Configuration Information [Automatically generated, do not change]:
Machine: i486
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i486'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu'
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash'
-DSHELL -DHAVE_CONFIG_H -I. -I../bash -I../bash/include
-I../bash/lib -g -O2 -Wall
uname output: Linux myhost 2.6.26-2-686 #1 SMP Wed Aug 19 06:06:52 UTC
2009 i686 GNU/Linux
Machine Type: i486-pc-linux-gnu
Bash Version: 3.2
Patch Level: 39
Release Status: release
When completing command substitution:
$ a $(b c<TAB>
the command completion for `a' is invoked, whereas I'd expect the
command completion for `b' to be invoked.
I would expect the same behaviour as with process substitution, which
invokes the completion for `b':
$ a <(b c<TAB>
Steps to reproduce:
1. Create functions `_a' and `_b' to complete `a' and `b':
_a() { echo a; }
_b() { echo b; }
complete -F _a a
complete -F _b b
2. Complete `b' within command substition:
$ a $(b c<TAB> # This returns `a', where I'd expected `b'?
3. Complete `b' within process substitution:
$ a <(b c<TAB> # This returns `b' all right.
Regards,
Freddy Vulto
http://fvue.nl
