On Wed, Nov 16, 2022 at 02:05:56PM -0500, Chet Ramey wrote:
> It doesn't matter. `local -' is the only way to save and restore the
> options; `declare -p -' and `typeset -p -' should have no special meaning.
The `declare -p'/`typeset -p' commands and the `local -p' command are
different commands.
On 11/16/22 12:12 PM, Emanuele Torre wrote:
The 31f4d468b60eb27d768ef56d0a8b4982346465d9 commit on the devel branch,
addressed this issue, but only partially:
bash-5.1$ ./bash --version |& head -n 1
GNU bash, version 5.2.9(6)-maint (x86_64-pc-linux-gnu)
bash-5.1$ ./bash -c 'a ()
The 31f4d468b60eb27d768ef56d0a8b4982346465d9 commit on the devel branch,
addressed this issue, but only partially:
bash-5.1$ ./bash --version |& head -n 1
GNU bash, version 5.2.9(6)-maint (x86_64-pc-linux-gnu)
bash-5.1$ ./bash -c 'a () { local -; local -p; declare -p -; typeset -p -;
On Mon, Oct 31, 2022, 18:31 Greg Wooledge wrote:
> On Mon, Oct 31, 2022 at 06:12:14PM +0100, Alex fxmbsw7 Ratchev wrote:
> > hi , sorry.. whats the purpose of local -
> > informational question
>
> a. Since there is no `declare -' equivalent of `local -', make sure to use
>`local -' in the
On Mon, Oct 31, 2022 at 06:12:14PM +0100, Alex fxmbsw7 Ratchev wrote:
> hi , sorry.. whats the purpose of local -
> informational question
a. Since there is no `declare -' equivalent of `local -', make sure to use
`local -' in the output of `local -p'.
-
s. The `local' builtin takes a
hi , sorry.. whats the purpose of local -
informational question
On Mon, Oct 31, 2022, 17:45 Emanuele Torre wrote:
> Since bash 5.2, local/typeset/declare -p without argument no longer
> outputs "declare -- -" when local - is used.
>
> But local/typeset/declare -p - still outputs "declare
Since bash 5.2, local/typeset/declare -p without argument no longer
outputs "declare -- -" when local - is used.
But local/typeset/declare -p - still outputs "declare -- -" instead of
"local -".
bash-5.1$ a () { local -; local -p; declare -p -; typeset -p -;
local -p - ;}
bash-5.1$
