to use quotes, to guarantee that there are two arguments, as in: if [ -n $variable ]; then echo true; fi - -- Don't work too hard, make some time for fun as well! Eric Blake e...@byu.net -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.9 (Cygwin) Comment: Public key at home.comcast.net/~ericblake/eblake.gpg Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org iEYEARECAAYFAkmFCUMACgkQ84KuGfSFAYCU6ACgj4hHK1Cxuk/gwI6QPo6xU0Ng 6KIAoMx3sk6bvV8YHGssez2s2vT7s45e =VLoa -END PGP SIGNATURE-
