On Fri, 29 Feb 2008, Bob Proulx wrote:
Jan Engelhardt wrote:
I wanted to get the number of seconds since the start of the day.
echo $[`date +%s` % 86400];
unfortunately does not do the right thing ÿÿ it would show
82800 instead of 0 when it is (local) midnight.
I can't think of
Philip Rowlands [EMAIL PROTECTED] writes:
I might be misunderstanding the problem, but it seems easy enough to do
this calling date only once:
$ date +%T | awk -F: '{ print $1 * 3600 + $2 * 60 + $3 }'
67652
This will fail during the day after a DST transition.
Andreas.
--
Andreas Schwab,
Andreas Schwab wrote:
This will fail during the day after a DST transition.
Which points out a terrible bug in my suggestion of how to map the
range of 0-(N-1) to the range of 1-N!
Bob wrote this buggy code:
case $secondssincedaystart in (0) secondssincedaystart=86400 ;; esac
That will
On Feb 29 2008 15:26, Bob Proulx wrote:
echo $[`date +%s` % 86400];
Note that the $[expression] syntax is deprecated and is scheduled for
removal from a future version of the shell. Please convert to using
the now standard $((expression)) syntax.
echo $(( $(date +%s) % 86400 ));
Jan Engelhardt wrote:
$(()) is easily confusable with $(), I therefore ask $[] to be not removed,
more like the reverse actually.
I am not able to influence the decision. I am just reporting how it
is documented.
Bob
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Hi,
this is probably all correct behavior as it is right now (coreutils 6.9):
$ date +%s
120433
$ TZ=GMT date +%s
120433
$ TZ=PDT date +%s
120433
but is there actually a way to do
$ TZ=anything date +%s -d `date '+%Y-%m-%d
Jan Engelhardt wrote:
$ date +%s
120433
%s seconds since 1970-01-01 00:00:00 UTC
$ TZ=GMT date +%s
120433
$ TZ=PDT date +%s
120433
Right. I assume you were *very fast* typing in that data and that
seconds did not move on while you were
On Feb 29 2008 14:20, Bob Proulx wrote:
Right. I assume you were *very fast* typing in that data and that
seconds did not move on while you were doing it. :-) I get the point
though. That value is a timezone independent value.
but is there actually a way to do
$ TZ=anything date +%s
Jan Engelhardt [EMAIL PROTECTED] writes:
this is probably all correct behavior as it is right now (coreutils 6.9):
$ date +%s
120433
$ TZ=GMT date +%s
120433
$ TZ=PDT date +%s
120433
%s is defined as seconds since 1970-01-01 00:00:00 UTC
Jan Engelhardt wrote:
I wanted to get the number of seconds since the start of the day.
echo $[`date +%s` % 86400];
How about:
echo $[$(date +%s) - $(date -d '' +%s)]
Brian
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Jan Engelhardt wrote:
There is (my default zone is /etc/localtime -
/usr/share/zoneinfo/Europe/Berlin):
$ TZ=GMT date +%s -d `date '+%Y-%m-%d %H:%M:%S'`
1204325194
$ date +%s
1204321595
(now with not-so-fast typing! :)
:-)
I wanted to get the number of
Brian Dessent wrote:
Jan Engelhardt wrote:
I wanted to get the number of seconds since the start of the day.
echo $[`date +%s` % 86400];
How about:
echo $[$(date +%s) - $(date -d '' +%s)]
That works most of the time and if I were never to run this at
midnight I would do just
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